結果
| 問題 |
No.3250 最小公倍数
|
| コンテスト | |
| ユーザー |
mkawa2
|
| 提出日時 | 2025-09-02 14:41:04 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 4,825 bytes |
| コンパイル時間 | 545 ms |
| コンパイル使用メモリ | 82,568 KB |
| 実行使用メモリ | 310,332 KB |
| 最終ジャッジ日時 | 2025-10-16 17:09:09 |
| 合計ジャッジ時間 | 6,066 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 5 TLE * 1 -- * 16 |
ソースコード
import sys
# sys.setrecursionlimit(200005)
# sys.set_int_max_str_digits(200005)
int1 = lambda x: int(x)-1
pDB = lambda *x: print(*x, end="\n", file=sys.stderr)
p2D = lambda x: print(*x, sep="\n", end="\n\n", file=sys.stderr)
def II(): return int(sys.stdin.readline())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LI1(): return list(map(int1, sys.stdin.readline().split()))
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def SI(): return sys.stdin.readline().rstrip()
dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
# inf = -1-(-1 << 31)
inf = -1-(-1 << 62)
# md = 10**9+7
md = 998244353
from collections import defaultdict
class Sieve:
def __init__(self, n):
self.plist = [2]
min_prime_factor = [2, 0]*(n//2+1)
for x in range(3, n+1, 2):
if min_prime_factor[x] == 0:
min_prime_factor[x] = x
self.plist.append(x)
if x**2 > n: continue
for y in range(x**2, n+1, 2*x):
if min_prime_factor[y] == 0:
min_prime_factor[y] = x
self.min_prime_factor = min_prime_factor
def isprime(self, x):
return self.min_prime_factor[x] == x
def pf(self, x):
pp, ee = [], []
while x > 1:
mpf = self.min_prime_factor[x]
if pp and mpf == pp[-1]:
ee[-1] += 1
else:
pp.append(mpf)
ee.append(1)
x //= mpf
return pp, ee
# unsorted
def factor(self, a):
ff = [1]
pp, ee = self.pf(a)
for p, e in zip(pp, ee):
ff, gg = [], ff
w = p
for _ in range(e):
for f in gg: ff.append(f*w)
w *= p
ff += gg
return ff
sv=Sieve(10**6)
class LCA:
def __init__(self, parent, depth):
n = len(parent)
self._depth = depth
log = max(self._depth).bit_length()
self._table = [parent]+[[-1]*n for _ in range(log)]
t0 = self._table[0]
for lv in range(log):
t1 = self._table[lv+1]
for u in range(n):
if t0[u] == -1: continue
t1[u] = t0[t0[u]]
t0 = t1
def anc(self, u, v):
diff = self._depth[u]-self._depth[v]
if diff < 0: u, v = v, u
diff = abs(diff)
u = self.up(u, diff)
if u == v: return u
for lv in range(self._depth[u].bit_length()-1, -1, -1):
tl = self._table[lv]
if tl[u] != tl[v]: u, v = tl[u], tl[v]
return self._table[0][u]
def up(self, u, dist):
lv = 0
while dist and u != -1:
if dist & 1: u = self._table[lv][u]
lv, dist = lv+1, dist >> 1
return u
n=II()
aa=LI()
to=[[] for _ in range(n)]
for _ in range(n-1):
u,v=LI1()
to[u].append(v)
to[v].append(u)
def dfs(root=0):
uu = []
stack = [root]
while stack:
u = stack.pop()
if dfsOrder[u] == -1:
dfsOrder[u] = len(uu)
utoi[u] = len(eulerTour)
eulerTour.append(u)
uu.append(u)
if u != root: stack.append(u)
# !!! to's format
for v in to[u]:
if v == parent[u]: continue
depth[v] = depth[u]+1
parent[v] = u
stack.append(v)
else:
right[u] = len(uu)
eulerTour.append(parent[u])
right[root] = len(uu)
return uu
eulerTour, utoi = [], [0]*n
right = [-1]*n # left = dfsOrder
parent, depth, dfsOrder = [-1]*n, [0]*n, [-1]*n
uu=dfs()
lca=LCA(parent,depth)
p2u=defaultdict(list)
pu2e={}
for u in uu:
pp,ee=sv.pf(aa[u])
for p,e in zip(pp,ee):
p2u[p].append(u)
pu2e[p,u]=e
ans=[1]*n
def auxiliary_tree(vv0,p):
if len(vv0)==1:
v=vv0[0]
ans[v]=ans[v]*pow(p,pu2e[p,v],md)%md
return
st = set(vv0)
for i in range(len(vv0)-1): st.add(lca.anc(vv0[i], vv0[i+1]))
vv = sorted(st, key=lambda x: dfsOrder[x])
stack = [vv[0]]
par = {}
for u in vv[1:]:
while right[stack[-1]] <= dfsOrder[u]: stack.pop()
par[u] = stack[-1]
stack.append(u)
mx=defaultdict(int)
sm=defaultdict(int)
for v in vv[::-1]:
if (p,v) in pu2e:mx[v]=max(mx[v],pu2e[p,v])
sm[v]+=mx[v]
ans[v]=ans[v]*pow(p,sm[v],md)%md
if v in par:
u=par[v]
mx[u]=max(mx[u],mx[v])
sm[u]-=mx[v]
for p in p2u:
auxiliary_tree(p2u[p],p)
for u in uu[:0:-1]:
v=parent[u]
ans[v]=ans[u]*ans[v]%md
print(*ans,sep="\n")
mkawa2