結果
| 問題 |
No.595 登山
|
| ユーザー |
gew1fw
|
| 提出日時 | 2025-06-12 19:13:43 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 1,036 bytes |
| コンパイル時間 | 425 ms |
| コンパイル使用メモリ | 82,588 KB |
| 実行使用メモリ | 112,676 KB |
| 最終ジャッジ日時 | 2025-06-12 19:13:48 |
| 合計ジャッジ時間 | 4,569 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 4 WA * 21 |
ソースコード
def main():
import sys
input = sys.stdin.read().split()
idx = 0
N = int(input[idx])
idx += 1
P = int(input[idx])
idx += 1
H = list(map(int, input[idx:idx+N]))
idx += N
if P == 0:
print(0)
return
# Compute sum1: sum1[i] is the cost to move from 1 to (i+1)th location (0-based)
sum1 = [0] * N
for i in range(1, N):
sum1[i] = sum1[i-1] + max(0, H[i] - H[i-1])
# Compute sum2: sum2[i] is the cost to move from (i+1)th location to N-1th location (0-based)
sum2 = [0] * N
for i in range(N-2, -1, -1):
sum2[i] = sum2[i+1] + max(0, H[i] - H[i+1])
# Compute the minimal cost when using exactly one teleport
min_cost = float('inf')
for k in range(N):
current = sum1[k] + sum2[k] + P
if current < min_cost:
min_cost = current
# Compare with the cost of not teleporting
no_teleport_cost = sum1[-1]
print(min(min_cost, no_teleport_cost))
if __name__ == "__main__":
main()
gew1fw