結果
| 問題 | No.3461 Min GCD |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2026-02-28 14:23:11 |
| 言語 | PyPy3 (7.3.17) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 2,557 bytes |
| 記録 | |
| コンパイル時間 | 343 ms |
| コンパイル使用メモリ | 78,468 KB |
| 実行使用メモリ | 114,860 KB |
| 最終ジャッジ日時 | 2026-02-28 14:23:31 |
| 合計ジャッジ時間 | 12,533 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge7 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 18 TLE * 1 -- * 2 |
ソースコード
def sieves(nn: int):
is_prime = [True] * nn
least_p = [-1] * nn
is_prime[0] = is_prime[1] = False
least_p[1] = 1
mobius = [1] * nn
mobius[0] = 0
for p in range(2, nn):
if not is_prime[p]:
continue
least_p[p] = p
mobius[p] = -1
for q in range(p * 2, nn, p):
is_prime[q] = False
if least_p[q] == -1:
least_p[q] = p
if q % (p * p) == 0:
mobius[q] = 0
else:
mobius[q] *= -1
primes = [p for p in range(2, nn) if is_prime[p]]
return is_prime, least_p, primes, mobius
def prime_factorize(n: int):
ans = {}
while n > 1:
p = least_p[n]
e = 0
while n % p == 0:
n //= p
e += 1
ans[p] = e
return ans
def get_divisors(n: int):
"""正の約数列挙
Args:
n (int): 約数を求める数 (>= 1)
Returns:
list[int]: `n`の正の約数
Notes:
- `n`の約数の個数をσ(n)として
- 計算量 Θ( σ(n) * log(σ(n)) )
- n <= 10^7 で σ(n) <= σ(8648640) = 448
- n <= 10^9 で σ(n) <= σ(735134400) = 1344
- n <= 10^18 で σ(n) <= σ(897612484786617600) = 103680
"""
pe = prime_factorize(n)
ans = [1]
for p, e in pe.items():
exps = [p ** ei for ei in range(1, e + 1)]
ans.extend([d * f for d in ans for f in exps])
ans.sort()
return ans
is_prime, least_p, primes, mobius = sieves(10**5 + 100)
from collections import defaultdict
n, k = map(lambda s_: int(s_), input().split())
a = tuple(map(lambda s_: int(s_), input().split()))
b = tuple(map(lambda s_: int(s_), input().split()))
cost = [[] for _ in range(n)]
for i in range(n):
ai, bi = a[i], b[i]
ci = cost[i]
ds = get_divisors(ai)
dcd = defaultdict(int)
for d in ds:
dcd[(bi + d - 1) // d * d - bi] = d
for c, d in sorted(dcd.items()):
if ci and ci[-1][0] > d:
continue
else:
ci.append((d, c))
import bisect
# for ci in cost:
# print(ci)
def check(g):
ans = 0
for ci in cost:
i = bisect.bisect_left(ci, (g, 0))
if i == len(ci):
# print(">>", ci, g, i)
return False
ans += ci[i][1]
# print(">", g, ": ", ans)
return ans <= k
ok = 0
ng = min(a) + 1
while abs(ok - ng) > 1:
mi = (ok + ng) // 2
if check(mi):
ok = mi
else:
ng = mi
print(ok)
# for i in range(1, 10):
# print(check(i))