結果

問題 No.2436 Min Diff Distance
ユーザー gew1fw
提出日時 2025-06-12 16:23:34
言語 PyPy3
(7.3.15)
結果
TLE  
実行時間 -
コード長 1,449 bytes
コンパイル時間 217 ms
コンパイル使用メモリ 82,108 KB
実行使用メモリ 53,384 KB
最終ジャッジ日時 2025-06-12 16:23:57
合計ジャッジ時間 4,210 ms
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 3 TLE * 1 -- * 19
権限があれば一括ダウンロードができます

ソースコード

diff #

import sys

def main():
    N = int(sys.stdin.readline())
    points = []
    a = []
    b = []
    for _ in range(N):
        x, y = map(int, sys.stdin.readline().split())
        points.append((x, y))
        a.append(x + y)
        b.append(x - y)
    
    max_a = max(a)
    min_a = min(a)
    max_b = max(b)
    min_b = min(b)
    
    # Precompute for each i the max_d
    max_d_list = []
    for i in range(N):
        ai = a[i]
        bi = b[i]
        d1 = max_a - ai
        d2 = ai - min_a
        d3 = max_b - bi
        d4 = bi - min_b
        max_d = max(d1, d2, d3, d4)
        max_d_list.append(max_d)
    
    # Compute min_d for each i (this part is not correct and needs to be addressed)
    # Placeholder approach, not correct
    min_d_list = []
    for i in range(N):
        ai = a[i]
        bi = b[i]
        min_val = float('inf')
        # This loop is O(N^2), which is not feasible for large N
        for j in range(N):
            if i == j:
                continue
            aj = a[j]
            bj = b[j]
            current_max = max(abs(ai - aj), abs(bi - bj))
            if current_max < min_val:
                min_val = current_max
        min_d_list.append(min_val)
    
    # Compute P_i and find the minimal
    min_p = float('inf')
    for i in range(N):
        p = max_d_list[i] - min_d_list[i]
        if p < min_p:
            min_p = p
    
    print(min_p)

if __name__ == "__main__":
    main()
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