結果
| 問題 |
No.5022 XOR Printer
|
| コンテスト | |
| ユーザー |
👑 |
| 提出日時 | 2025-07-26 15:53:14 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 2 ms / 2,000 ms |
| コード長 | 4,236 bytes |
| コンパイル時間 | 3,932 ms |
| コンパイル使用メモリ | 258,624 KB |
| 実行使用メモリ | 7,716 KB |
| スコア | 4,965,975,011 |
| 最終ジャッジ日時 | 2025-07-26 15:53:22 |
| 合計ジャッジ時間 | 5,714 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
| 純コード判定しない問題か言語 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| other | AC * 50 |
ソースコード
#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef pair<int, int> P;
template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}
int main(){
int N, T;
cin >> N >> T;
const int K = 20;
const int M = 6;
vector<vector<int>> A(N, vector<int>(N));
cin >> A;
vector<pair<int, int>> basis;
int y = 0, x = 0, s = 0;
string O;
auto R = [&](){x++; O += 'R';};
auto L = [&](){x--; O += 'L';};
auto D = [&](){y++; O += 'D';};
auto U = [&](){y--; O += 'U';};
auto C = [&](){s ^= A[y][x]; O += 'C';};
auto W = [&](){A[y][x] ^= s; O += 'W';};
vector<pair<int, int>> P;
rep(z, N / 2){
rep(x, N) P.emplace_back(2 * z, x);
rep(x, N) P.emplace_back(2 * z + 1, (N - 1) - x);
}
auto Move = [&](int y_to, int x_to){
while(y_to > y) D();
while(x_to > x) R();
while(y_to < y) U();
while(x_to < x) L();
};
rep(p, M){
for(auto [y1, x1] : P){
bool ng = false;
for(int q = 0; q < p; q++){
auto [y2, x2] = basis[q];
if(y1 == y2 and x1 == x2) ng = true;
}
if(ng) continue;
bool success = false;
{
int val = A[y1][x1] ^ s;
for(int q = 0; q < p; q++){
auto [y2, x2] = basis[q];
if((val >> (K - 1 - q)) & 1) val ^= A[y2][x2];
}
if((val >> (K - 1 - p)) & 1){
success = true;
}
}
if(success){
cerr << y1 << ' ' << x1 << "\n";
int val = A[y1][x1] ^ s;
cerr << val << "\n";
for(int q = 0; q < p; q++){
auto [y2, x2] = basis[q];
if((val >> (K - 1 - q)) & 1){
val ^= A[y2][x2];
Move(y2, x2);
C();
}
cerr << val << "\n";
}
Move(y1, x1);
W();
basis.emplace_back(y1, x1);
break;
}
}
}
rep(p, M){
for(int q = 0; q < p; q++){
if((s >> (K - 1 - q)) & 1){
auto [y1, x1] = basis[q];
Move(y1, x1);
C();
}
}
{
if(((s >> (K - 1 - p)) & 1) == 0){
auto [y1, x1] = basis[p];
Move(y1, x1);
C();
}
}
for(auto [y1, x1] : P){
bool ng = false;
for(int q = 0; q < M; q++){
auto [y2, x2] = basis[q];
if(y1 == y2 and x1 == x2) ng = true;
}
if(ng) continue;
if(((A[y1][x1] >> (K - 1 - p)) & 1) == 0){
Move(y1, x1);
W();
}
}
}
rep(i, min(int(O.size()), T)){
auto c = O[i];
cout << c << "\n";
}
return 0;
}