結果

問題 No.453 製薬会社
コンテスト
ユーザー lmori
提出日時 2026-04-25 02:42:20
言語 C++23
(gcc 15.2.0 + boost 1.89.0)
コンパイル:
g++-15 -O2 -lm -std=c++23 -Wuninitialized -DONLINE_JUDGE -o a.out _filename_
実行:
./a.out
結果
AC  
実行時間 3 ms / 2,000 ms
コード長 6,677 bytes
記録
記録タグの例:
初AC ショートコード 純ショートコード 純主流ショートコード 最速実行時間
コンパイル時間 4,530 ms
コンパイル使用メモリ 381,544 KB
実行使用メモリ 6,400 KB
最終ジャッジ日時 2026-04-25 02:42:26
合計ジャッジ時間 5,548 ms
ジャッジサーバーID
(参考情報)
judge2_0 / judge3_0
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 4
other AC * 9
権限があれば一括ダウンロードができます

ソースコード

diff #
raw source code

#include <bits/stdc++.h>

#include <atcoder/all>
using namespace std;
using namespace atcoder;
using lint = long long;
using mint = modint998244353;
using ull = unsigned long long;
using ld = long double;
using int128 = __int128_t;
#define all(x) (x).begin(), (x).end()
#define EPS 1e-10
#define uniqv(v) v.erase(unique(all(v)), v.end())
#define OVERLOAD_REP(_1, _2, _3, name, ...) name
#define REP1(i, n) for (auto i = std::decay_t<decltype(n)>{}; (i) < (n); ++(i))
#define REP2(i, l, r) for (auto i = (l); (i) < (r); ++(i))
#define rep(...) OVERLOAD_REP(__VA_ARGS__, REP2, REP1)(__VA_ARGS__)
#define log(x) cout << x << endl
#define logfixed(x) cout << fixed << setprecision(10) << x << endl;
#define logy(bool)         \
  if (bool) {              \
    cout << "Yes" << endl; \
  } else {                 \
    cout << "No" << endl;  \
  }

ostream& operator<<(ostream& dest, __int128_t value) {
  ostream::sentry s(dest);
  if (s) {
    __uint128_t tmp = value < 0 ? -value : value;
    char buffer[128];
    char* d = end(buffer);
    do {
      --d;
      *d = "0123456789"[tmp % 10];
      tmp /= 10;
    } while (tmp != 0);
    if (value < 0) {
      --d;
      *d = '-';
    }
    int len = end(buffer) - d;
    if (dest.rdbuf()->sputn(d, len) != len) {
      dest.setstate(ios_base::badbit);
    }
  }
  return dest;
}

template <typename T>
ostream& operator<<(ostream& os, const vector<T>& v) {
  for (int i = 0; i < (int)v.size(); i++) {
    os << v[i] << (i + 1 != (int)v.size() ? " " : "");
  }
  return os;
}

template <typename T>
ostream& operator<<(ostream& os, const set<T>& set_var) {
  for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {
    os << *itr;
    ++itr;
    if (itr != set_var.end()) os << " ";
    itr--;
  }
  return os;
}

template <typename T, typename U>
ostream& operator<<(ostream& os, const map<T, U>& map_var) {
  for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {
    os << itr->first << " -> " << itr->second << "\n";
  }
  return os;
}

template <typename T, typename U>
ostream& operator<<(ostream& os, const pair<T, U>& pair_var) {
  os << "(" << pair_var.first << ", " << pair_var.second << ")";
  return os;
}

void out() { cout << '\n'; }
template <class T, class... Ts>
void out(const T& a, const Ts&... b) {
  cout << a;
  ((cout << ' ' << b), ...);
  cout << '\n';
}

template <typename T>
istream& operator>>(istream& is, vector<T>& v) {
  for (T& in : v) is >> in;
  return is;
}

inline void in(void) { return; }
template <typename First, typename... Rest>
void in(First& first, Rest&... rest) {
  cin >> first;
  in(rest...);
  return;
}

template <typename T>
bool chmax(T& a, const T& b) {
  if (a < b) {
    a = b;
    return true;
  }
  return false;
}
template <typename T>
bool chmin(T& a, const T& b) {
  if (a > b) {
    a = b;
    return true;
  }
  return false;
}

vector<lint> dx8 = {1, 1, 0, -1, -1, -1, 0, 1};
vector<lint> dy8 = {0, 1, 1, 1, 0, -1, -1, -1};
vector<lint> dx4 = {1, 0, -1, 0};
vector<lint> dy4 = {0, 1, 0, -1};

bool equal_ld(long double a, long double b) {
  return abs(a - b) <= EPS;
}

// a>b
bool greater_ld(long double a, long double b) {
  return !equal_ld(a, b) and a > b;
}

bool less_ld(long double a, long double b) {
  return !equal_ld(a, b) and a < b;
}

