結果
問題 |
No.2332 Make a Sequence
|
ユーザー |
![]() |
提出日時 | 2025-06-12 14:02:42 |
言語 | PyPy3 (7.3.15) |
結果 |
TLE
|
実行時間 | - |
コード長 | 1,814 bytes |
コンパイル時間 | 447 ms |
コンパイル使用メモリ | 82,160 KB |
実行使用メモリ | 141,724 KB |
最終ジャッジ日時 | 2025-06-12 14:03:41 |
合計ジャッジ時間 | 18,921 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 45 TLE * 1 -- * 15 |
ソースコード
import sys import heapq def main(): sys.setrecursionlimit(1 << 25) N, M = map(int, sys.stdin.readline().split()) A = list(map(int, sys.stdin.readline().split())) B = list(map(int, sys.stdin.readline().split())) C = list(map(int, sys.stdin.readline().split())) if M == 0: print(0) return # Compute Z-array for A + '#' + B S = A + [0] + B # Using 0 as a separator (assuming 0 is not in A or B) n = len(S) Z = [0] * n l, r = 0, 0 for i in range(1, n): if i <= r: Z[i] = min(r - i + 1, Z[i - l]) while i + Z[i] < n and S[Z[i]] == S[i + Z[i]]: Z[i] += 1 if i + Z[i] - 1 > r: l, r = i, i + Z[i] - 1 # Precompute k_i for each i in B k_list = [0] * M for i in range(M): pos_in_S = N + 1 + i max_k = Z[pos_in_S] max_k = min(max_k, N) max_k = min(max_k, M - i) k_list[i] = max_k # Check if B can be formed # We'll handle this via the DP INF = float('inf') dp = [INF] * (M + 1) dp[0] = 0 heap = [] heapq.heappush(heap, (0, 0)) while heap: current_cost, i = heapq.heappop(heap) if i == M: print(current_cost) return if current_cost > dp[i]: continue max_k = k_list[i] if i < M else 0 max_k = min(max_k, M - i) if max_k == 0: continue for k in range(1, max_k + 1): j = i + k if j > M: continue new_cost = current_cost + k * C[i] if new_cost < dp[j]: dp[j] = new_cost heapq.heappush(heap, (new_cost, j)) print(-1 if dp[M] == INF else dp[M]) if __name__ == "__main__": main()