結果
| 問題 |
No.1481 Rotation ABC
|
| コンテスト | |
| ユーザー |
gew1fw
|
| 提出日時 | 2025-06-12 15:48:57 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 2,185 bytes |
| コンパイル時間 | 351 ms |
| コンパイル使用メモリ | 83,036 KB |
| 実行使用メモリ | 77,248 KB |
| 最終ジャッジ日時 | 2025-06-12 15:49:03 |
| 合計ジャッジ時間 | 5,413 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 10 TLE * 1 -- * 27 |
ソースコード
import sys
from collections import deque
MOD = 998244353
def main():
N = int(sys.stdin.readline())
S = list(sys.stdin.readline().strip())
# We can model each state as a tuple for hashing
initial = tuple(S)
visited = set()
queue = deque()
visited.add(initial)
queue.append(initial)
count = 0
while queue:
current = queue.popleft()
count += 1
# For each possible triplet, check if it's in A,B,C state
# Consider all possible orderings
# We need to look for triplets (i,j,k) in any of the three orderings where S_i=A, S_j=B, S_k=C
# For each such triplet, apply the operation and enqueue the new state if not visited
for i in range(N):
for j in range(N):
for k in range(N):
if i == j or j == k or k == i:
continue
# Check the three orderings
valid = False
# Check order 1: i < j < k
if i < j < k:
if current[i] == 'A' and current[j] == 'B' and current[k] == 'C':
valid = True
# Check order 2: j < k < i
elif j < k < i:
if current[i] == 'A' and current[j] == 'B' and current[k] == 'C':
valid = True
# Check order 3: k < i < j
elif k < i < j:
if current[i] == 'A' and current[j] == 'B' and current[k] == 'C':
valid = True
if valid:
# Create a new state
new_state = list(current)
new_state[i] = 'B'
new_state[j] = 'C'
new_state[k] = 'A'
new_state_tuple = tuple(new_state)
if new_state_tuple not in visited:
visited.add(new_state_tuple)
queue.append(new_state_tuple)
print(count % MOD)
if __name__ == "__main__":
main()
gew1fw