結果
| 問題 | No.2313 Product of Subsequence (hard) |
| ユーザー |
|
| 提出日時 | 2026-04-26 03:36:50 |
| 言語 | PyPy3 (7.3.17) |
| 結果 |
AC
|
| 実行時間 | 3,484 ms / 4,000 ms |
| コード長 | 4,337 bytes |
| 記録 | |
| コンパイル時間 | 518 ms |
| コンパイル使用メモリ | 84,992 KB |
| 実行使用メモリ | 356,844 KB |
| 最終ジャッジ日時 | 2026-04-26 03:37:30 |
| 合計ジャッジ時間 | 33,937 ms |
|
ジャッジサーバーID (参考情報) |
judge3_0 / judge2_1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 27 |
ソースコード
## https://yukicoder.me/problems/no/353
import math
MOD = 998244353
class CombinationCalculator:
"""
modを考慮したPermutation, Combinationを計算するためのクラス
"""
def __init__(self, size, mod):
self.mod = mod
self.factorial = [0] * (size + 1)
self.factorial[0] = 1
for i in range(1, size + 1):
self.factorial[i] = (i * self.factorial[i - 1]) % self.mod
self.inv_factorial = [0] * (size + 1)
self.inv_factorial[size] = pow(self.factorial[size], self.mod - 2, self.mod)
for i in reversed(range(size)):
self.inv_factorial[i] = ((i + 1) * self.inv_factorial[i + 1]) % self.mod
def calc_combination(self, n, r):
if n < 0 or n < r or r < 0:
return 0
if r == 0 or n == r:
return 1
ans = self.inv_factorial[n - r] * self.inv_factorial[r]
ans %= self.mod
ans *= self.factorial[n]
ans %= self.mod
return ans
def calc_permutation(self, n, r):
if n < 0 or n < r:
return 0
ans = self.inv_factorial[n - r]
ans *= self.factorial[n]
ans %= self.mod
return ans
def main():
N, K = map(int, input().split())
A = list(map(int, input().split()))
if K == 1:
print((pow(2, N, MOD) - 1) % MOD)
return
base_k = K
# Kを素因数分解
sqrt_k = int(math.sqrt(K))
k_primes = {}
for p in range(2, sqrt_k + 1):
if K % p == 0:
ans = 0
while K % p == 0:
ans += 1
K //= p
k_primes[p] = ans
if K > 1:
k_primes[K] = 1
k_primes_array = [(p, value) for p, value in k_primes.items()]
k_primes_array.sort(key=lambda x: x[0])
# 状態を全て定義
def dfs(k_primes_array, index, p, p_list, p_to_list_map):
if index == len(k_primes_array):
xx = tuple(p_list)
p_to_list_map[p] = xx
return
p0, value = k_primes_array[index]
q = 1
for v in range(value + 1):
p_list.append(v)
dfs(k_primes_array, index + 1, p * q, p_list, p_to_list_map)
p_list.pop()
q *= p0
return
p_to_list_map = {}
dfs(k_primes_array, 0, 1, [], p_to_list_map)
# 各種状態遷移について定義しておく
transition = {}
for from_p, from_p_list in p_to_list_map.items():
for transi_p, transi_p_list in p_to_list_map.items():
q = 1
for j in range(len(k_primes_array)):
p, max_v = k_primes_array[j]
q *= p ** (min(max_v, from_p_list[j] + transi_p_list[j]))
transition[(from_p, transi_p)] = q
# 各要素について
a_array = {}
for a in A:
ans = []
q = 1
for p, value in k_primes_array:
x = 0
while a % p == 0:
x += 1
a //= p
x = min(value, x)
q *= p ** x
if q not in a_array:
a_array[q] = 0
a_array[q] += 1
combi = CombinationCalculator(N, MOD)
# dpで解く
dp = {1: 1}
for a, freq_q in a_array.items():
new_dp = dp.copy()
for key_p, value in dp.items():
key_p0 = key_p
xxx = 1
for q in range(1, freq_q + 1):
new_key_p = transition[(key_p0, a)]
if new_key_p not in new_dp:
new_dp[new_key_p] = 0
new_dp[new_key_p] += (value * combi.calc_combination(freq_q, q)) % MOD
new_dp[new_key_p] %= MOD
xxx += combi.calc_combination(freq_q, q)
xxx %= MOD
if new_key_p == key_p0:
yyy = (pow(2, freq_q, MOD) - xxx) % MOD
if new_key_p not in new_dp:
new_dp[new_key_p] = 0
new_dp[new_key_p] += (value * yyy) % MOD
new_dp[new_key_p] %= MOD
break
key_p0 = new_key_p
dp = new_dp
if base_k not in dp:
print(0)
else:
print(dp[base_k])
if __name__ == "__main__":
main()