結果
| 問題 | 
                            No.1153 ねこちゃんゲーム
                             | 
                    
| コンテスト | |
| ユーザー | 
                             gew1fw
                         | 
                    
| 提出日時 | 2025-06-12 19:24:33 | 
| 言語 | PyPy3  (7.3.15)  | 
                    
| 結果 | 
                             
                                WA
                                 
                             
                            
                         | 
                    
| 実行時間 | - | 
| コード長 | 1,986 bytes | 
| コンパイル時間 | 184 ms | 
| コンパイル使用メモリ | 81,900 KB | 
| 実行使用メモリ | 144,976 KB | 
| 最終ジャッジ日時 | 2025-06-12 19:25:12 | 
| 合計ジャッジ時間 | 32,324 ms | 
| 
                            ジャッジサーバーID (参考情報)  | 
                        judge2 / judge4 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 2 | 
| other | AC * 6 WA * 29 TLE * 1 -- * 4 | 
ソースコード
import sys
from collections import deque
def main():
    sys.setrecursionlimit(1 << 25)
    n, m = map(int, sys.stdin.readline().split())
    A = list(map(int, sys.stdin.readline().split()))
    edges = [[] for _ in range(n+1)]
    for _ in range(n-1):
        u, v = map(int, sys.stdin.readline().split())
        edges[u].append(v)
        edges[v].append(u)
    
    # Build the tree with parent pointers and children lists
    root = 1
    parent = [0] * (n + 1)
    children = [[] for _ in range(n + 1)]
    visited = [False] * (n + 1)
    q = deque([root])
    visited[root] = True
    while q:
        u = q.popleft()
        for v in edges[u]:
            if not visited[v]:
                visited[v] = True
                parent[v] = u
                children[u].append(v)
                q.append(v)
    
    # Compute Grundy numbers using iterative post-order traversal
    g = [0] * (n + 1)
    stack = []
    visited_post = [False] * (n + 1)
    stack.append((root, False))
    while stack:
        u, processed = stack.pop()
        if processed:
            s = set()
            for v in children[u]:
                s.add(g[v])
            mex = 0
            while mex in s:
                mex += 1
            g[u] = mex
        else:
            stack.append((u, True))
            for v in reversed(children[u]):
                stack.append((v, False))
    
    # Calculate the total XOR
    T = 0
    for a in A:
        T ^= g[a]
    
    if T == 0:
        print(-1, -1)
    else:
        # Find a valid move for Ebi-chan
        found = False
        for idx in range(m):
            u = A[idx]
            current_g = g[u]
            target = current_g ^ T
            for v in children[u]:
                if g[v] == target:
                    print(idx + 1, v)
                    found = True
                    break
            if found:
                break
        if not found:
            print(-1, -1)
if __name__ == "__main__":
    main()
            
            
            
        
            
gew1fw