結果
| 問題 |
No.2019 Digits Filling for All Substrings
|
| コンテスト | |
| ユーザー |
gew1fw
|
| 提出日時 | 2025-06-12 19:04:27 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 2,086 bytes |
| コンパイル時間 | 681 ms |
| コンパイル使用メモリ | 82,452 KB |
| 実行使用メモリ | 99,392 KB |
| 最終ジャッジ日時 | 2025-06-12 19:04:44 |
| 合計ジャッジ時間 | 3,967 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | TLE * 1 -- * 29 |
ソースコード
MOD = 998244353
def main():
import sys
input = sys.stdin.read
data = input().split()
N = int(data[0])
S = data[1]
# Precompute prefix sums for sum_mod and number of '?'
pre_mod = [0] * (N + 1)
pre_q = [0] * (N + 1)
for i in range(1, N+1):
c = S[i-1]
if c == '?':
pre_q[i] = pre_q[i-1] + 1
pre_mod[i] = pre_mod[i-1]
else:
d = int(c)
pre_mod[i] = (pre_mod[i-1] + d) % 3
pre_q[i] = pre_q[i-1]
# Precompute pow_dp[k][r] where r is 0,1,2
max_k = N
a, b, c = 4, 3, 3 # coefficients of f(x) = 4 + 3x +3x²
pow_dp = [ [0]*3 for _ in range(max_k+1) ]
pow_dp[0][0] = 1
for k in range(1, max_k+1):
for r in range(3):
# Multiply by f(x): for each term x^r, multiply by 4, 3x, 3x²
# and accumulate to new_r = (r + s) mod3 for s=0,1,2
new_r0 = (pow_dp[k-1][r] * a) % MOD
new_r1 = (pow_dp[k-1][r] * b) % MOD
new_r2 = (pow_dp[k-1][r] * c) % MOD
pow_dp[k][(r + 0) %3] = (pow_dp[k][(r +0) %3] + new_r0) % MOD
pow_dp[k][(r +1) %3] = (pow_dp[k][(r +1) %3] + new_r1) % MOD
pow_dp[k][(r +2) %3] = (pow_dp[k][(r +2) %3] + new_r2) % MOD
# Calculate sum_f_part1: sum for k>0
sum_f_part1 = 0
for L in range(1, N+1):
for R in range(L, N+1):
k = pre_q[R] - pre_q[L-1]
if k == 0:
continue
sum_mod = (pre_mod[R] - pre_mod[L-1]) % 3
t = (-sum_mod) %3
sum_f_part1 = (sum_f_part1 + pow_dp[k][t]) % MOD
# Calculate sum_f_part2: sum for k=0 and sum_mod ==0
sum_f_part2 = 0
for L in range(1, N+1):
for R in range(L, N+1):
k = pre_q[R] - pre_q[L-1]
if k !=0:
continue
sum_mod = (pre_mod[R] - pre_mod[L-1]) %3
if sum_mod ==0:
sum_f_part2 +=1
total = (sum_f_part1 + sum_f_part2) % MOD
print(total)
if __name__ == '__main__':
main()
gew1fw