結果
| 問題 | No.3159 Just Answer 10 Integers! | 
| コンテスト | |
| ユーザー | 👑 | 
| 提出日時 | 2025-05-23 19:36:24 | 
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) | 
| 結果 | 
                                WA
                                 
                             | 
| 実行時間 | - | 
| コード長 | 2,318 bytes | 
| コンパイル時間 | 3,640 ms | 
| コンパイル使用メモリ | 251,356 KB | 
| 実行使用メモリ | 7,848 KB | 
| 最終ジャッジ日時 | 2025-05-23 19:36:38 | 
| 合計ジャッジ時間 | 5,226 ms | 
| ジャッジサーバーID (参考情報) | judge4 / judge3 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | WA * 1 | 
| other | WA * 9 | 
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:26:51: warning: integer overflow in expression of type ‘int’ results in ‘-2120241362’ [-Woverflow]
   26 |         const long long P = 2*3*5*7*11*13*17*19*23*29;
      |                             ~~~~~~~~~~~~~~~~~~~~~~^~~
            
            ソースコード
#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef pair<int, int> P;
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}
int main(){
	const long long P = 2*3*5*7*11*13*17*19*23*29;
	vector<long long> primes = {2,3,5,7,11,13,17,19,23,29};
	int n;
	cin >> n;
	rep(i, n){
		cout << P / primes[i] << ' ';
	}
	return 0;
}
            
            
            
        