結果
| 問題 |
No.291 黒い文字列
|
| ユーザー |
gew1fw
|
| 提出日時 | 2025-06-12 15:37:11 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 1,149 bytes |
| コンパイル時間 | 485 ms |
| コンパイル使用メモリ | 82,292 KB |
| 実行使用メモリ | 54,184 KB |
| 最終ジャッジ日時 | 2025-06-12 15:38:05 |
| 合計ジャッジ時間 | 2,370 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 21 WA * 5 |
ソースコード
def max_kuroi_subsequences(s):
target = "KUROI"
counts = {c: 0 for c in target}
for c in s:
if c in counts:
counts[c] += 1
M = s.count('?')
# Step 1: Compute maximum possible t based on counts and M
sum_counts = sum(counts[c] for c in target)
max_t = (sum_counts + M) // 5
low, high = 0, max_t
best_t = 0
while low <= high:
mid = (low + high) // 2
needed = 0
for c in target:
if counts[c] < mid:
needed += (mid - counts[c])
if needed > M:
break
if needed <= M:
best_t = mid
low = mid + 1
else:
high = mid - 1
t = best_t
# Step 2: Compute the number of subsequences using DP
dp = [0] * (len(target) + 1)
dp[0] = 1
for c in s:
for i in reversed(range(len(target))):
if c == target[i] or c == '?':
dp[i+1] += dp[i]
dp_result = dp[len(target)]
# The answer is the minimum of t and dp_result
return min(t, dp_result)
# Read input
s = input().strip()
print(max_kuroi_subsequences(s))
gew1fw