結果

問題 No.1630 Sorting Integers (Greater than K)
ユーザー gew1fw
提出日時 2025-06-12 21:15:47
言語 PyPy3
(7.3.15)
結果
TLE  
実行時間 -
コード長 2,940 bytes
コンパイル時間 222 ms
コンパイル使用メモリ 82,116 KB
実行使用メモリ 262,828 KB
最終ジャッジ日時 2025-06-12 21:16:58
合計ジャッジ時間 9,898 ms
ジャッジサーバーID
(参考情報)
judge2 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 5
other AC * 12 TLE * 2 -- * 8
権限があれば一括ダウンロードができます

ソースコード

diff #

import sys
from copy import deepcopy

def can_form_larger(counts, s):
    if not s:
        return False
    current_counts = counts.copy()
    for i in range(len(s)):
        current_digit = int(s[i])
        # Check if any digit larger than current_digit exists
        for d in range(current_digit + 1, 10):
            if current_counts[d] > 0:
                return True
        # Check if current_digit is available
        if current_counts[current_digit] == 0:
            return False
        current_counts[current_digit] -= 1
    return False

def solve():
    N, K = sys.stdin.readline().split()
    N = int(N)
    c = list(map(int, sys.stdin.readline().split()))
    counts = [0] * 10  # counts[1..9] are used
    for i in range(9):
        counts[i+1] = c[i]
    
    if len(K) != N:
        if len(K) > N:
            print(-1)
            return
        else:
            # Form the smallest possible N-digit number
            res = []
            for d in range(1, 10):
                res.append(str(d) * counts[d])
            res = ''.join(res)
            if len(res) == N:
                print(res)
            else:
                print(-1)
            return
    
    # Now, len(K) == N
    current_counts = deepcopy(counts)
    prefix = []
    for i in range(N):
        current_digit = int(K[i])
        found = False
        for d in range(current_digit, 10):
            if current_counts[d] == 0:
                continue
            if d > current_digit:
                # Use this d and fill the rest with sorted remaining digits
                temp_counts = current_counts.copy()
                temp_counts[d] -= 1
                remaining = []
                for digit in range(1, 10):
                    remaining.append(str(digit) * temp_counts[digit])
                remaining = ''.join(remaining)
                candidate = ''.join(prefix) + str(d) + remaining
                if len(candidate) != N:
                    continue
                if candidate > K:
                    print(candidate)
                    return
            else:
                # Check if using d allows remaining digits to form a larger number
                temp_counts = current_counts.copy()
                temp_counts[d] -= 1
                if can_form_larger(temp_counts, K[i+1:]):
                    current_counts[d] -= 1
                    prefix.append(str(d))
                    found = True
                    break
        if not found:
            # Check if we can use current_digit
            if current_counts[current_digit] > 0:
                current_counts[current_digit] -= 1
                prefix.append(str(current_digit))
            else:
                print(-1)
                return
    # After processing all digits, check if the formed number is larger than K
    formed = ''.join(prefix)
    if formed > K:
        print(formed)
    else:
        print(-1)

solve()
0