結果
| 問題 |
No.2026 Yet Another Knapsack Problem
|
| コンテスト | |
| ユーザー |
gew1fw
|
| 提出日時 | 2025-06-12 21:10:27 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 1,745 bytes |
| コンパイル時間 | 383 ms |
| コンパイル使用メモリ | 81,980 KB |
| 実行使用メモリ | 133,672 KB |
| 最終ジャッジ日時 | 2025-06-12 21:12:22 |
| 合計ジャッジ時間 | 38,972 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 35 TLE * 1 -- * 6 |
ソースコード
def main():
import sys
input = sys.stdin.read
data = input().split()
idx = 0
N = int(data[idx])
idx += 1
items = []
for i in range(1, N+1):
c_i = int(data[idx])
v_i = int(data[idx+1])
idx += 2
items.append((i, c_i, v_i))
# Initialize DP
INF = -1 << 60
dp = [[INF] * (N + 1) for _ in range(N + 1)]
dp[0][0] = 0
for i, c_i, v_i in items:
# We need to handle taking x items, x can be 0~c_i
# Use binary optimization
virtual = []
x = 1
while x <= c_i:
take = min(x, c_i)
virtual.append((take, take * i, take * v_i))
c_i -= take
x *= 2
if c_i > 0:
virtual.append((c_i, c_i * i, c_i * v_i))
# For each virtual item, process 0-1 knapsack style
for dx, dw, dv in virtual:
# Update dp: for each (k, w), try adding dx, dw, dv
for k in range(N, -1, -1):
for w in range(N, -1, -1):
if dp[k][w] != INF:
new_k = k + dx
new_w = w + dw
if new_k > N or new_w > N:
continue
if dp[new_k][new_w] < dp[k][w] + dv:
dp[new_k][new_w] = dp[k][w] + dv
# Now, for each k from 1 to N, find the maximum value among w <= N
result = []
for k in range(1, N+1):
max_val = INF
for w in range(0, N+1):
if dp[k][w] > max_val and dp[k][w] != INF:
max_val = dp[k][w]
result.append(max_val)
for val in result:
print(val)
if __name__ == '__main__':
main()
gew1fw