結果
| 問題 | No.3566 Subsequence Sum |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2026-06-06 00:02:21 |
| 言語 | C++17 (gcc 15.2.0 + boost 1.89.0) |
| 結果 |
AC
|
| 実行時間 | 626 ms / 2,000 ms |
| コード長 | 5,154 bytes |
| 記録 | |
| コンパイル時間 | 2,353 ms |
| コンパイル使用メモリ | 229,208 KB |
| 実行使用メモリ | 98,172 KB |
| 最終ジャッジ日時 | 2026-06-06 00:02:35 |
| 合計ジャッジ時間 | 5,834 ms |
|
ジャッジサーバーID (参考情報) |
judge1_1 / judge2_0 |
| 純コード判定待ち |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 15 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
//入力が必ず-mod<=a<modの時.
template<const int mod> //mod<2^30.
struct modint{ //mod変更が不可能.
public:
long long v;
static void setmod(int m){} //飾り.
static constexpr long long getmod(){return mod;}
modint():v(0){}
template<typename T>
modint(T a):v(a){if(v < 0) v += mod;}
long long val()const{return v;}
modint &operator=(const modint &b) = default;
modint &operator+()const{return (*this);}
modint operator-()const{return modint(0)-(*this);}
modint operator+(const modint b)const{return modint(v)+=b;}
modint operator-(const modint b)const{return modint(v)-=b;}
modint operator*(const modint b)const{return modint(v)*=b;}
modint operator/(const modint b)const{return modint(v)/=b;}
modint &operator+=(const modint b){
v += b.v; if(v >= mod) v -= mod;
return *this;
}
modint &operator-=(const modint b){
v -= b.v; if(v < 0) v += mod;
return *this;
}
modint &operator*=(const modint b){v = v*b.v%mod; return *this;}
modint &operator/=(modint b){ //b!=0 mod素数が必須.
assert(b.v != 0);
(*this) *= b.pow(mod-2);
return *this;
}
modint pow(long long n)const{
modint ret = 1,p = v;
if(n < 0) p = p.inv(),n = -n;
while(n){
if(n&1) ret *= p;
p *= p; n >>= 1;
}
return ret;
}
modint inv()const{return pow(mod-2);} //素数mod必須.
modint &operator++(){*this += 1; return *this;}
modint &operator--(){*this -= 1; return *this;}
modint operator++(int){modint ret = *this; *this += 1; return ret;}
modint operator--(int){modint ret = *this; *this -= 1; return ret;}
friend bool operator==(const modint a,const modint b){return a.v==b.v;}
friend bool operator!=(const modint a,const modint b){return a.v!=b.v;}
friend bool operator<(const modint a,const modint b){return a.v<b.v;}
friend bool operator<=(const modint a,const modint b){return a.v<=b.v;}
friend bool operator>=(const modint a,const modint b){return a.v>=b.v;}
friend bool operator>(const modint a,const modint b){return a.v>b.v;}
friend ostream &operator<<(ostream &os,const modint a){return os<<a.v;}
friend istream &operator>>(istream &is,modint &a){ //入力はmodをとってくれる.
long long x; is >> x; x %= mod;
a = modint(x); return is;
}
};
using mint = modint<998244353>; const long long mod = 998244353;
struct SS{
mint v,mul,add;
SS operator*(SS b){
return {v*b.v,mul*b.mul,add*b.mul+v*b.add};
}
SS operator+(SS b){
return {v+b.v,mul+b.mul,add+b.add};
}
SS operator+=(SS b){
return *this = *this+b;
}
SS operator*=(SS b){
return *this = *this*b;
}
};
template<typename T>
vector<vector<T>> multima(vector<vector<T>> &A,vector<vector<T>> &B){
assert(A.at(0).size() == B.size() && B.size());
int H = A.size(),W = B.at(0).size();
vector<vector<T>> ret(H,vector<T>(W));
for(int i=0; i<H; i++) for(int k=0; k<W; k++){
for(int l=0; l<A.at(i).size(); l++){
ret.at(i).at(k) += B.at(l).at(k)*A.at(i).at(l);
}
}
return ret; //計算できる行列のみ.
}
template<typename T>
vector<vector<T>> Powmat(vector<vector<T>> A,vector<vector<T>> B,long long N){ //return A^N*B ABは行列;
//n*n行列A n*1行列Bと想定 O(n^3*logN).
assert(A.size() && A.size() == A.at(0).size() && N >= 0);
while(N){
if(N&1) B = multima(A,B);
A = multima(A,A); N >>= 1;
}
return B;
}
int main(){
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
string s; cin >> s;
int N = s.size(),K; cin >> K;
vector<vector<int>> next(N,vector<int>(10,N));
for(int i=N-2; i>=0; i--){
next.at(i) = next.at(i+1);
next.at(i).at(s.at(i+1)-'0') = i+1;
}
vector<int> C(10,-1);
for(int i=0; i<N; i++){
int c = s.at(i)-'0';
if(C.at(c) != -1) continue;
C.at(c) = i;
}
vector<int> look;
for(int i=0; i<10; i++) if(C.at(i) != -1) look.push_back(i);
int n = look.size();
vector<vector<SS>> A(n+1,vector<SS>(n+1)),B(n+1,vector<SS>(1));
for(int p=0; p<n; p++){
int c = look.at(p);
if(c) B.at(p).at(0) = {1,1,c};
vector<SS> dp(N);
dp.at(C.at(c)) = {1,1,0};
vector<SS> V(n+1);
for(int i=C.at(c); i<N; i++){
SS v = dp.at(i);
V.at(n) += v;
v = {v.v,v.mul*10,v.add*10};
for(int k=0; k<n; k++){
int c2 = look.at(k);
int to = next.at(i).at(c2);
SS now = {v.v,v.mul,v.add+v.v*c2};
if(to == N){
V.at(k) += now;
}
else dp.at(to) += now;
}
}
for(int i=0; i<=n; i++) A.at(i).at(p) = V.at(i);
}
A.at(n).at(n) = {1,1,0};
B = Powmat(A,B,K);
auto [v1,v2,v3] = B.at(n).at(0);
cout << v3 << endl; return 0;
cout << v1 << " " << v2 << " " << v3 << endl;
}