結果
| 問題 |
No.3141 Balancing with X=>O Flip
|
| コンテスト | |
| ユーザー |
HackberryA3
|
| 提出日時 | 2025-05-16 22:13:01 |
| 言語 | C++23 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 3 ms / 2,000 ms |
| コード長 | 3,448 bytes |
| コンパイル時間 | 2,658 ms |
| コンパイル使用メモリ | 281,496 KB |
| 実行使用メモリ | 7,844 KB |
| 最終ジャッジ日時 | 2025-05-17 03:14:36 |
| 合計ジャッジ時間 | 3,506 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 26 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ull = unsigned long long;
using vll = vector<ll>;
using vvll = vector<vll>;
using P = pair<int, int>;
using PP = pair<int, P>;
using PLL = pair<ll, ll>;
using PPLL = pair<ll, PLL>;
#define rep(i, n) for(ll i = 0; i < n; ++i)
#define rrep(i, n) for(ll i = n - 1; i >= 0; --i)
#define loop(i, a, b) for(ll i = a; i <= b; ++i)
#define all(v) v.begin(), v.end()
#define nC2(n) n * (n - 1) / 2
constexpr ll INF = 9009009009009009009LL;
constexpr int INF32 = 2002002002;
constexpr ll MOD = 998244353;
constexpr ll MOD107 = 1000000007;
// Linear Algebra ////////////////////////////////////////////////
const double Rad2Deg = 180.0 / M_PI;
const double Deg2Rad = M_PI / 180.0;
//////////////////////////////////////////////////////////////////
int dx[8] = {0, 1, 0, -1, 1, 1, -1, -1};
int dy[8] = {1, 0, -1, 0, 1, -1, 1, -1};
template <class T>
inline bool chmax(T &a, const T &b) {
if (a < b) {
a = b;
return true;
}
return false;
}
template <class T>
inline bool chmin(T &a, const T &b) {
if (a > b) {
a = b;
return true;
}
return false;
}
template <typename Container,
typename = std::enable_if_t<
!std::is_same_v<Container, std::string> &&
std::is_convertible_v<decltype(std::declval<Container>().begin()),
typename Container::iterator>>>
ostream &operator<<(ostream &os, const Container &container) {
auto it = container.begin();
auto end = container.end();
if (it != end) {
os << *it;
++it;
}
for (; it != end; ++it) {
os << " " << *it;
}
return os;
}
template <typename T>
ostream& operator<<(ostream& os, const vector<T>& v) {
for (size_t i = 0; i < v.size(); ++i) {
os << v[i];
if (i != v.size() - 1) os << " ";
}
return os;
}
template <typename T>
ostream& operator<<(ostream& os, const vector<vector<T>>& vv) {
for (size_t i = 0; i < vv.size(); ++i) {
os << vv[i];
if (i != vv.size() - 1) os << "\n";
}
return os;
}
template <typename T>
istream& operator>>(istream& is, vector<T>& v) {
assert(v.size() > 0);
for (size_t i = 0; i < v.size(); ++i) is >> v[i];
return is;
}
template <typename T>
istream& operator>>(istream& is, vector<vector<T>>& vv) {
assert(vv.size() > 0);
for (size_t i = 0; i < vv.size(); ++i) is >> vv[i];
return is;
}
struct phash {
template<class T1, class T2>
inline size_t operator()(const pair<T1, T2> & p) const {
auto h1 = hash<T1>()(p.first);
auto h2 = hash<T2>()(p.second);
size_t seed = h1 + h2;
h1 = ((h1 >> 16) ^ h1) * 0x45d9f3b;
h1 = ((h1 >> 16) ^ h1) * 0x45d9f3b;
h1 = (h1 >> 16) ^ h1;
seed ^= h1 + 0x9e3779b9 + (seed << 6) + (seed >> 2);
h2 = ((h2 >> 16) ^ h2) * 0x45d9f3b;
h2 = ((h2 >> 16) ^ h2) * 0x45d9f3b;
h2 = (h2 >> 16) ^ h2;
seed ^= h2 + 0x9e3779b9 + (seed << 6) + (seed >> 2);
return seed;
}
};
int solve() {
ll n; cin >> n;
string s; cin >> s;
stack<char> st;
rep(i, n) {
if (s[i] == '(') {
if (!st.empty() && st.top() == ')') {
st.pop();
}
else {
st.push(s[i]);
}
}
else {
if (!st.empty() && st.top() == '(') {
st.pop();
}
else {
st.push(s[i]);
}
}
}
cout << (st.empty() ? "Yes" : "No") << endl;
return 0;
}
int main() {
cin.tie(nullptr);
ios::sync_with_stdio(false);
return solve();
}
HackberryA3