結果
| 問題 |
No.3202 Periodic Alternating Subsequence
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2025-07-12 13:56:20 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 1,274 ms / 2,000 ms |
| コード長 | 2,225 bytes |
| コンパイル時間 | 457 ms |
| コンパイル使用メモリ | 81,952 KB |
| 実行使用メモリ | 77,172 KB |
| 最終ジャッジ日時 | 2025-07-12 13:56:47 |
| 合計ジャッジ時間 | 27,321 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 24 |
ソースコード
import sys
input = lambda :sys.stdin.readline()[:-1]
ni = lambda :int(input())
na = lambda :list(map(int,input().split()))
yes = lambda :print("yes");Yes = lambda :print("Yes");YES = lambda : print("YES")
no = lambda :print("no");No = lambda :print("No");NO = lambda : print("NO")
#######################################################################
#2D matrix
mod = 10 ** 9 + 7
def mat_add(A, B):
assert len(A)==len(B) and len(A[0]) == len(B[0])
n = len(A)
m = len(A[0])
for i in range(n):
for j in range(m):
A[i][j] += B[i][j]
A[i][j] %= mod
return A
def mat_mul(A,B):
assert len(A[0]) == len(B)
n = len(A)
m = len(B[0])
p = len(A[0])
R = [[0 for j in range(m)]for i in range(n)]
for i in range(n):
for j in range(m):
for k in range(p):
R[i][j] += A[i][k]*B[k][j] % mod
R[i][j] %= mod
return R
def mat_pow(A, x):
assert len(A)==len(A[0])
n = len(A)
R = [[0 for j in range(n)]for i in range(n)]
for i in range(n):
R[i][i] = 1
while x > 0:
if x&1:
R = mat_mul(R, A)
A = mat_mul(A,A)
x >>= 1
return R
def mat_pri(A):
for i in A:
print(*i)
t = input()
k = ni()
M = 7
S = [[0] * M for i in range(M)]
for i in range(M):
S[i][i] = 1
A = [[1, 1, 0, 1, 0, 0, 0],
[0, 1, 0, 0, 0, 0, 0],
[0, 1, 1, 1, 0, 0, 0],
[0, 0, 0, 1, 0, 0, 0],
[0, 0, 0, 1, 1, 1, 0],
[0, 0, 0, 0, 0, 1, 0],
[0, 0, 0, 0, 0, 1, 1]]
B = [[1, 0, 1, 0, 1, 0, 0],
[0, 1, 1, 0, 1, 0, 0],
[0, 0, 1, 0, 0, 0, 0],
[0, 0, 0, 1, 1, 0, 1],
[0, 0, 0, 0, 1, 0, 0],
[0, 0, 0, 0, 0, 1, 1],
[0, 0, 0, 0, 0, 0, 1]]
for i in range(len(t)):
if t[i] == "0":
S = mat_mul(S, A)
else:
S = mat_mul(S, B)
S = mat_pow(S, k)
# print(S)
v = [[1, 0, 0, 0, 0, 0, 0]]
v = mat_mul(v, S)
# print(v)
ans = v[0][3] + v[0][4] + v[0][5] * 2 + v[0][6] * 2
print(ans % mod)
# v = [[1, 0, 0, 0, 0, 0, 0]]
# for _ in range(k):
# for i in range(len(t)):
# if t[i] == "0":
# v = mat_mul(v, A)
# else:
# v = mat_mul(v, B)
# print(v)