結果
| 問題 |
No.3227 Matrix Query
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2025-08-08 21:47:55 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 469 ms / 8,000 ms |
| コード長 | 8,724 bytes |
| コンパイル時間 | 2,421 ms |
| コンパイル使用メモリ | 211,052 KB |
| 実行使用メモリ | 7,720 KB |
| 最終ジャッジ日時 | 2025-08-08 21:48:09 |
| 合計ジャッジ時間 | 12,696 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 28 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
//入力が必ず-mod<a<modの時.
template<int idx> //modが入力で与えられる場合.
struct dynamic_modint{ //mod変更が可能 最初にsetmod必須 idxで複数個所持が可能.
private:
static int mod;
public:
long long v = 0;
static constexpr long long getmod(){return mod;}
static void setmod(int m){
assert(m > 0);
mod = m;
}
dynamic_modint(){v = 0;}
dynamic_modint(int a){v = a<0?a+mod:a;} dynamic_modint(long long a){v = a<0?a+mod:a;}
dynamic_modint(unsigned int a){v = a;}
dynamic_modint(unsigned long long a){v = a;}
long long val()const{return v;}
void modu(){v = (v%mod+mod)%mod;}
dynamic_modint &operator=(const dynamic_modint &b) = default;
dynamic_modint operator+()const{return (*this);}
dynamic_modint operator-()const{return dynamic_modint(0)-(*this);}
dynamic_modint operator+(const dynamic_modint b)const{return dynamic_modint(v)+=b;}
dynamic_modint operator-(const dynamic_modint b)const{return dynamic_modint(v)-=b;}
dynamic_modint operator*(const dynamic_modint b)const{return dynamic_modint(v)*=b;}
dynamic_modint operator/(const dynamic_modint b)const{return dynamic_modint(v)/=b;}
dynamic_modint operator+=(const dynamic_modint b){
v += b.v; if(v >= mod) v -= mod;
return *this;
}
dynamic_modint operator-=(const dynamic_modint b){
v -= b.v; if(v < 0) v += mod;
return *this;
}
dynamic_modint operator*=(const dynamic_modint b){v = v*b.v%mod; return *this;}
dynamic_modint operator/=(dynamic_modint b){ //b!=0 mod素数が必須.
if(b == 0) assert(false);
int left = mod-2;
while(left){if(left&1) *this *= b; b *= b; left >>= 1;}
return *this;
}
dynamic_modint operator++(){*this += 1; return *this;}
dynamic_modint operator--(){*this -= 1; return *this;}
dynamic_modint operator++(int){*this += 1; return *this;}
dynamic_modint operator--(int){*this -= 1; return *this;}
bool operator==(const dynamic_modint b)const{return v == b.v;}
bool operator!=(const dynamic_modint b)const{return v != b.v;}
bool operator>(const dynamic_modint b)const{return v > b.v;}
bool operator>=(const dynamic_modint b)const{return v >= b.v;}
bool operator<(const dynamic_modint b)const{return v < b.v;}
bool operator<=(const dynamic_modint b)const{return v <= b.v;}
dynamic_modint pow(long long n)const{
dynamic_modint ret = 1,p = v;
if(n < 0) p = p.inv(),n = -n;
while(n){
if(n&1) ret *= p;
p *= p; n >>= 1;
}
return ret;
}
dynamic_modint inv()const{return dynamic_modint(1)/v;} //素数mod必須.
};
template<int idx> int dynamic_modint<idx>::mod=998244353;
using mint = dynamic_modint<0>;
template<typename T>
vector<vector<T>> multima(vector<vector<T>> &A,vector<vector<T>> &B){
assert(A.at(0).size() == B.size() && B.size());
int H = A.size(),W = B.at(0).size();
vector<vector<T>> ret(H,vector<T>(W));
for(int i=0; i<H; i++) for(int k=0; k<W; k++){
for(int l=0; l<A.at(i).size(); l++){
ret.at(i).at(k) += A.at(i).at(l)*B.at(l).at(k);
}
}
return ret; //計算できる行列のみ.
}
template<typename T>
vector<vector<T>> Powmat(vector<vector<T>> A,vector<vector<T>> B,long long N){ //return A^N*B ABは行列;
//n*n行列A n*1行列Bと想定 O(n^3*logN).
assert(A.size() && A.size() == A.at(0).size() && N >= 0);
while(N){
if(N&1) B = multima(A,B);
A = multima(A,A); N >>= 1;
}
return B;
}
using SS = tuple<mint,mint,mint,mint>;
class SegmentTree{
public:
int siz = -1,n = -1;
vector<SS> dat;
SS op(SS a, SS b){
auto [a0,a1,a2,a3] = a;
auto [b0,b1,b2,b3] = b;
return {a0*b0+a1*b2,a0*b1+a1*b3,a2*b0+a3*b2,a2*b1+a3*b3};
}
SS e(){return {1,0,0,1};}
void renew (SS &a,SS x){
a = op(a,x);
//a = x; //set(pos,x)で可能.
