結果
問題 | No.204 ゴールデン・ウィーク(2) |
ユーザー |
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提出日時 | 2025-06-12 21:44:02 |
言語 | PyPy3 (7.3.15) |
結果 |
WA
|
実行時間 | - |
コード長 | 1,515 bytes |
コンパイル時間 | 317 ms |
コンパイル使用メモリ | 81,732 KB |
実行使用メモリ | 53,984 KB |
最終ジャッジ日時 | 2025-06-12 21:48:26 |
合計ジャッジ時間 | 3,181 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 25 WA * 21 |
ソースコード
def main(): import sys D = int(sys.stdin.readline()) line1 = sys.stdin.readline().strip() line2 = sys.stdin.readline().strip() S = line1 + line2 # S is 14 characters # Find all runs of 'o's runs = [] n = len(S) i = 0 while i < n: if S[i] == 'o': start = i while i < n and S[i] == 'o': i += 1 end = i - 1 runs.append((start, end)) else: i += 1 # Compute max_run max_run = max((end - start + 1) for (start, end) in runs) if runs else 0 # Compute possible candidates candidates = [max_run, D] # Check runs before and after if runs: first_start, first_end = runs[0] if first_start == 0: candidates.append(D + (first_end - first_start + 1)) last_start, last_end = runs[-1] if last_end == len(S) - 1: candidates.append((last_end - last_start + 1) + D) # Check all pairs of runs for i in range(len(runs)): for j in range(i + 1, len(runs)): run_i = runs[i] run_j = runs[j] # Distance between run_i's end and run_j's start distance = run_j[0] - run_i[1] - 1 if distance <= D: merged = (run_i[1] - run_i[0] + 1) + (run_j[1] - run_j[0] + 1) + distance candidates.append(merged) # The maximum possible max_length = max(candidates) print(max_length) if __name__ == '__main__': main()