結果
| 問題 |
No.260 世界のなんとか3
|
| コンテスト | |
| ユーザー |
gew1fw
|
| 提出日時 | 2025-06-12 18:26:25 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
MLE
|
| 実行時間 | - |
| コード長 | 3,749 bytes |
| コンパイル時間 | 203 ms |
| コンパイル使用メモリ | 82,432 KB |
| 実行使用メモリ | 78,416 KB |
| 最終ジャッジ日時 | 2025-06-12 18:27:00 |
| 合計ジャッジ時間 | 10,047 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 1 MLE * 26 |
ソースコード
MOD = 10**9 + 7
def subtract_one(s):
s_list = list(s)
i = len(s_list) - 1
while i >= 0 and s_list[i] == '0':
s_list[i] = '9'
i -= 1
if i == -1:
return '0'
s_list[i] = str(int(s_list[i]) - 1)
if s_list[0] == '0' and len(s_list) > 1:
return ''.join(s_list[1:])
return ''.join(s_list)
def count_aho(num_str):
digits = list(map(int, num_str))
n = len(digits)
dp_prev = [[[0] * 2 for _ in range(3)] for __ in range(2)]
dp_prev[1][0][0] = 1 # tight=1, mod3=0, has3=0
for pos in range(n):
dp_next = [[[0] * 2 for _ in range(3)] for __ in range(2)]
for tight in [0, 1]:
for mod3 in [0, 1, 2]:
for has3 in [0, 1]:
count = dp_prev[tight][mod3][has3]
if count == 0:
continue
max_d = digits[pos] if tight else 9
for d in range(0, max_d + 1):
new_tight = 1 if (tight and d == max_d) else 0
new_mod3_val = (mod3 + d) % 3
new_has3_val = 1 if (has3 or d == 3) else 0
dp_next[new_tight][new_mod3_val][new_has3_val] = (
dp_next[new_tight][new_mod3_val][new_has3_val] + count
) % MOD
dp_prev = dp_next
total = 0
for tight in [0, 1]:
for mod3 in [0, 1, 2]:
for has3 in [0, 1]:
if mod3 == 0 or has3 == 1:
total = (total + dp_prev[tight][mod3][has3]) % MOD
return total
def count_aho_and_eight(num_str):
digits = list(map(int, num_str))
n = len(digits)
dp_prev = [[[[0] * 8 for _ in range(2)] for __ in range(3)] for ___ in range(2)]
dp_prev[1][0][0][0] = 1 # tight=1, mod3=0, has3=0, mod8=0
for pos in range(n):
dp_next = [[[[0] * 8 for _ in range(2)] for __ in range(3)] for ___ in range(2)]
for tight in [0, 1]:
for mod3 in [0, 1, 2]:
for has3 in [0, 1]:
for mod8 in range(8):
count = dp_prev[tight][mod3][has3][mod8]
if count == 0:
continue
max_d = digits[pos] if tight else 9
for d in range(0, max_d + 1):
new_tight = 1 if (tight and d == max_d) else 0
new_mod3_val = (mod3 + d) % 3
new_has3_val = 1 if (has3 or d == 3) else 0
new_mod8_val = (mod8 * 10 + d) % 8
dp_next[new_tight][new_mod3_val][new_has3_val][new_mod8_val] = (
dp_next[new_tight][new_mod3_val][new_has3_val][new_mod8_val] + count
) % MOD
dp_prev = dp_next
total = 0
for tight in [0, 1]:
for mod3 in [0, 1, 2]:
for has3 in [0, 1]:
for mod8 in [0]:
if mod3 == 0 or has3 == 1:
total = (total + dp_prev[tight][mod3][has3][mod8]) % MOD
return total
def main():
A, B = input().split()
A_minus_1 = subtract_one(A)
# Calculate count_aho for B and A-1
count_B_aho = count_aho(B)
count_Aminus1_aho = count_aho(A_minus_1)
total_aho = (count_B_aho - count_Aminus1_aho) % MOD
# Calculate count_aho_and_eight for B and A-1
count_B_ae = count_aho_and_eight(B)
count_Aminus1_ae = count_aho_and_eight(A_minus_1)
total_ae = (count_B_ae - count_Aminus1_ae) % MOD
# The answer is (total_aho - total_ae) mod MOD
ans = (total_aho - total_ae) % MOD
print(ans)
if __name__ == "__main__":
main()
gew1fw