結果

問題 No.3185 Three Abs
ユーザー HackberryA3
提出日時 2025-06-20 22:48:24
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 4,187 bytes
コンパイル時間 3,085 ms
コンパイル使用メモリ 285,968 KB
実行使用メモリ 25,296 KB
最終ジャッジ日時 2025-06-20 22:48:33
合計ジャッジ時間 8,551 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other WA * 30
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ull = unsigned long long;
using vll = vector<ll>;
using vvll = vector<vll>;
using P = pair<int, int>;
using PP = pair<int, P>;
using PLL = pair<ll, ll>;
using PPLL = pair<ll, PLL>;
#define rep(i, n) for (ll i = 0; i < (ll)n; ++i)
#define rrep(i, n) for (ll i = n - 1; i >= 0; --i)
#define loop(i, a, b) for (ll i = a; i <= b; ++i)
#define all(v) v.begin(), v.end()
#define nC2(n) n *(n - 1) / 2
constexpr ll INF = 9009009009009009009LL;
constexpr int INF32 = 2002002002;
constexpr ll MOD = 998244353;
constexpr ll MOD107 = 1000000007;

// Linear Algebra ////////////////////////////////////////////////
const double Rad2Deg = 180.0 / M_PI;
const double Deg2Rad = M_PI / 180.0;
//////////////////////////////////////////////////////////////////

int dx[8] = {0, 1, 0, -1, 1, 1, -1, -1};
int dy[8] = {1, 0, -1, 0, 1, -1, 1, -1};

template <class T> inline bool chmax(T &a, const T &b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}
template <class T> inline bool chmin(T &a, const T &b) {
    if (a > b) {
        a = b;
        return true;
    }
    return false;
}

template <typename Container,
          typename = std::enable_if_t<
              !std::is_same_v<Container, std::string> &&
              std::is_convertible_v<decltype(std::declval<Container>().begin()),
                                    typename Container::iterator>>>
ostream &operator<<(ostream &os, const Container &container) {
    auto it = container.begin();
    auto end = container.end();

    if (it != end) {
        os << *it;
        ++it;
    }
    for (; it != end; ++it) {
        os << " " << *it;
    }
    return os;
}
template <typename T> ostream &operator<<(ostream &os, const vector<T> &v) {
    for (size_t i = 0; i < v.size(); ++i) {
        os << v[i];
        if (i != v.size() - 1) os << " ";
    }
    return os;
}
template <typename T>
ostream &operator<<(ostream &os, const vector<vector<T>> &vv) {
    for (size_t i = 0; i < vv.size(); ++i) {
        os << vv[i];
        if (i != vv.size() - 1) os << "\n";
    }
    return os;
}
template <typename T> istream &operator>>(istream &is, vector<T> &v) {
    assert(v.size() > 0);
    for (size_t i = 0; i < v.size(); ++i)
        is >> v[i];
    return is;
}
template <typename T> istream &operator>>(istream &is, vector<vector<T>> &vv) {
    assert(vv.size() > 0);
    for (size_t i = 0; i < vv.size(); ++i)
        is >> vv[i];
    return is;
}

struct phash
{
    template <class T1, class T2>
    inline size_t operator()(const pair<T1, T2> &p) const {
        auto h1 = hash<T1>()(p.first);
        auto h2 = hash<T2>()(p.second);

        size_t seed = h1 + h2;
        h1 = ((h1 >> 16) ^ h1) * 0x45d9f3b;
        h1 = ((h1 >> 16) ^ h1) * 0x45d9f3b;
        h1 = (h1 >> 16) ^ h1;
        seed ^= h1 + 0x9e3779b9 + (seed << 6) + (seed >> 2);
        h2 = ((h2 >> 16) ^ h2) * 0x45d9f3b;
        h2 = ((h2 >> 16) ^ h2) * 0x45d9f3b;
        h2 = (h2 >> 16) ^ h2;
        seed ^= h2 + 0x9e3779b9 + (seed << 6) + (seed >> 2);
        return seed;
    }
};

template <typename T> using v = vector<T>;
template <typename T> using vv = vector<vector<T>>;
int solve() {
    ll t;
    cin >> t;
    while (t--) {
        ll n;
        cin >> n;
        vll a(n);
        cin >> a;

        vv<tuple<ll, ll, ll>> dp(n + 1, v<tuple<ll, ll, ll>>(3, {0, 0, 0}));
        rep(i, n) {
			dp[i + 1][0] = dp[i][0];
			get<0>(dp[i + 1][0]) += a[i];

			if (0 < i) {
				ll x = abs(get<0>(dp[i][0])) + abs(a[i]);
				ll y = abs(get<0>(dp[i][1])) + abs(get<1>(dp[i][1]) + a[i]);
				dp[i + 1][1] = x > y ? dp[i][0] : dp[i][1];
				get<1>(dp[i + 1][1]) += a[i];
			}
			if (1 < i) {
				ll x = abs(get<0>(dp[i][1])) + abs(get<1>(dp[i][1])) + abs(a[i]);
				ll y = abs(get<0>(dp[i][2])) + abs(get<1>(dp[i][2])) + abs(get<2>(dp[i][2]) + a[i]);
				dp[i + 1][2] = x > y ? dp[i][1] : dp[i][2];
				get<2>(dp[i + 1][2]) += a[i];
			}
        }

		cout << abs(get<0>(dp[n][2])) + abs(get<1>(dp[n][2])) + abs(get<2>(dp[n][2])) << "\n";
    }

    return 0;
}

int main() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);

    return solve();
}
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