// maximize z
pair<long double, vector<long double>> simplex(vector<long double> z, vector<vector<long double>> A, vector<long double> B) {
  int n = int(A.size());
  int m = int(A[0].size());
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < m; j++) {
      A[i][j] = -A[i][j];
    }
  }

  bool is_feasible = true;
  for (int i = 0; i < n; i++) {
    if (less_ld(B[i], 0.0)) is_feasible = false;
  }

  vector<int> n_index(m), b_index(n);
  iota(n_index.begin(), n_index.end(), 0);
  iota(b_index.begin(), b_index.end(), m);
  if (!is_feasible) {
    // todo
  }

  bool stop = false;
  long double optimal_value = 0.0;
  while (!stop) {
    stop = true;
    for (int j = 0; j < m; j++) {
      if (greater_ld(z[j], 0.0)) {
        stop = false;
        int min_i = 1e9;
        int i_memo;
        long double min_ratio = 1e18;
        for (int i = 0; i < n; i++) {
          if (less_ld(A[i][j], 0.0)) {
            long double ratio = B[i] / (-A[i][j]);
            if (greater_ld(min_ratio, ratio) or (equal_ld(min_ratio, ratio) and greater_ld(min_i, b_index[i]))) {
              min_i = b_index[i];
              i_memo = i;
              min_ratio = ratio;
            }
          }
        }

        if (min_i == 1e9) {
          // 非有界
          return {1e35, {}};
        } else {
          vector<long double> tmp(m);
          long double coef = -A[i_memo][j];
          for (int r = 0; r < n; r++) {
            if (r == i_memo) {
              for (int c = 0; c < m; c++) {
                if (c != j) {
                  tmp[c] = A[r][c] / coef;
                } else {
                  tmp[c] = (-1.0) / coef;
                }
              }
              B[r] /= coef;
              continue;
            }
            long double mul = A[r][j];
            if (equal_ld(mul, 0.0)) continue;
            B[r] += mul * min_ratio;

            for (int c = 0; c < m; c++) {
              if (c != j) {
                A[r][c] += A[i_memo][c] / coef * mul;
              } else {
                A[r][c] = (-1.0) / coef * mul;
              }
            }
          }
          long double mul = z[j];
          optimal_value += mul * min_ratio;
          for (int c = 0; c < m; c++) {
            if (c != j) {
              z[c] += A[i_memo][c] / coef * mul;
            } else {
              z[c] = (-1.0) / coef * mul;
            }
          }
          swap(A[i_memo], tmp);
          swap(n_index[j], b_index[i_memo]);

          // for (int r = 0; r < n; r++) {
          //   cout << "x(" << b_index[r] << ") = ";
          //   cout << B[r] << " ";
          //   for (int c = 0; c < m; c++) {
          //     cout << (A[r][c] >= 0.0 ? "+" : "") << A[r][c] << "x(" << n_index[c] << ") ";
          //   }
          //   out();
          // }
          // cout << "z   = " << optimal_value << " ";
          // for (int c = 0; c < m; c++) {
          //   cout << (z[c] >= 0.0 ? "+" : "") << z[c] << "x(" << n_index[c] << ") ";
          // }
          // out();
          // out("===================================");
          // out();
          break;
        }
      }
    }
  }
  return {optimal_value, {}};
}

int main() {
  cin.tie(0)->sync_with_stdio(0);
  vector<long double> z = {1000, 2000};
  vector<vector<long double>> a = {{0.75, 2.0 / 7.0}, {0.25, 5.0 / 7.0}};
  vector<long double> b(2);
  in(b);
  logfixed(simplex(z, a, b).first);
}
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