結果

問題 No.3239 Omnibus
コンテスト
ユーザー HoyHoyCharhang
提出日時 2025-08-15 23:41:01
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 667 ms / 10,000 ms
コード長 4,980 bytes
コンパイル時間 2,637 ms
コンパイル使用メモリ 282,740 KB
実行使用メモリ 31,488 KB
最終ジャッジ日時 2025-08-15 23:41:25
合計ジャッジ時間 18,239 ms
ジャッジサーバーID
（参考情報） 		judge6 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 33
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <bits/stdc++.h>
#define fi first
#define se second
#define rep(i,s,n) for (int i = (s); i < (n); ++i)
#define rrep(i,n,g) for (int i = (n)-1; i >= (g); --i)
#define all(a) a.begin(),a.end()
#define rall(a) a.rbegin(),a.rend()
#define len(x) (int)(x).size()
#define dup(x,y) (((x)+(y)-1)/(y))
#define pb push_back
#define eb emplace_back
#define Field(T) vector<vector<T>>
using namespace std;
using ll = long long;
using ull = unsigned long long;
template<typename T> using pq = priority_queue<T,vector<T>,greater<T>>;
using P = pair<int,int>;
template<class T>bool chmax(T&a,T b){if(a<b){a=b;return 1;}return 0;}
template<class T>bool chmin(T&a,T b){if(b<a){a=b;return 1;}return 0;}

template <typename S>
struct DynamicSegTree {
  struct Node {
    Node *l, *r;
    ll idx;
    S val, sum;
    Node(S val_, ll p) : l(nullptr), r(nullptr), idx(p), val(val_), sum(val_) {}
    void update() {
      sum = val;
      if (l) sum = l->sum + sum;
      if (r) sum = sum + r->sum;
    }
  };

  ll n;
  Node* root;
  const S e = S();

  DynamicSegTree(ll _n) : n(_n), root(nullptr) {}

  void set(ll p, S x) {
    _set(root, 0, n, p, x);
  }
  S get(ll p) {
    return _get(root, 0, n, p);
  }
  S prod(ll l, ll r) {
    return _prod(root, 0, n, l, r);
  }
  S all_prod() {
    if (!root) return e;
    else return root->sum;
  }

  ll max_right(ll l, const function<bool(S)> &f) {
    S x = e;
    return _max_right(root, 0, n, l, x, f);
  }

  ll min_left(ll r, const function<bool(S)> &f) {
    assert(r <= n);
    assert(f(e));
    S x = e;
    return _min_left(root, 0, n, r, x, f);
  }

 private:

  void _set(Node* &t, ll a, ll b, ll p, S x) {
    if (!t) {
      t = new Node(x, p);
      return;
    }
    if (p == t->idx) {
      t->val = x;
      t->update();
      return;
    }
    ll c = a + (b - a)/2;
    if (p < c) {
      if (t->idx < p) {
        swap(t->idx, p);
        swap(t->val, x);
      }
      _set(t->l, a, c, p, x);
    } else {
      if (t->idx > p) {
        swap(t->idx, p);
        swap(t->val, x);
      }
      _set(t->r, c, b, p, x);
    }
    t->update();
  }

  S _get(Node* &t, ll a, ll b, ll p) {
    if (!t) return e;
    if (p == t->idx) {
      return t->val;
    }
    ll c = a + (b - a)/2;
    if (p < c) {
      return _get(t->l, a, c, p);
    } else {
      return _get(t->r, c, b, p);
    }
  }

  S _prod(Node *&t, ll a, ll b, ll l, ll r) {
    if (!t || b <= l || r <= a) return e;
    if (l <= a && b <= r) return t->sum;
    ll c = a + (b - a)/2;
    return _prod(t->l, a, c, l, r) + ((l <= t->idx && t->idx < r) ? t->val : e) + _prod(t->r, c, b, l, r);
  }

  ll _max_right(Node *&t, ll a, ll b, ll l, S &x, const function<bool(S)> &f) const {
    if (!t || b <= l) return n;
    if (f(x + t->sum)) {
      x = x + t->sum;
      return n;
    }
    ll c = a + (b - a)/2;
    ll res = _max_right(t->l, a, c, l, x, f);
    if (res != n) return res;
    if (l <= t->idx) {
      x = x + t->val;
      if (!f(x)) return t->idx;
    }
    return _max_right(t->r, c, b, l, x, f);
  }

  ll _min_left(Node *&t, ll a, ll b, ll r, S &x, const function<bool(S)> &f) const {
    if (!t || r <= a) return 0;
    if (f(t->sum + x)) {
      x = t->sum + x;
      return 0;
    }
    ll c = a + (b - a)/2;
    ll res = _min_left(t->r, c, b, r, x, f);
    if (res != 0) return res;
    if (t->idx < r) {
      x = t->val + x;
      if (!f(x)) return t->idx + 1;
    }
    return _min_left(t->l, a, c, r, x, f);
  };
};

struct S {
  ll val; int cnt;
  S(): val(0), cnt(0) {}
  S(ll val, int cnt) : val(val), cnt(cnt) {}
  friend S operator+(S a, S b) {
    a.val += b.val, a.cnt += b.cnt;
    return a;
  }
};

int main() {
  int n, q;
  string s0;
  cin >> n >> q >> s0;
  vector<int> s(n);
  rep(i,0,n) s[i] = s0[i]-'a';
  int m = 17576;
  vector<DynamicSegTree<S>> seg(m, DynamicSegTree<S>(n));
  rep(i,0,n-2) {
    int val = s[i]*676+s[i+1]*26+s[i+2];
    seg[val].set(i, S{i, 1});
  }
  rep(i,0,q) {
    int t;
    cin >> t;
    if (t == 1) {
      int k; char c;
      cin >> k >> c;
      --k;
      int x = c-'a';
      if (k >= 2) {
        int val = s[k-2]*676+s[k-1]*26+s[k];
        seg[val].set(k-2, S());
        int nval = s[k-2]*676+s[k-1]*26+x;
        seg[nval].set(k-2, S(k-2, 1));
      }
      if (1 <= k && k < n-1) {
        int val = s[k-1]*676+s[k]*26+s[k+1];
        seg[val].set(k-1, S());
        int nval = s[k-1]*676+x*26+s[k+1];
        seg[nval].set(k-1, S(k-1, 1));
      }
      if (k < n-2) {
        int val = s[k]*676+s[k+1]*26+s[k+2];
        seg[val].set(k, S());
        int nval = x*676+s[k+1]*26+s[k+2];
        seg[nval].set(k, S(k, 1));
      }
      s[k] = x;
    } else {
      int l, r;
      string u;
      cin >> l >> r >> u;
      --l;
      if (r-l <= 2) {
        cout << 0 << endl;
        continue;
      }
      int a = (u[0]-'a')*676+(u[1]-'a')*26+(u[2]-'a');
      S p = seg[a].prod(l, r-2);
      ll ans = p.val-1LL*(l-1)*p.cnt;
      cout << ans << endl;
    }
  }
  return 0;
}
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