結果

問題 No.137 貯金箱の焦り
コンテスト
ユーザー a_s_k
提出日時 2026-05-15 03:48:11
言語 C++23
(gcc 15.2.0 + boost 1.89.0)
コンパイル:
g++-15 -O2 -lm -std=c++23 -Wuninitialized -DONLINE_JUDGE -o a.out _filename_
実行:
./a.out
結果
WA  
実行時間 -
コード長 3,965 bytes
記録
記録タグの例:
初AC ショートコード 純ショートコード 純主流ショートコード 最速実行時間
コンパイル時間 5,914 ms
コンパイル使用メモリ 386,476 KB
実行使用メモリ 6,400 KB
最終ジャッジ日時 2026-05-15 03:48:19
合計ジャッジ時間 6,309 ms
ジャッジサーバーID
(参考情報)
judge3_1 / judge1_0
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 9 WA * 14
権限があれば一括ダウンロードができます
コンパイルメッセージ
In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/vector:67,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/functional:66,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/x86_64-pc-linux-gnu/bits/stdc++.h:55,
                 from main.cpp:1:
In function '_ForwardIterator std::uninitialized_copy(_InputIterator, _InputIterator, _ForwardIterator) [with _InputIterator = atcoder::dynamic_modint<-1>*; _ForwardIterator = atcoder::dynamic_modint<-1>*]',
    inlined from 'constexpr _ForwardIterator std::__uninitialized_copy_a(_InputIterator, _Sentinel, _ForwardIterator, allocator<_Tp>&) [with _InputIterator = atcoder::dynamic_modint<-1>*; _Sentinel = atcoder::dynamic_modint<-1>*; _ForwardIterator = atcoder::dynamic_modint<-1>*; _Tp = atcoder::dynamic_modint<-1>]' at /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/bits/stl_uninitialized.h:635:32,
    inlined from 'constexpr std::vector<_Tp, _Alloc>& std::vector<_Tp, _Alloc>::operator=(const std::vector<_Tp, _Alloc>&) [with _Tp = atcoder::dynamic_modint<-1>; _Alloc = std::allocator<atcoder::dynamic_modint<-1> >]' at /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/bits/vector.tcc:257:35,
    inlined from 'int main()' at main.cpp:161:14:
/home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/bits/stl_uninitialized.h:273:31: warning: 'void* __builtin_memcpy(void*, const void*, long unsigned int)' writing between 1 and 10004 bytes into a region of size 0 overflows the destination [-Wstringop-overflow=]
  273 |               __builtin_memcpy(std::__niter_base(__result),
      |               ~~~~~~~~~~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~
  274 |                                std::__niter_base(__first),
      |                                ~~~~~~~~~~~~~~~~~~~~~~~~~~~
  275 |                                __n * sizeof(_ValT));
      |                                ~~~~~~~~~~~~~~~~~~~~
In f

ソースコード

diff #
raw source code

#include "bits/stdc++.h"
#include "atcoder/all"
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/tag_and_trait.hpp>
using namespace __gnu_pbds;
using namespace std;
using namespace atcoder;
using ll = long long;
using ld = long double;
using ull = unsigned long long;
#define rep(i, m, n) for (ll i = (ll)m; i < (ll)n; i++)
#define drep(i, m, n) for (ll i = m - 1; i >= n; i--)
#define Endl endl
#define all(a) a.begin(), a.end()
#define pr(i, j) make_pair(i, j)
#define isin(x, l, r) (l <= x && x < r)
template <typename T>
bool chmin(T &a, T b)
{
    if (a > b)
    {
        a = b;
        return true;
    }
    return false;
};
template <typename T>
bool chmax(T &a, T b)
{
    if (a < b)
    {
        a = b;
        return true;
    }
    return false;
};
#define srt(ar) sort(ar.begin(), ar.end())
#define rev(ar) reverse(ar.begin(), ar.end())
#define jge(f, s, t) cout << (f ? s : t) << endl
template <typename T>
using ordered_set = tree<T, null_type, std::less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")

#define printar(ar)             \
    do                          \
    {                           \
        for (auto dbg : ar)     \
        {                       \
            cout << dbg << " "; \
        }                       \
        cout << endl;           \
    } while (0)
const ll inf = 1e18;
const ld pi = 3.14159265358979;
const ld eps = 1e-9;
template <class T, ll n, ll idx = 0>
auto make_vec(const ll (&d)[n], const T &init) noexcept
{
    if constexpr (idx < n)
        return std::vector(d[idx], make_vec<T, n, idx + 1>(d, init));
    else
        return init;
}

template <class T, ll n>
auto make_vec(const ll (&d)[n]) noexcept
{
    return make_vec(d, T{});
}
//////////////// 以下を貼る ////////////////
template <class T>
size_t HashCombine(const size_t seed, const T &v)
{
    return seed ^ (std::hash<T>()(v) + 0x9e3779b9 + (seed << 6) + (seed >> 2));
}
/* pair用 */
template <class T, class S>
struct std::hash<std::pair<T, S>>
{
    size_t operator()(const std::pair<T, S> &keyval) const noexcept
    {
        return HashCombine(std::hash<T>()(keyval.first), keyval.second);
    }
};
/* vector用 */
template <class T>
struct std::hash<std::vector<T>>
{
    size_t operator()(const std::vector<T> &keyval) const noexcept
    {
        size_t s = 0;
        for (auto &&v : keyval)
            s = HashCombine(s, v);
        return s;
    }
};
/* tuple用 */
template <int N>
struct HashTupleCore
{
    template <class Tuple>
    size_t operator()(const Tuple &keyval) const noexcept
    {
        size_t s = HashTupleCore<N - 1>()(keyval);
        return HashCombine(s, std::get<N - 1>(keyval));
    }
};
template <>
struct HashTupleCore<0>
{
    template <class Tuple>
    size_t operator()(const Tuple &keyval) const noexcept { return 0; }
};
template <class... Args>
struct std::hash<std::tuple<Args...>>
{
    size_t operator()(const tuple<Args...> &keyval) const noexcept
    {
        return HashTupleCore<tuple_size<tuple<Args...>>::value>()(keyval);
    }
};
////////////////////////////////////////////
using mint = modint;
int main()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    ll n, m;
    cin >> n >> m;
    modint::set_mod(1234567891);
    vector<ll> a(n);
    rep(i, 0, n)
    {
        cin >> a[i];
    }
    vector<mint> dp(2501);
    dp[0] = 1;
    rep(i, 0, 62)
    {
        rep(j, 0, n)
        {
            drep(k, 2501, 0)
            {
                if (k - a[j] >= 0)
                {
                    dp[k] += dp[k - a[j]];
                }
            }
        }
        vector<mint> cp(2501);
        rep(j, 0, 2501)
        {
            if (m % 2 == j % 2)
            {
                cp[j / 2] += dp[j];
            }
        }
        dp = cp;
        m /= 2;
    }
    cout << dp[0].val() << endl;
}
0