結果
問題 |
No.2036 Max Middle
|
ユーザー |
![]() |
提出日時 | 2025-06-12 13:57:32 |
言語 | PyPy3 (7.3.15) |
結果 |
TLE
|
実行時間 | - |
コード長 | 1,184 bytes |
コンパイル時間 | 145 ms |
コンパイル使用メモリ | 82,244 KB |
実行使用メモリ | 279,284 KB |
最終ジャッジ日時 | 2025-06-12 13:57:48 |
合計ジャッジ時間 | 4,192 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 4 TLE * 1 -- * 12 |
ソースコード
import sys from collections import deque def main(): n = int(sys.stdin.readline()) A = list(map(int, sys.stdin.readline().split())) if n < 3: print(0) return is_peak = [False] * n q = deque() for i in range(1, n-1): if A[i-1] < A[i] and A[i] > A[i+1]: is_peak[i] = True q.append(i) count = 0 while q: i = q.popleft() if not is_peak[i]: continue # Perform the operation min_val = min(A[i-1], A[i+1]) A[i] = min_val - 1 count += 1 is_peak[i] = False # Current position is no longer a peak # Check surrounding positions for new peaks for j in [i-1, i, i+1]: if j < 1 or j >= n-1: continue # Check if j is a peak now if A[j-1] < A[j] and A[j] > A[j+1]: if not is_peak[j]: is_peak[j] = True q.append(j) else: if is_peak[j]: is_peak[j] = False # In case it was marked as peak before print(count) if __name__ == "__main__": main()