結果
| 問題 | No.3600 Moving Queen Many Times |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2026-07-24 23:22:33 |
| 言語 | C++17 (gcc 15.2.0 + boost 1.90.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 4,335 bytes |
| 記録 | |
| コンパイル時間 | 1,358 ms |
| コンパイル使用メモリ | 222,844 KB |
| 実行使用メモリ | 178,176 KB |
| 最終ジャッジ日時 | 2026-07-24 23:22:43 |
| 合計ジャッジ時間 | 8,082 ms |
|
ジャッジサーバーID (参考情報) |
judge3_0 / judge1_1 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 WA * 1 |
| other | AC * 34 WA * 41 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
//入力が必ず-mod<=a<modの時.
template<const int mod> //mod<2^30.
struct modint{ //mod変更が不可能.
public:
long long v;
static void setmod(int m){} //飾り.
static constexpr long long getmod(){return mod;}
modint():v(0){}
template<typename T>
modint(T a):v(a){if(v < 0) v += mod;}
long long val()const{return v;}
modint &operator=(const modint &b) = default;
modint &operator+()const{return (*this);}
modint operator-()const{return modint(0)-(*this);}
modint operator+(const modint b)const{return modint(v)+=b;}
modint operator-(const modint b)const{return modint(v)-=b;}
modint operator*(const modint b)const{return modint(v)*=b;}
modint operator/(const modint b)const{return modint(v)/=b;}
modint &operator+=(const modint b){
v += b.v; if(v >= mod) v -= mod;
return *this;
}
modint &operator-=(const modint b){
v -= b.v; if(v < 0) v += mod;
return *this;
}
modint &operator*=(const modint b){v = v*b.v%mod; return *this;}
modint &operator/=(modint b){ //b!=0 mod素数が必須.
assert(b.v != 0);
(*this) *= b.pow(mod-2);
return *this;
}
modint pow(long long n)const{
modint ret = 1,p = v;
if(n < 0) p = p.inv(),n = -n;
while(n){
if(n&1) ret *= p;
p *= p; n >>= 1;
}
return ret;
}
modint inv()const{return pow(mod-2);} //素数mod必須.
modint &operator++(){*this += 1; return *this;}
modint &operator--(){*this -= 1; return *this;}
modint operator++(int){modint ret = *this; *this += 1; return ret;}
modint operator--(int){modint ret = *this; *this -= 1; return ret;}
friend bool operator==(const modint a,const modint b){return a.v==b.v;}
friend bool operator!=(const modint a,const modint b){return a.v!=b.v;}
friend bool operator<(const modint a,const modint b){return a.v<b.v;}
friend bool operator<=(const modint a,const modint b){return a.v<=b.v;}
friend bool operator>=(const modint a,const modint b){return a.v>=b.v;}
friend bool operator>(const modint a,const modint b){return a.v>b.v;}
friend ostream &operator<<(ostream &os,const modint a){return os<<a.v;}
friend istream &operator>>(istream &is,modint &a){ //入力はmodをとってくれる.
long long x; is >> x; x %= mod;
a = modint(x); return is;
}
};
using mint = modint<998244353>; const long long mod = 998244353;
template<typename T>
vector<vector<T>> multima(vector<vector<T>> &A,vector<vector<T>> &B){
assert(A.at(0).size() == B.size() && B.size());
int H = A.size(),W = B.at(0).size();
vector<vector<T>> ret(H,vector<T>(W));
for(int i=0; i<H; i++) for(int k=0; k<W; k++){
for(int l=0; l<A.at(i).size(); l++){
ret.at(i).at(k) += A.at(i).at(l)*B.at(l).at(k);
}
}
return ret; //計算できる行列のみ.
}
template<typename T>
vector<vector<T>> Powmat(vector<vector<T>> A,vector<vector<T>> B,long long N){ //return A^N*B ABは行列;
//n*n行列A n*1行列Bと想定 O(n^3*logN).
assert(A.size() && A.size() == A.at(0).size() && N >= 0);
while(N){
if(N&1) B = multima(A,B);
A = multima(A,A); N >>= 1;
}
return B;
}
int main(){
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
long long H,W,sx,gx,sy,gy,K; cin >> H >> W >> sx >> sy >> gx >> gy >> K,sx--,sy--,gx--,gy--;
long long N = H*W,n2 = 1<<N;
long long loop = K/16; K %= 16;
vector dp(n2,vector(N,vector<mint>(N)));
for(int i=0; i<N; i++) dp[0][i][i] = 1;
for(int s=1; s<n2; s++) for(int i=0; i<N; i++) for(int k=0; k<N; k++) if(s&(1<<k)){
int x = k/W,y = k%W;
for(int l=0; l<N; l++) if(k != l){
int x2 = l/W,y2 = l%W;
if(x == x2 || y == y2 || abs(x-x2) == abs(y-y2)) dp[s][i][k] += dp[s-(1<<k)][i][l];
}
}
vector<vector<mint>> A = dp.back(),B(N,vector<mint>(1));
B.at(sx*W+sy).at(0) = 1;
if(loop) B = Powmat(A,B,loop);
mint answer = 0;
for(int s=0; s<n2; s++) for(int i=0; i<N; i++){
if(__popcount((unsigned int)s) != K) continue;
int k = gx*W+gy;
answer += B.at(i).at(0)*dp[s][i][k];
}
cout << answer << endl;
}