結果
問題 |
No.3269 Leq-K Partition
|
ユーザー |
![]() |
提出日時 | 2025-09-20 02:28:17 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 4,688 bytes |
コンパイル時間 | 3,479 ms |
コンパイル使用メモリ | 183,664 KB |
実行使用メモリ | 7,716 KB |
最終ジャッジ日時 | 2025-09-20 02:30:06 |
合計ジャッジ時間 | 95,125 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 22 WA * 5 |
ソースコード
#include <algorithm> #include <atcoder/all> #include <bitset> #include <cassert> #include <cmath> #include <ctime> #include <functional> #include <iomanip> #include <iostream> #include <map> #include <queue> #include <random> #include <set> #include <stack> #include <string> #include <tuple> #include <unordered_map> #include <unordered_set> #include <utility> #include <vector> using namespace std; using namespace atcoder; typedef long long ll; #define rep(i, n) for (int i = 0; i < (int)(n); i++) #define repr(i, n) for (int i = (int)(n) - 1; i >= 0; i--) #define repk(i, k, n) for (int i = k; i < (int)(n); i++) #define all(v) v.begin(), v.end() #define mod1 1000000007 #define mod2 998244353 #define mod3 100000007 #define vi vector<int> #define vs vector<string> #define vc vector<char> #define vl vector<ll> #define vb vector<bool> #define vvi vector<vector<int>> #define vvc vector<vector<char>> #define vvl vector<vector<ll>> #define vvb vector<vector<bool>> #define vvvi vector<vector<vector<int>>> #define vvvl vector<vector<vector<ll>>> #define pii pair<int, int> #define pil pair<int, ll> #define pli pair<ll, int> #define pll pair<ll, ll> #define vpii vector<pair<int, int>> #define vpll vector<pair<ll, ll>> #define vvpii vector<vector<pair<int, int>>> #define vvpll vector<vector<pair<ll, ll>>> template <typename T> void debug(T e) { cerr << e << endl; } template <typename T> void debug(vector<T> &v) { rep(i, v.size()) { cerr << v[i] << " "; } cerr << endl; } template <typename T> void debug(vector<vector<T>> &v) { rep(i, v.size()) { rep(j, v[i].size()) { cerr << v[i][j] << " "; } cerr << endl; } } template <typename T> void debug(vector<pair<T, T>> &v) { rep(i, v.size()) { cerr << v[i].first << " " << v[i].second << endl; } } template <typename T> void debug(set<T> &st) { for (auto itr = st.begin(); itr != st.end(); itr++) { cerr << *itr << " "; } cerr << endl; } template <typename T> void debug(multiset<T> &ms) { for (auto itr = ms.begin(); itr != ms.end(); itr++) { cerr << *itr << " "; } cerr << endl; } template <typename T> void debug(map<T, T> &mp) { for (auto itr = mp.begin(); itr != mp.end(); itr++) { cerr << itr->first << " " << itr->second << endl; } } void debug_out() { cerr << endl; } template <typename Head, typename... Tail> void debug_out(Head H, Tail... T) { cerr << H << " "; debug_out(T...); } using mint = modint998244353; void debug_mint1(vector<mint> &vec) { for (int i = 0; i < vec.size(); i++) { cerr << vec[i].val() << " "; } cerr << endl; } void debug_mint2(vector<vector<mint>> &vec) { for (int i = 0; i < vec.size(); i++) { for (int j = 0; j < vec[i].size(); j++) { cerr << vec[i][j].val() << " "; } cerr << endl; } } ll solve(ll N, vector<ll> &A, ll k){ vector<ll> dp(N + 1, N + 3); vector<ll> cnts(N, 0); dp[0] = 0; ll left = 0; ll right = 0; ll kind = 0; while (left < N){ if (right == N){ cnts[A[left]]--; if (cnts[A[left]] == 0){ kind--; } left++; } else if (kind <= k){ if (cnts[A[right]] == 0){ kind++; } cnts[A[right]]++; right++; } else{ cnts[A[left]]--; if (cnts[A[left]] == 0){ kind--; } left++; } if (kind <= k){ dp[right] = min(dp[right], dp[left] + 1); } } return dp[N]; } int main(){ ll N; cin >> N; vector<ll> A(N); for (ll i = 0; i < N; i++){ cin >> A[i]; A[i]--; } ll INF = 10000000000023; vector<ll> cnts(N, 0); ll B = 1500; for (ll i = 1; i <= min(B, N); i++){ // 尺取り法 + dp cout << solve(N, A, i) << endl; } vector<ll> min_kind(N / B + 2); min_kind[0] = N + 1; for (ll i = 1; i <= N / B + 1; i++){ // 答えが i になる種類数の最大値を求めよう ll ok = 0; ll ng = N + 1; while (ng - ok > 1){ ll mid = (ok + ng) / 2; if (solve(N, A, mid) >= i){ ok = mid; } else{ ng = mid; } } min_kind[i] = ok; } // debug(min_kind); vector<ll> ans(N + 1); for (ll i = N / B; i >= 1; i--){ for (ll j = min_kind[i + 1] + 1; j <= min_kind[i]; j++){ ans[j] = i; } } for (ll i = B + 1; i <= N; i++){ cout << ans[i] << endl; } }