結果

問題 No.3250 最小公倍数
ユーザー GOTKAKO
提出日時 2025-08-29 22:45:55
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 1,752 ms / 2,000 ms
コード長 5,708 bytes
コンパイル時間 2,765 ms
コンパイル使用メモリ 214,744 KB
実行使用メモリ 120,528 KB
最終ジャッジ日時 2025-08-29 22:46:35
合計ジャッジ時間 26,567 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 21
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;

//入力が必ず-mod<a<modの時.
template<const int mod>
struct modint{ //mod変更が不可能.
    public:
    long long v = 0;
    static void setmod(int m){} //飾り.
    static constexpr long long getmod(){return mod;}
    modint(){v = 0;} modint(int a){v = a<0?a+mod:a;} modint(long long a){v = a<0?a+mod:a;}
    modint(unsigned int a){v = a;} modint(unsigned long long a){v = a;}
    long long val()const{return v;}
 
    modint &operator=(const modint &b) = default;
    modint operator+()const{return (*this);}
    modint operator-()const{return modint(0)-(*this);}
    modint operator+(const modint b)const{return modint(v)+=b;}
    modint operator-(const modint b)const{return modint(v)-=b;}
    modint operator*(const modint b)const{return modint(v)*=b;}
    modint operator/(const modint b)const{return modint(v)/=b;}
    modint operator+=(const modint b){
        v += b.v; if(v >= mod) v -= mod;
        return *this;
    }
    modint operator-=(const modint b){
        v -= b.v; if(v < 0) v += mod; 
        return *this;
    }   
    modint operator*=(const modint b){v = v*b.v%mod; return *this;}
    modint operator/=(modint b){ //b!=0 mod素数が必須.
        if(b == 0) assert(false);
        int left = mod-2;
        while(left){if(left&1) *this *= b; b *= b; left >>= 1;}
        return *this;
    }
    modint operator++(){*this += 1; return *this;}
    modint operator--(){*this -= 1; return *this;}
    modint operator++(int){*this += 1; return *this;}
    modint operator--(int){*this -= 1; return *this;}
    bool operator==(const modint b)const{return v == b.v;}
    bool operator!=(const modint b)const{return v != b.v;}
    bool operator>(const modint b)const{return v > b.v;}
    bool operator>=(const modint b)const{return v >= b.v;}
    bool operator<(const modint b)const{return v < b.v;}
    bool operator<=(const modint b)const{return v <= b.v;}
    modint pow(long long n)const{
        modint ret = 1,p = v;
        if(n < 0) p = p.inv(),n = -n;
        while(n){
            if(n&1) ret *= p;
            p *= p; n >>= 1;
        }
        return ret;
    }
    modint inv()const{return modint(1)/v;} //素数mod必須.
};
using mint = modint<998244353>; const long long mod = 998244353;

int main(){
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);

    int Limit = 1001001; //Limit->必要なサイズ fac->x! facinv->1/x! inv->1/x.

    vector<mint> inv(Limit+1); inv.at(1) = 1;
    for(int i=2; i<=Limit; i++) inv.at(i) = (-(mod/i)*inv.at(mod%i).v%mod+mod)%mod;

    int Need = 1001001;
    vector<vector<pair<int,int>>> Pf(Need+1);
    vector<bool> prime(Need+1,true);
    prime.at(0) = false; prime.at(1) = false;
    for(int i=2; i<=Need; i++){
        if(!prime.at(i)) continue;
        Pf.at(i) = {{i,i}};
        for(int k=i+i; k<=Need; k+=i){
            prime.at(k) = false;
            int f = 1,k2 = k;
            while(k2%i == 0) f *= i,k2 /= i;
            Pf.at(k).push_back({i,f});
        }
    }

    int N; cin >> N;
    vector<int> A(N);
    for(auto &a : A) cin >> a;
    vector<vector<int>> Graph(N);
    for(int i=0; i<N-1; i++){
        int u,v; cin >> u >> v;
        u--; v--;
        Graph.at(u).push_back(v);
        Graph.at(v).push_back(u);
    }
    {
        vector<int> siz(N);
        auto dfs = [&](auto dfs,int pos,int back) -> int {
            int ret = 1;
            for(auto to : Graph.at(pos)) if(to != back) ret += dfs(dfs,to,pos);
            siz.at(pos) = ret;
            return ret;
        };
        dfs(dfs,0,-1);
        for(auto &g : Graph) sort(g.begin(),g.end(),[&](auto a,auto b){return siz.at(a)>siz.at(b);});
    }

    vector<mint> answer(N);
    {
        vector<int> T(1001001,0);
        vector<int> best(1001001,1);
        mint now = 1;
        int time = 0,reset = -1;
        auto dfs = [&](auto dfs,int pos,int back,bool leader) -> void {
            int big = -1;
            for(auto to : Graph.at(pos)){
                if(to == back) continue;
                big = to; break;
            }
            for(auto to : Graph.at(pos)){
                if(to == back || to == big) continue;
                dfs(dfs,to,pos,false);
            }
            if(big != -1) dfs(dfs,big,pos,true);
            {
                auto dfs2 = [&](auto dfs2,int po,int ba) -> void {
                    for(auto [p,v] : Pf.at(A.at(po))){
                        if(T.at(p) <= reset){
                            T.at(p) = time;
                            now *= v;
                            best.at(p) = v;
                        }
                        else if(best.at(p) < v){
                            now *= inv.at(best.at(p));
                            now *= v;
                            best.at(p) = v;
                        }
                    }
                    for(auto to : Graph.at(po)) if(to != ba) dfs2(dfs2,to,po);
                };
                for(auto to : Graph.at(pos)){
                    if(to == back || to == big) continue;
                    dfs2(dfs2,to,pos);
                }
            }
            for(auto [p,v] : Pf.at(A.at(pos))){
                if(T.at(p) <= reset){
                    T.at(p) = time;
                    now *= v;
                    best.at(p) = v;
                }
                else if(best.at(p) < v){
                    now *= inv.at(best.at(p));
                    now *= v;
                    best.at(p) = v;
                }
            }

            answer.at(pos) = now;
            if(!leader){
                now = 1,reset = time++;
            }
        };
        dfs(dfs,0,-1,true);
    }
    for(auto &a : answer) cout << a.v << "\n";
}
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