//その他.
}
SegmentTree(int N){init(N);}
SegmentTree(const vector<SS> &A){//長さ配列サイズに合わせる.
siz = 1; n = A.size();
while(siz < n) siz *= 2;
dat.resize(siz*2,e());
for(int i=0; i<n; i++) dat.at(i+siz) = A.at(i);
for(int i=siz-1; i>0; i--) dat.at(i) = op(dat.at(i*2),dat.at(i*2+1));
}
void init(int N){
//全要素単位元に初期化.
siz = 1; n = N;
while(siz < n) siz *= 2;
dat.assign(siz*2,e());
}
void init(const vector<SS> &A){//長さ配列サイズに合わせる.
siz = 1; n = A.size();
while(siz < n) siz *= 2;
dat.resize(siz*2,e());
for(int i=0; i<n; i++) dat.at(i+siz) = A.at(i);
for(int i=siz-1; i>0; i--) dat.at(i) = op(dat.at(i*2),dat.at(i*2+1));
}
void set(int pos,SS x){
pos = pos+siz;
dat.at(pos) = x;
while(pos != 1){
pos = pos/2;
dat.at(pos) = op(dat.at(pos*2),dat.at(pos*2+1));
}
}
void update(int pos,SS x){
pos = pos+siz;
renew(dat.at(pos),x);
while(pos != 1){
pos = pos/2;
dat.at(pos) = op(dat.at(pos*2),dat.at(pos*2+1));
}
}
SS findans(int l, int r){
SS retl = e(),retr = e();
l += siz,r += siz;
while(l < r){
if(l&1) retl = op(retl,dat.at(l++));
if(r&1) retr = op(dat.at(--r),retr);
l >>= 1; r >>= 1;
}
return op(retl,retr);
}
SS get(int pos){return dat.at(pos+siz);}
SS rangeans(int l, int r){return findans(l,r);}
SS allrange(){return dat.at(1);}
//rightは) leftは[で 渡す&返す.
int maxright(const function<bool(SS)> f,int l = 0){
//fを満たさない最小の箇所を返す なければn.
l += siz; int r = n+siz;
vector<int> ls,rs;
while(l < r){
if(l&1) ls.push_back(l++);
if(r&1) rs.push_back(--r);
l >>= 1; r >>= 1;
}
SS okl = e();
for(int i=0; i<ls.size(); i++){
l = ls.at(i);
SS now = op(okl,dat.at(l));
if(!f(now)){
while(l < siz){
l <<= 1;
now = op(okl,dat.at(l));
if(f(now)){okl = now; l++;}
}
return l-siz;
}
okl = now;
}
for(int i=rs.size()-1; i>=0; i--){
l = rs.at(i);
SS now = op(okl,dat.at(l));
if(!f(now)){
while(l < siz){
l <<= 1;
now = op(okl,dat.at(l));
if(f(now)){okl = now; l++;}
}
return l-siz;
}
okl = now;
}
return n;
}
int minleft(const function<bool(SS)> f,int r = -1){
//fを満たす最小の箇所を返す なければ0.
if(r == -1) r = n;
int l = siz; r += siz;
vector<int> ls,rs;
while(l < r){
if(l&1) ls.push_back(l++);
if(r&1) rs.push_back(--r);
l >>= 1; r >>= 1;
}
SS okr = e();
for(int i=0; i<rs.size(); i++){
r = rs.at(i);
SS now = op(dat.at(r),okr);
if(!f(now)){
while(r < siz){
r <<= 1; r++;
now = op(dat.at(r),okr);
if(f(now)){okr = now; r--;}
}
return r+1-siz;
}
okr = now;
}
for(int i=ls.size()-1; i>=0; i--){
r = ls.at(i);
SS now = op(dat.at(r),okr);
if(!f(now)){
while(r < siz){
r <<= 1; r++;
now = op(dat.at(r),okr);
if(f(now)){okr = now; r--;}
}
return r+1-siz;
}
okr = now;
}
return 0;
}
};
int main(){
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int K,N; cin >> K >> N; mint::setmod(K);
vector<SS> give(N);
for(auto &[a,b,c,d] : give){
cin >> a.v >> b.v >> c.v >> d.v;
a.modu(),b.modu(),c.modu(),d.modu();
}
SegmentTree Z(give);
int Q; cin >> Q;
while(Q--){
int pos,l,r; cin >> pos >> l >> r; pos--,l--;
mint a,b,c,d; cin >> a.v >> b.v >> c.v >> d.v;
a.modu(),b.modu(),c.modu(),d.modu();
Z.set(pos,{a,b,c,d});
tie(a,b,c,d) = Z.rangeans(l,r);
cout << a.v << " " << b.v << "\n" << c.v << " " << d.v << "\n";
}
}