結果
| 問題 |
No.3178 free sort
|
| コンテスト | |
| ユーザー |
iomir
|
| 提出日時 | 2025-06-13 21:52:41 |
| 言語 | C++23 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 3,854 bytes |
| コンパイル時間 | 2,990 ms |
| コンパイル使用メモリ | 281,832 KB |
| 実行使用メモリ | 27,216 KB |
| 最終ジャッジ日時 | 2025-06-13 21:52:50 |
| 合計ジャッジ時間 | 8,206 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 5 |
| other | WA * 40 |
ソースコード
#include<bits/stdc++.h>
//#include <atcoder/all>
using namespace std;
//using namespace atcoder;
#define all(v) v.begin(),v.end()
using ll = long long;
using ull = unsigned long long;
using lll = __int128;
using vll=vector<ll>;
using vvll = vector<vector<ll>>;
using P = pair<ll,ll>;
using vp=vector<pair<ll, ll>>;
//using mint=modint1000000007;
//using mint=modint998244353;
const ll INF=1ll<<60;
ll mod10=1e9+7;
ll mod99=998244353;
const double PI = acos(-1);
#define rep(i,n) for (ll i=0;i<n;++i)
#define per(i,n) for(ll i=n-1;i>=0;--i)
#define rep2(i,a,n) for (ll i=a;i<n;++i)
#define per2(i,a,n) for (ll i=a;i>=n;--i)
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }
template <long long MOD>
struct modint {
long long value;
modint(long long x = 0) {
if (x >= 0) {
value = x % MOD;
} else {
value = MOD - (-x) % MOD;
}
}
modint operator-() const {
return modint(-value);
}
modint operator+() const {
return modint(*this);
}
modint &operator+=(const modint &other) {
value += other.value;
if (value >= MOD) {
value -= MOD;
}
return *this;
}
modint &operator-=(const modint &other) {
value += MOD - other.value;
if (value >= MOD) {
value -= MOD;
}
return *this;
}
modint &operator*=(const modint other) {
value = value * other.value % MOD;
return *this;
}
modint &operator/=(modint other) {
(*this) *= other.inv();
return *this;
}
modint operator+(const modint &other) const {
return modint(*this) += other;
}
modint operator-(const modint &other) const {
return modint(*this) -= other;
}
modint operator*(const modint &other) const {
return modint(*this) *= other;
}
modint operator/(const modint &other) const {
return modint(*this) /= other;
}
modint pow(long long x) const {
modint ret(1), mul(value);
while (x > 0) {
if (x % 2 == 1) {
ret *= mul;
}
mul *= mul;
x /= 2;
}
return ret;
}
modint inv() const {
return pow(MOD - 2);
}
bool operator==(const modint &other) const {
return value == other.value;
}
bool operator!=(const modint &other) const {
return value != other.value;
}
friend std::ostream &operator<<(std::ostream &os, const modint &x) {
return os << x.value;
}
friend std::istream &operator>>(std::istream &is, modint &x) {
long long v;
is >> v;
x = modint<MOD>(v);
return is;
}
};
using mint = modint<998244353>;
using mod107 = modint<1000000007>;
vector<ll> fact,invfact,inv;
void init(ll N,ll mod){
fact.resize(N+5);
inv.resize(N+5);
invfact.resize(N+5);
fact[0]=1;fact[1]=1;
invfact[0]=1;invfact[1]=1;
inv[0]=1;inv[1]=1;
for(int i=2;i<N+3;i++){
fact[i]=fact[i-1]*i%mod;
inv[i]=mod-inv[mod%i]*(mod/i)%mod;
invfact[i] = invfact[i-1]*inv[i]%mod;
}
}
ll nCk(ll n,ll x,ll mod){
return fact[n]*invfact[n-x]%mod*invfact[x]%mod;
}
bool solve(){
string S;cin>>S;
ll N=S.size();
vll cnt(10);
rep(i,N) cnt[S[i]-'0']++;
mint ans=fact[N];rep(i,10) ans/=fact[cnt[i]];
if(cnt[0]==0){
cout << ans << endl;
return 0;
}
mint ans2=fact[N-1]/fact[cnt[0]-1];rep2(i,1,10) ans2/=fact[cnt[i]];
cout << ans-ans2 << endl;
return 0;
}
int main(){
init(1000000,mod99);
cin.tie(0);
ios::sync_with_stdio(false);
ll T=1;//cin>>T;
rep(i,T) solve();
}
iomir