結果

問題 No.3316 Make 81181819 with only 0,1,or 8
コンテスト
ユーザー 👑 binap
提出日時 2025-10-31 23:24:59
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 3,767 bytes
コンパイル時間 3,869 ms
コンパイル使用メモリ 259,948 KB
実行使用メモリ 7,720 KB
最終ジャッジ日時 2025-10-31 23:25:07
合計ジャッジ時間 7,151 ms
ジャッジサーバーID
（参考情報） 		judge4 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 5 WA * 17
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
using namespace atcoder;
typedef long long ll;
typedef pair<int, int> P;

template <int m> ostream& operator<<(ostream& os, const static_modint<m>& a) {os << a.val(); return os;}
template <int m> ostream& operator<<(ostream& os, const dynamic_modint<m>& a) {os << a.val(); return os;}
template <int m> istream& operator>>(istream& is, static_modint<m>& a) {long long x; is >> x; a = x; return is;}
template <int m> istream& operator>>(istream& is, dynamic_modint<m>& a) {long long x; is >> x; a = x; return is;}
template<typename T> istream& operator>>(istream& is, vector<T>& v){int n = v.size(); assert(n > 0); rep(i, n) is >> v[i]; return is;}
template<typename U, typename T> ostream& operator<<(ostream& os, const pair<U, T>& p){os << p.first << ' ' << p.second; return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<T>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : " "); return os;}
template<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v){int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? "\n" : ""); return os;}
template<typename T> ostream& operator<<(ostream& os, const set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename T> ostream& operator<<(ostream& os, const unordered_set<T>& se){for(T x : se) os << x << " "; os << "\n"; return os;}
template<typename S, auto op, auto e> ostream& operator<<(ostream& os, const atcoder::segtree<S, op, e>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}
template<typename S, auto op, auto e, typename F, auto mapping, auto composition, auto id> ostream& operator<<(ostream& os, const atcoder::lazy_segtree<S, op, e, F, mapping, composition, id>& seg){int n = seg.max_right(0, [](S){return true;}); rep(i, n) os << seg.get(i) << (i == n - 1 ? "\n" : " "); return os;}

template<typename T> void chmin(T& a, T b){a = min(a, b);}
template<typename T> void chmax(T& a, T b){a = max(a, b);}

const int K = 10;
const int INF = 1001001001;

using T = tuple<int, int, int>;

int solve(){
	int n;
	cin >> n;
	vector<int> dig(K);
	
	n = 81181819 - n;
	
	rep(i, K){
		dig[(K - 1) - i] = n % 10;
		n /= 10;
	}
	
	vector<vector<T>> dp(K + 1, vector<T>(10, make_tuple(INF, INF, INF)));
	dp[0][0] = T{0, 0, 0};
	
	vector<pair<int, int>> memo(100, make_pair(INF, INF));
	for(int one = 0; one <= 7; one++){
		for(int eight = 0; eight <= 7; eight++){
			int sum = one * 1 + eight * 8;
			if(one + eight < memo[sum].first + memo[sum].second){
				memo[sum] = make_pair(one, eight);
			}
		}
	}
	rep(i, K){
		for(int down = 0; down < 10; down++){
			int rest = down * 10 + dig[i];
			auto [val1, one1, eight1] = dp[i][down];
			for(int minus = 0; minus < 100; minus++){
				auto [one, eight] = memo[minus];
				int val_new = max(val1, one +  eight);
				if(0 <= rest - minus and rest - minus < 10){
					auto [val2, one2, eight2] = dp[i + 1][rest - minus];
					if(val_new < val2){
						dp[i + 1][rest - minus] = T{val_new, one, eight};
					}
				}
			}
		}
	}
	{
		vector<int> ans;
		{
			auto [val, one, eight] = dp[K][0];
			ans.resize(val);
		}
		int ten = 1;
		int down = 0;
		for(int i = K; i > 0; i--){
			auto [val, one, eight] = dp[i][down];
			int j = 0;
			rep(_, one){
				ans[j] += 1 * ten;
				j++;
			}
			rep(_, eight){
				ans[j] += 8 * ten;
				j++;
			}
			ten *= 10;
			down = (one * 1 + eight * 8) / 10;
//			cout << ans;
//			cout << down << "\n";
//			flush(cout);
		}
		cout << ans.size() << "\n";
		for(auto x : ans){
			cout << x << "\n";
		}
	}
	return 0;
}

int main(){
	int t;
	cin >> t;
	rep(_, t) solve();
	return 0;
}
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