結果
問題 |
No.3283 Labyrinth and Friends
|
ユーザー |
👑 |
提出日時 | 2025-09-26 22:41:04 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 3,186 bytes |
コンパイル時間 | 3,985 ms |
コンパイル使用メモリ | 255,460 KB |
実行使用メモリ | 7,720 KB |
最終ジャッジ日時 | 2025-09-26 22:41:10 |
合計ジャッジ時間 | 5,753 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | WA * 2 |
other | WA * 45 |
ソースコード
#include<bits/stdc++.h> #include<atcoder/all> #define rep(i,n) for(int i=0;i<n;i++) using namespace std; using namespace atcoder; typedef long long ll; typedef pair<int, int> P; template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;} template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;} template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;} template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;} template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;} template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;} template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;} template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;} template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;} template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;} template<typename T> void chmin(T& a, T b){a = min(a, b);} template<typename T> void chmax(T& a, T b){a = max(a, b);} const long long INF = 1001001001001001; int main(){ int n, x; cin >> n >> x; vector<vector<int>> children(n); for(int i = 1; i < n; i++){ int p; cin >> p; p--; children[p].push_back(i); } vector<long long> c(n); vector<int> s(n); for(int i = 1; i < n; i++) cin >> c[i] >> s[i]; auto solve = [&](int from, auto solve) -> vector<long long>{ vector<long long> dp = {0LL}; for(auto to : children[from]){ auto ep = solve(to, solve); vector<long long> dp_new(dp.size() + ep.size() - 1, 0LL); for(int i = 0; i < int(dp.size()); i++){ for(int j = 0; j < int(ep.size()); j++){ chmax(dp_new[i + j], dp[i] + ep[j]); } } swap(dp, dp_new); } { vector<long long> dp_new(dp.size() + s[from], 0); for(int i = 0; i < int(dp.size()); i++){ dp_new[i + s[from]] = dp[i] + c[from]; } dp_new[0] = 0; swap(dp, dp_new); } return dp; }; auto dp = solve(0, solve); long long ans = INF; for(int i = x; i <= int(dp.size()); i++){ chmin(ans, (long long)i); } cout << ans << "\n"; cerr << dp; return 0; }