結果
| 問題 |
No.2026 Yet Another Knapsack Problem
|
| コンテスト | |
| ユーザー |
gew1fw
|
| 提出日時 | 2025-06-12 15:34:26 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 2,142 bytes |
| コンパイル時間 | 197 ms |
| コンパイル使用メモリ | 82,668 KB |
| 実行使用メモリ | 109,396 KB |
| 最終ジャッジ日時 | 2025-06-12 15:36:00 |
| 合計ジャッジ時間 | 26,817 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 35 TLE * 1 -- * 6 |
ソースコード
import sys
import math
from itertools import accumulate
def main():
input = sys.stdin.read().split()
ptr = 0
N = int(input[ptr])
ptr +=1
items = []
v1 = 0
for i in range(1, N+1):
c_i = int(input[ptr])
v_i = int(input[ptr+1])
ptr +=2
if i ==1:
v1 = v_i
else:
items.append( (i, c_i, v_i) )
max_m = N//2 # since i >=2, each contributes at least 2 weight per item
INF = -10**18
dp = [ [INF]*(N+1) for _ in range(max_m+1) ]
dp[0][0] = 0
for (i, c_i, v_i) in items:
# Binary splitting
k = 1
remaining = c_i
while remaining >0:
take = min(k, remaining)
# Update DP in reverse order
for m in range(max_m, -1, -1):
for w in range(N, -1, -1):
if dp[m][w] == INF:
continue
new_m = m + take
new_w = w + i * take
if new_m > max_m or new_w > N:
continue
if dp[new_m][new_w] < dp[m][w] + v_i * take:
dp[new_m][new_w] = dp[m][w] + v_i * take
remaining -= take
k *=2
# Precompute max_val[m][w] = max(dp[m][0..w])
max_val = [ [INF]*(N+1) for _ in range(max_m+1) ]
for m in range(max_m+1):
current_max = INF
for w in range(N+1):
if dp[m][w] > current_max:
current_max = dp[m][w]
max_val[m][w] = current_max
for k in range(1, N+1):
best = INF
max_possible_m = min(k, max_m)
for m in range(0, max_possible_m+1):
remaining = k - m
allowed_w = N - remaining
if allowed_w <0:
continue
allowed_w = min(allowed_w, N)
current_val = max_val[m][allowed_w]
if current_val == INF:
continue
total = current_val + remaining * v1
if total > best:
best = total
print(best)
if __name__ == '__main__':
main()
gew1fw