結果
問題 |
No.219 巨大数の概算
|
ユーザー |
![]() |
提出日時 | 2025-06-12 14:08:10 |
言語 | PyPy3 (7.3.15) |
結果 |
TLE
|
実行時間 | - |
コード長 | 2,006 bytes |
コンパイル時間 | 179 ms |
コンパイル使用メモリ | 82,304 KB |
実行使用メモリ | 103,808 KB |
最終ジャッジ日時 | 2025-06-12 14:08:23 |
合計ジャッジ時間 | 6,174 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | -- * 1 |
other | TLE * 1 -- * 50 |
ソースコード
from decimal import Decimal, getcontext, ROUND_FLOOR getcontext().prec = 35 # Sufficient precision for all cases # Precompute the log10 values for X.Y where X ranges from 1-9 and Y from 0-9 log_table = [] for X in range(1, 10): row = [] for Y in range(0, 10): value = Decimal(X) + Decimal(Y) / Decimal(10) log_val = value.log10() row.append(log_val) # Append log10(X+1) for the upper bound of Y=10 row.append(Decimal(X + 1).log10()) log_table.append(row) def find_X(f): # Binary search to find X such that log10(X) <= f < log10(X+1) left, right = 1, 9 while left <= right: mid = (left + right) // 2 lower = Decimal(mid).log10() upper = Decimal(mid + 1).log10() if lower <= f < upper: return mid if f < lower: right = mid - 1 else: left = mid + 1 return None def find_Y(X, f): row = log_table[X - 1] left, right = 0, 9 while left <= right: mid = (left + right) // 2 lower = row[mid] upper = row[mid + 1] if lower <= f < upper: return mid if f < lower: right = mid - 1 else: left = mid + 1 return None def main(): import sys input = sys.stdin.read().split() idx = 0 N = int(input[idx]) idx += 1 results = [] for _ in range(N): A = int(input[idx]) B = int(input[idx + 1]) idx += 2 log_A = Decimal(A).log10() log_val = B * log_A # Calculate m and f accurately m = int(log_val.to_integral(rounding=ROUND_FLOOR)) f = log_val - m X = find_X(f) if X is None: X = 1 # Fallback, though theoretically impossible Y = find_Y(X, f) if Y is None: Y = 0 # Fallback results.append(f"{X} {Y} {m}") print('\n'.join(results)) if __name__ == "__main__": main()