結果
問題 | No.337 P versus NP |
ユーザー | はむこ |
提出日時 | 2016-08-06 02:45:03 |
言語 | C++11 (gcc 11.4.0) |
結果 |
AC
|
実行時間 | 2 ms / 2,000 ms |
コード長 | 3,075 bytes |
コンパイル時間 | 2,532 ms |
コンパイル使用メモリ | 160,504 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-11-07 02:32:22 |
合計ジャッジ時間 | 2,598 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,248 KB |
testcase_02 | AC | 2 ms
5,248 KB |
testcase_03 | AC | 2 ms
5,248 KB |
testcase_04 | AC | 2 ms
5,248 KB |
testcase_05 | AC | 2 ms
5,248 KB |
testcase_06 | AC | 2 ms
5,248 KB |
testcase_07 | AC | 1 ms
5,248 KB |
testcase_08 | AC | 1 ms
5,248 KB |
testcase_09 | AC | 2 ms
5,248 KB |
testcase_10 | AC | 2 ms
5,248 KB |
testcase_11 | AC | 2 ms
5,248 KB |
testcase_12 | AC | 1 ms
5,248 KB |
testcase_13 | AC | 2 ms
5,248 KB |
testcase_14 | AC | 2 ms
5,248 KB |
testcase_15 | AC | 2 ms
5,248 KB |
testcase_16 | AC | 2 ms
5,248 KB |
testcase_17 | AC | 1 ms
5,248 KB |
testcase_18 | AC | 2 ms
5,248 KB |
testcase_19 | AC | 2 ms
5,248 KB |
testcase_20 | AC | 2 ms
5,248 KB |
testcase_21 | AC | 1 ms
5,248 KB |
testcase_22 | AC | 2 ms
5,248 KB |
ソースコード
#include <bits/stdc++.h> using namespace std; #ifdef _WIN32 #define scanfll(x) scanf("%I64d", x) #define printfll(x) printf("%I64d", x) #else #define scanfll(x) scanf("%lld", x) #define printfll(x) printf("%lld", x) #endif #define rep(i,n) for(long long i = 0; i < (long long)(n); i++) #define repi(i,a,b) for(long long i = (long long)(a); i < (long long)(b); i++) #define pb push_back #define all(x) (x).begin(), (x).end() #define fi first #define se second #define mt make_tuple #define mp make_pair template<class T1, class T2> bool chmin(T1 &a, T2 b) { return b < a && (a = b, true); } template<class T1, class T2> bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); } using ll = long long; using ld = long double; using vll = vector<ll>; using vvll = vector<vll>; using vld = vector<ld>; using vi = vector<int>; using vvi = vector<vi>; vll conv(vi& v) { vll r(v.size()); rep(i, v.size()) r[i] = v[i]; return r; } using P = pair<ll, ll>; template <typename T, typename U> ostream &operator<<(ostream &o, const pair<T, U> &v) { o << "(" << v.first << ", " << v.second << ")"; return o; } template<size_t...> struct seq{}; template<size_t N, size_t... Is> struct gen_seq : gen_seq<N-1, N-1, Is...>{}; template<size_t... Is> struct gen_seq<0, Is...> : seq<Is...>{}; template<class Ch, class Tr, class Tuple, size_t... Is> void print_tuple(basic_ostream<Ch,Tr>& os, Tuple const& t, seq<Is...>){ using s = int[]; (void)s{0, (void(os << (Is == 0? "" : ", ") << get<Is>(t)), 0)...}; } template<class Ch, class Tr, class... Args> auto operator<<(basic_ostream<Ch, Tr>& os, tuple<Args...> const& t) -> basic_ostream<Ch, Tr>& { os << "("; print_tuple(os, t, gen_seq<sizeof...(Args)>()); return os << ")"; } ostream &operator<<(ostream &o, const vvll &v) { rep(i, v.size()) { rep(j, v[i].size()) o << v[i][j] << " "; cout << endl; } return o; } template <typename T> ostream &operator<<(ostream &o, const vector<T> &v) { o << '['; rep(i, v.size()) o << v[i] << (i != v.size()-1 ? ", " : ""); o << "]"; return o; } template <typename T> ostream &operator<<(ostream &o, const set<T> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it << (next(it) != m.end() ? ", " : ""); o << "]"; return o; } template <typename T, typename U> ostream &operator<<(ostream &o, const map<T, U> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it << (next(it) != m.end() ? ", " : ""); o << "]"; return o; } template <typename T, typename U> ostream &operator<<(ostream &o, const unordered_map<T, U> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it; o << "]"; return o; } void printbits(ll mask, ll n) { rep(i, n) { cout << !!(mask & (1ll << i)); } cout << endl; } #define ldout fixed << setprecision(40) static const double EPS = 1e-14; static const long long INF = 1e18; static const long long mo = 1e9+7; int main(void) { cin.tie(0); ios::sync_with_stdio(false); ll n, p; cin >> n >> p; if (p == n * p) { cout << "=" << endl; } else { cout << "!=" << endl; } return 0; }