結果

問題 No.1345 Beautiful BINGO
ユーザー gew1fw
提出日時 2025-06-12 16:06:09
言語 PyPy3
(7.3.15)
結果
TLE  
実行時間 -
コード長 2,591 bytes
コンパイル時間 210 ms
コンパイル使用メモリ 82,336 KB
実行使用メモリ 83,172 KB
最終ジャッジ日時 2025-06-12 16:06:15
合計ジャッジ時間 5,244 ms
ジャッジサーバーID
（参考情報） 		judge4 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 5 TLE * 1 -- * 55
権限があれば一括ダウンロードができます

ソースコード

diff # 

import sys
import heapq
from itertools import combinations

def main():
    input = sys.stdin.read().split()
    ptr = 0
    N = int(input[ptr])
    ptr +=1
    M = int(input[ptr])
    ptr +=1
    
    grid = []
    for i in range(N):
        row = list(map(int, input[ptr:ptr+N]))
        ptr +=N
        grid.append(row)
    
    lines = []
    for i in range(N):  # rows
        mask = 0
        total = 0
        for j in range(N):
            cell = i * N + j
            mask |= (1 << cell)
            total += grid[i][j]
        lines.append((mask, total))
    for j in range(N):  # columns
        mask = 0
        total = 0
        for i in range(N):
            cell = i * N + j
            mask |= (1 << cell)
            total += grid[i][j]
        lines.append((mask, total))
    # main diagonals
    mask = 0
    total =0
    for i in range(N):
        j = i
        cell = i * N + j
        mask |= (1 << cell)
        total += grid[i][j]
    lines.append((mask, total))
    mask =0
    total =0
    for i in range(N):
        j = N -1 -i
        cell = i * N + j
        mask |= (1 << cell)
        total += grid[i][j]
    lines.append((mask, total))
    
    L = len(lines)
    heap = []
    visited = dict()
    for idx in range(L):
        mask, cost = lines[idx]
        key = (1, mask)
        if key not in visited or cost < visited[key]:
            visited[key] = cost
            heapq.heappush(heap, (cost, 1, mask, [idx]))
    
    while heap:
        current_cost, count, current_mask, used = heapq.heappop(heap)
        if count >= M:
            print(current_cost)
            return
        if (count, current_mask) in visited and visited[(count, current_mask)] < current_cost:
            continue
        for idx in range(L):
            if idx in used:
                continue
            l_mask, l_cost = lines[idx]
            new_mask = current_mask | l_mask
            added = l_mask & (~current_mask)
            new_cost = current_cost + bin(added).count('1') * 0
            sum_added = sum(grid[i][j] for i in range(N) for j in range(N) if (new_mask & (1 << (i*N + j))) and not (current_mask & (1 << (i*N + j))))
            new_cost = current_cost + sum_added
            new_count = count + 1
            new_used = used + [idx]
            key = (new_count, new_mask)
            if key in visited:
                if visited[key] <= new_cost:
                    continue
            visited[key] = new_cost
            heapq.heappush(heap, (new_cost, new_count, new_mask, new_used))
    
    print(-1)

if __name__ == "__main__":
    main()
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