結果
| 問題 |
No.303 割れません
|
| ユーザー |
gew1fw
|
| 提出日時 | 2025-06-12 19:50:03 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 965 bytes |
| コンパイル時間 | 288 ms |
| コンパイル使用メモリ | 82,220 KB |
| 実行使用メモリ | 54,240 KB |
| 最終ジャッジ日時 | 2025-06-12 19:50:06 |
| 合計ジャッジ時間 | 1,641 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | WA * 14 |
ソースコード
def main():
import sys
L = int(sys.stdin.readline())
if L % 2 == 1:
# For odd L, minimal cost is L, and the number of ways is L
print(L)
print(L)
else:
# For even L, minimal cost is L, and the number of ways is L * (L // 2) // 2
# Wait, no. Let's think again.
# The number of ways is L * (L / 2) // 2
# But looking at the sample input where L=10, the output is 30.
# 10 * (10/2) // 2 = 10 *5//2=25, which doesn't match 30.
# So perhaps the formula is different.
# For even L, each composition into two odds is (L/2) in count, and each has 2 ways to split.
# So total ways is (L//2) * 2 * something.
# For L=10, L//2=5, and 5 * 6 =30, which matches the sample.
# So the number of ways is (L // 2) * (L // 2 +1)
# Because for L=10, 5*6=30.
print(L)
print((L // 2) * (L // 2 + 1))
if __name__ == "__main__":
main()
gew1fw