結果
| 問題 | No.3436 [Cherry 8th Tune B] この夏に何が起こるかな? |
| コンテスト | |
| ユーザー |
mkawa2
|
| 提出日時 | 2026-01-23 22:25:44 |
| 言語 | PyPy3 (7.3.17) |
| 結果 |
AC
|
| 実行時間 | 2,041 ms / 4,000 ms |
| コード長 | 2,199 bytes |
| 記録 | |
| コンパイル時間 | 220 ms |
| コンパイル使用メモリ | 82,544 KB |
| 実行使用メモリ | 115,144 KB |
| 最終ジャッジ日時 | 2026-01-23 22:30:09 |
| 合計ジャッジ時間 | 57,542 ms |
|
ジャッジサーバーID (参考情報) |
judge6 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 43 |
ソースコード
import sys
# sys.setrecursionlimit(200005)
# sys.set_int_max_str_digits(200005)
int1 = lambda x: int(x)-1
pDB = lambda *x: print(*x, end="\n", file=sys.stderr)
p2D = lambda x: print(*x, sep="\n", end="\n\n", file=sys.stderr)
def II(): return int(sys.stdin.readline())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LI1(): return list(map(int1, sys.stdin.readline().split()))
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def SI(): return sys.stdin.readline().rstrip()
dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
# inf = -1-(-1 << 31)
inf = -1-(-1 << 62)
# md = 10**9+7
md = 998244353
from bisect import *
from collections import defaultdict
def solve():
def binary_search(l, r, minimize):
if minimize: l -= 1
else: r += 1
while l+1 < r:
m = (l+r)//2
if ok(m) ^ minimize: l = m
else: r = m
if minimize: return r
return l
def ok(m):
s = 0
for t, c in zip(tt, cc):
i = bisect(sb, m-t)
ij = bisect(d2b[c], m-t)
j = bisect(d2b[c], m-t+ss[c])
s += i+j-ij
if s >= p: return True
return False
n, m, k, p = LI()
tt = LI()
cc = LI1()
bb = LI()
dd = LI1()
ss = LI()
rev = 0
if n > m:
rev = 1
n, m = m, n
tt, bb = bb, tt
cc, dd = dd, cc
d2b = [[] for _ in range(k)]
for b, d in zip(bb, dd): d2b[d].append(b)
for d in range(k): d2b[d].sort()
sb = sorted(bb)
x = binary_search(0, 2000000000, True)
# print(x)
if rev:
n, m = m, n
tt, bb = bb, tt
cc, dd = dd, cc
b2j = defaultdict(list)
for j, b in enumerate(bb): b2j[b].append(j)
for i in range(n):
t, c = tt[i], cc[i]
for j in b2j[x-t]:
if dd[j] != c:
print(i+1, j+1)
return
for j in b2j[x-t+ss[c]]:
if dd[j] == c:
print(i+1, j+1)
return
for _ in range(II()): solve()
mkawa2