結果
問題 |
No.1400 すごろくで世界旅行
|
ユーザー |
![]() |
提出日時 | 2025-06-12 18:54:21 |
言語 | PyPy3 (7.3.15) |
結果 |
MLE
|
実行時間 | - |
コード長 | 2,945 bytes |
コンパイル時間 | 234 ms |
コンパイル使用メモリ | 82,384 KB |
実行使用メモリ | 405,476 KB |
最終ジャッジ日時 | 2025-06-12 18:54:31 |
合計ジャッジ時間 | 8,319 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 13 MLE * 2 -- * 3 |
ソースコード
import sys from collections import deque def main(): V, D = map(int, sys.stdin.readline().split()) E = [] for _ in range(V): s = sys.stdin.readline().strip() row = [int(c) for c in s] E.append(row) # Build adjacency list adj = [[] for _ in range(V)] for i in range(V): for j in range(V): if E[i][j] == 1: adj[i].append(j) # Check if the graph is strongly connected using Kosaraju's algorithm visited = [False] * V order = [] def dfs(u): stack = [(u, False)] while stack: node, processed = stack.pop() if processed: order.append(node) continue if visited[node]: continue visited[node] = True stack.append((node, True)) for v in adj[node]: if not visited[v]: stack.append((v, False)) for u in range(V): if not visited[u]: dfs(u) reverse_adj = [[] for _ in range(V)] for u in range(V): for v in adj[u]: reverse_adj[v].append(u) visited = [False] * V component = [0] * V label = 0 def reverse_dfs(u, label): stack = [u] visited[u] = True component[u] = label while stack: node = stack.pop() for v in reverse_adj[node]: if not visited[v]: visited[v] = True component[v] = label stack.append(v) for u in reversed(order): if not visited[u]: reverse_dfs(u, label) label += 1 if label != 1: print("No") return # Check bipartite color = [-1] * V is_bip = True start = 0 color[start] = 0 q = deque([start]) while q: u = q.popleft() for v in adj[u]: if color[v] == -1: color[v] = color[u] ^ 1 q.append(v) elif color[v] == color[u]: is_bip = False break if not is_bip: break if is_bip: print("No") return # Check if D is large enough if D >= 2 * V - 2: print("Yes") return # Compute diameter max_diameter = 0 for u in range(V): dist = [-1] * V q = deque([u]) dist[u] = 0 current_max = 0 while q: node = q.popleft() for v in adj[node]: if dist[v] == -1: dist[v] = dist[node] + 1 current_max = max(current_max, dist[v]) q.append(v) max_diameter = max(max_diameter, current_max) if max_diameter > D: print("No") return print("Yes") if __name__ == "__main__": main()