結果
| 問題 | No.8133 Reversed |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2026-04-01 23:10:23 |
| 言語 | C++17 (gcc 15.2.0 + boost 1.89.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 4,726 bytes |
| 記録 | |
| コンパイル時間 | 2,022 ms |
| コンパイル使用メモリ | 221,276 KB |
| 実行使用メモリ | 229,116 KB |
| 最終ジャッジ日時 | 2026-04-01 23:10:31 |
| 合計ジャッジ時間 | 4,265 ms |
|
ジャッジサーバーID (参考情報) |
judge4_1 / judge1_1 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | WA * 1 |
| other | WA * 6 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
//入力が必ず-mod<=a<modの時.
template<const long long mod> //mod<2^30.
struct modint{ //mod変更が不可能.
public:
long long v;
static void setmod(long long m){} //飾り.
static constexpr long long getmod(){return mod;}
modint():v(0){}
template<typename T>
modint(T a):v(a){if(v < 0) v += mod;}
long long val()const{return v;}
modint &operator=(const modint &b) = default;
modint &operator+()const{return (*this);}
modint operator-()const{return modint(0)-(*this);}
modint operator+(const modint b)const{return modint(v)+=b;}
modint operator-(const modint b)const{return modint(v)-=b;}
modint operator*(const modint b)const{return modint(v)*=b;}
modint operator/(const modint b)const{return modint(v)/=b;}
modint &operator+=(const modint b){
v += b.v; if(v >= mod) v -= mod;
return *this;
}
modint &operator-=(const modint b){
v -= b.v; if(v < 0) v += mod;
return *this;
}
modint &operator*=(const modint b){v = (__int128_t)v*b.v%mod; return *this;}
modint &operator/=(modint b){ //b!=0 mod素数が必須.
assert(b.v != 0);
(*this) *= b.pow(mod-2);
return *this;
}
modint pow(long long n)const{
modint ret = 1,p = v;
if(n < 0) p = p.inv(),n = -n;
while(n){
if(n&1) ret *= p;
p *= p; n >>= 1;
}
return ret;
}
modint inv()const{return pow(mod-2);} //素数mod必須.
modint &operator++(){*this += 1; return *this;}
modint &operator--(){*this -= 1; return *this;}
modint operator++(int){modint ret = *this; *this += 1; return ret;}
modint operator--(int){modint ret = *this; *this -= 1; return ret;}
friend bool operator==(const modint a,const modint b){return a.v==b.v;}
friend bool operator!=(const modint a,const modint b){return a.v!=b.v;}
friend bool operator<(const modint a,const modint b){return a.v<b.v;}
friend bool operator<=(const modint a,const modint b){return a.v<=b.v;}
friend bool operator>=(const modint a,const modint b){return a.v>=b.v;}
friend bool operator>(const modint a,const modint b){return a.v>b.v;}
friend ostream &operator<<(ostream &os,const modint a){return os<<a.v;}
friend istream &operator>>(istream &is,modint &a){ //入力はmodをとってくれる.
long long x; is >> x; x %= mod;
a = modint(x); return is;
}
};
using mint = modint<7'000'000'001LL>; const long long mod = 7'000'000'001LL;
int main(){
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
vector<bool> already(20);
vector<mint> memo(20);
auto all = [&](long long d) -> mint {
if(already.at(d)) return memo.at(d);
already.at(d) = true;
long long p10 = 1;
for(int i=0; i<d; i++) p10 *= 10;
memo.at(d) = mint(p10/2%mod)*mint((p10-1)%mod);
return memo.at(d);
};
auto f = [&](long long x) -> mint {
auto dfs = [&](auto dfs,int digit,long long p10,long long left,bool zero = false) -> mint {
mint ret = 0;
int d = 1;
if(zero) d = 0;
while(left >= p10 && d < 10){
ret += (p10%mod*d)%mod;
ret += all(digit)*10;
left -= p10,d++;
}
if(d == 10) ret += dfs(dfs,digit+1,p10*10,left);
else if(left){
ret += (left%mod*d)%mod;
ret += dfs(dfs,digit-1,p10/10,left,true)*10;
}
return ret;
};
return dfs(dfs,0,1,x);
};
auto Get = [&](string S) -> long long {
long long ret = 0;
while(S.size()){
char c = S.back(); S.pop_back();
if('0' <= c && c <= '9') ret *= 10,ret += c-'0';
}
return ret;
};
auto Get2 = [&](string S) -> pair<long long,long long> {
long long L = 0,R = 0;
bool isL = true;
for(auto c : S){
if('0' <= c && c <= '9'){
if(isL) L *= 10,L += c-'0';
else R *= 10,R += c-'0';
}
else if(c == ' ') isL = false;
}
return {L,R};
};
string S; cin >> S;
const string rev = "\xE2\x80\xAE";
const char* Rev = "\xE2\x80\xAE";
auto delrev = [&]() -> void {
if(S.rfind(rev,0) == 0) S.erase(0,rev.size());
};
getline(cin,S);
delrev();
while(getline(cin,S)){
delrev();
auto [L,R] = Get2(S);
mint small = f(L-1),big = f(R);
long long v = (big-small).v;
string answer = to_string(v)+'\n';
cout << Rev << answer;
}
}