結果
問題 |
No.2456 Stamp Art
|
ユーザー |
![]() |
提出日時 | 2025-06-12 12:52:50 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 2,813 ms / 5,000 ms |
コード長 | 1,519 bytes |
コンパイル時間 | 535 ms |
コンパイル使用メモリ | 82,788 KB |
実行使用メモリ | 324,880 KB |
最終ジャッジ日時 | 2025-06-12 12:54:35 |
合計ジャッジ時間 | 33,615 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 23 |
ソースコード
H, W = map(int, input().split()) grid = [input().strip() for _ in range(H)] prefix = [[0] * (W + 1) for _ in range(H + 1)] for i in range(1, H + 1): row_sum = 0 for j in range(1, W + 1): row_sum += 1 if grid[i-1][j-1] == '#' else 0 prefix[i][j] = prefix[i-1][j] + row_sum def is_possible(k): if k == 0: return False diff = [[0] * (W + 2) for _ in range(H + 2)] max_a = H - k + 1 max_b = W - k + 1 for a in range(1, max_a + 1): a_end = a + k - 1 for b in range(1, max_b + 1): b_end = b + k - 1 total = prefix[a_end][b_end] - prefix[a-1][b_end] - prefix[a_end][b-1] + prefix[a-1][b-1] if total == k * k: diff[a][b] += 1 diff[a][b_end + 1] -= 1 diff[a_end + 1][b] -= 1 diff[a_end + 1][b_end + 1] += 1 # Compute row-wise prefix sums for i in range(1, H + 1): for j in range(1, W + 1): diff[i][j] += diff[i][j-1] # Compute column-wise prefix sums for j in range(1, W + 1): for i in range(1, H + 1): diff[i][j] += diff[i-1][j] # Check all black cells for i in range(H): for j in range(W): if grid[i][j] == '#' and diff[i+1][j+1] == 0: return False return True low = 1 high = min(H, W) ans = 0 while low <= high: mid = (low + high) // 2 if is_possible(mid): ans = mid low = mid + 1 else: high = mid - 1 print(ans)