#1163967 (C++23) No.3535 $E\times - Otogibanashi$

• 問題: No.3535 $E\times - Otogibanashi$
• ユーザー: yaaya
• 提出日時: 2026-05-08 23:11:13
• 言語: C++23 (gcc 15.2.0 + boost 1.89.0)
• 結果: AC
• 実行時間: 716 ms / 2,000 ms
• コード長: 3,693 bytes
• コンパイル時間: 2,529 ms
• コンパイル使用メモリ: 342,148 KB
• 実行使用メモリ: 91,848 KB
• 最終ジャッジ日時: 2026-05-08 23:11:33
• 合計ジャッジ時間: 9,550 ms
• ジャッジサーバーID （参考情報）: judge2_1 / judge3_1

ファイルパターン	結果
sample	AC * 2
other	AC * 21

ソースコード

#include <bits/stdc++.h>
using namespace std;
#define rep(i,a,b) for(ll i=a;i<b;i++)
#define rrep(i,a,b) for(ll i=a-1;i>=b;i--)
#define ll long long
#define ull unsigned long long
#define ld long double
#define bl __int128_t
#define fi first
#define se second
#define vel vector<long long>
#define vvel vector<vector<long long>>
#define vvepll vector<vepll>
#define pll pair<ll,ll>
#define vepll vector<pll>
#define ves vector<string>
#define vem vector<mint>
#define vvem vector<vem>
#define bl __int128_t
#define cleout(i) cout<<fixed<<setprecision(i)
template<class T>using PQ=priority_queue<T,vector<T>,greater<T>>;
//               上  右 下 左
vector<int> dx={ -1, 0, 1, 0 };
vector<int> dy={ 0, 1, 0, -1 };


vector<int> ddx={ 1, 1, 1, 0, -1, -1, -1, 0 };
vector<int> ddy={ 1, 0, -1, -1, -1, 0, 1, 1 };

ll N, K, M, L, R, T, Q, H, W, i, j, l, r;
ll x, y, z;
unsigned long long q;
string S;
long double k;
ll inf=1000000000000000000;//1e18
// inf=1e9+7;
// LLONG_MAX

//mt19937_64 rng((ull) chrono::steady_clock::now().time_since_epoch().count());

//[x^M]1/(1-x)^N=comb(N-1+M,M)

struct mint{
    ll num;
    static ll P;
    static void set_mod(ll MOD){
        P=MOD;
    }
    mint(ll x=0){
        if(x<0){
            x*=-1;
            x%=P;
            x=P-x;
        }
        x%=P;
        num=x;
    }
    mint operator+(const mint &other)const{
        return mint(num+other.num);
    }
    mint operator-(const mint &other)const{
        return mint(num-other.num);
    }
    mint operator*(const mint &other)const{
        return mint(num*other.num);
    }
    mint &operator+=(const mint &other){
        num+=other.num;
        if(num>=P) num-=P;
        return *this;
    }
    mint &operator-=(const mint &other){
        num-=other.num;
        if(num<0) num+=P;
        return *this;
    }
    mint &operator*=(const mint &other){
        num=(num*other.num)%P;
        return *this;
    }
    mint beki(const ll &x)const{
        mint res=1;
        mint now=num;
        rep(i,0,60){
            if(x&(1ll<<i)){
                res*=now;
            } 
            now*=now;
        }
        return res;
    }
    mint inv()const{
        mint res=1;
        mint now=num;
        rep(i,0,30){
            if((P-2)&(1ll<<i)){
                res*=now;
            } 
            now*=now;
        }
        return res;
    }
    mint operator/(const mint &other)const{
        return *this*other.inv();
    }
    mint &operator/=(const mint &other){
        num=(num*other.inv())%P;
        return *this;
    }
    operator ll()const{
        return (ll)(num);
    }
    friend ostream& operator<<(ostream& os, const mint& m){
        os << m.num;
        return os;
    }
    friend istream& operator>>(istream& is,mint& m){
        ll x;
        is>>x;
        m=mint(x);
        return is;
    }
};
ll mint::P=998244353;
//ll mint::P=1000000007;

void _solve(){
    ll p;
    cin>>N>>p;
    mint::set_mod(p);
    mint ans=0;
    unordered_set<ll> se;
    rep(i,1,10){
        rep(j,0,10){
            rep(k,0,10){
                ll now=0;
                now+=10*i+i;
                now*=100;
                now+=10*j+k;
                now*=100;
                now+=k*10+j;
                rep(l,1,10000){
                    if(abs(now*l)<=N){
                        if(!se.count(now*l))ans-=(mint)(now)*(mint)l;
                        se.insert(now*l);
                    }else break;
                }
            }
        }
    }
    cout<<ans<<"\n";
}


int main(){
    cin.tie(nullptr);
 	ios_base::sync_with_stdio(false);

    
    ll _;
    bool multitest=0;
    if(multitest)cin>>_;
    else _=1;
    rep(__,0,_){
        _solve();
    }
}