#1174246 (C++17) No.3605 Grand Cross

• 問題: No.3605 Grand Cross
• ユーザー: 👑 AngrySadEight
• 提出日時: 2026-07-30 02:11:23
• 言語: C++17 (gcc 15.2.0 + boost 1.90.0)
• 結果: AC
• 実行時間: 381 ms / 2,000 ms
• コード長: 5,925 bytes
• コンパイル時間: 2,588 ms
• コンパイル使用メモリ: 220,064 KB
• 実行使用メモリ: 77,724 KB
• 最終ジャッジ日時: 2026-07-31 20:53:04
• 合計ジャッジ時間: 13,782 ms
• ジャッジサーバーID （参考情報）: judge1_0 / judge2_0

ファイルパターン	結果
sample	AC * 1
other	AC * 49

ソースコード

#include <algorithm>
#include <atcoder/all>
#include <bitset>
#include <cassert>
#include <cmath>
#include <ctime>
#include <functional>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <random>
#include <set>
#include <stack>
#include <string>
#include <tuple>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
using namespace std;
using namespace atcoder;
typedef long long ll;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define repr(i, n) for (int i = (int)(n) - 1; i >= 0; i--)
#define repk(i, k, n) for (int i = k; i < (int)(n); i++)
#define all(v) v.begin(), v.end()
#define mod1 1000000007
#define mod2 998244353
#define mod3 100000007
#define vi vector<int>
#define vs vector<string>
#define vc vector<char>
#define vl vector<ll>
#define vb vector<bool>
#define vvi vector<vector<int>>
#define vvc vector<vector<char>>
#define vvl vector<vector<ll>>
#define vvb vector<vector<bool>>
#define vvvi vector<vector<vector<int>>>
#define vvvl vector<vector<vector<ll>>>
#define pii pair<int, int>
#define pil pair<int, ll>
#define pli pair<ll, int>
#define pll pair<ll, ll>
#define vpii vector<pair<int, int>>
#define vpll vector<pair<ll, ll>>
#define vvpii vector<vector<pair<int, int>>>
#define vvpll vector<vector<pair<ll, ll>>>

template <typename T>
void debug(T e) {
    cerr << e << endl;
}

template <typename T>
void debug(vector<T> &v) {
    rep(i, v.size()) { cerr << v[i] << " "; }
    cerr << endl;
}

template <typename T>
void debug(vector<vector<T>> &v) {
    rep(i, v.size()) {
        rep(j, v[i].size()) { cerr << v[i][j] << " "; }
        cerr << endl;
    }
}

template <typename T>
void debug(vector<pair<T, T>> &v) {
    rep(i, v.size()) { cerr << v[i].first << " " << v[i].second << endl; }
}

template <typename T>
void debug(set<T> &st) {
    for (auto itr = st.begin(); itr != st.end(); itr++) {
        cerr << *itr << " ";
    }
    cerr << endl;
}

template <typename T>
void debug(multiset<T> &ms) {
    for (auto itr = ms.begin(); itr != ms.end(); itr++) {
        cerr << *itr << " ";
    }
    cerr << endl;
}

template <typename T>
void debug(map<T, T> &mp) {
    for (auto itr = mp.begin(); itr != mp.end(); itr++) {
        cerr << itr->first << " " << itr->second << endl;
    }
}

void debug_out() { cerr << endl; }

template <typename Head, typename... Tail>
void debug_out(Head H, Tail... T) {
    cerr << H << " ";
    debug_out(T...);
}

using mint = modint1000000007;

void debug_mint1(vector<mint> &vec) {
    for (int i = 0; i < vec.size(); i++) {
        cerr << vec[i].val() << " ";
    }
    cerr << endl;
}

void debug_mint2(vector<vector<mint>> &vec) {
    for (int i = 0; i < vec.size(); i++) {
        for (int j = 0; j < vec[i].size(); j++) {
            cerr << vec[i][j].val() << " ";
        }
        cerr << endl;
    }
}

int main() {
    ll T;
    cin >> T;
    while (T--){
        ll N, M;
        cin >> N >> M;
        vector<ll> A(N);
        vector<ll> B(M);
        vector<ll> C(N);
        vector<ll> D(M);
        rep(i, N) cin >> A[i];
        rep(i, M) cin >> B[i];
        rep(i, N) cin >> C[i];
        rep(i, M) cin >> D[i];

        vector<ll> RA(N);
        vector<ll> RB(M);
        rep(i, N) RA[i] = A[N - 1 - i];
        rep(i, M) RB[i] = B[M - 1 - i];

        vector<ll> sum_a(N + 1, 0);
        vector<ll> sum_b(M + 1, 0);
        vector<ll> sum_ra(N + 1, 0);
        vector<ll> sum_rb(M + 1, 0);
        rep(i, N) sum_a[i + 1] = sum_a[i] + A[i];
        rep(i, M) sum_b[i + 1] = sum_b[i] + B[i];
        rep(i, N) sum_ra[i + 1] = sum_ra[i] + RA[i];
        rep(i, M) sum_rb[i + 1] = sum_rb[i] + RB[i];

        // どちらか片方は必ず端まで伸びる？
        // 各色のインデックスを前もって計算しておく
        vector<vector<ll>> id_a(N + M + 1, vector<ll>(0));
        vector<vector<ll>> id_b(N + M + 1, vector<ll>(0));
        vector<vector<ll>> id_ra(N + M + 1, vector<ll>(0));
        vector<vector<ll>> id_rb(N + M + 1, vector<ll>(0));
        rep(i, N){
            id_a[C[i]].push_back(i);
            id_ra[C[N - 1 - i]].push_back(i);
        }
        rep(i, M){
            id_b[D[i]].push_back(i);
            id_rb[D[M - 1 - i]].push_back(i);
        }
        
        ll ans = -1;
        // 片方の端を固定し、もう片方の中央を固定する
        for (ll i = 0; i < M; i++){
            ll ub = min(min(i, M - 1 - i), (N + 1) / 2 - 1);
            auto it = lower_bound(all(id_a[D[i]]), ub + 1);
            if (it == id_a[D[i]].begin()) continue;
            it--;
            ll id = *it;

            // debug_out(i, id);
            ans = max(ans, sum_a[id * 2 + 1] + sum_b[i + id + 1] - sum_b[i - id]);
        }
        for (ll i = 0; i < M; i++){
            ll ub = min(min(i, M - 1 - i), (N + 1) / 2 - 1);
            auto it = lower_bound(all(id_ra[D[i]]), ub + 1);
            if (it == id_ra[D[i]].begin()) continue;
            it--;
            ll id = *it;

            // debug_out(i, id);
            ans = max(ans, sum_ra[id * 2 + 1] + sum_b[i + id + 1] - sum_b[i - id]);
        }
        for (ll i = 0; i < N; i++){
            ll ub = min(min(i, N - 1 - i), (M + 1) / 2 - 1);
            auto it = lower_bound(all(id_b[C[i]]), ub + 1);
            if (it == id_b[C[i]].begin()) continue;
            it--;
            ll id = *it;

            // debug_out(i, id);
            ans = max(ans, sum_b[id * 2 + 1] + sum_a[i + id + 1] - sum_a[i - id]);
        }
        for (ll i = 0; i < N; i++){
            ll ub = min(min(i, N - 1 - i), (M + 1) / 2 - 1);
            auto it = lower_bound(all(id_rb[C[i]]), ub + 1);
            if (it == id_rb[C[i]].begin()) continue;
            it--;
            ll id = *it;

            // debug_out(i, id);
            ans = max(ans, sum_rb[id * 2 + 1] + sum_a[i + id + 1] - sum_a[i - id]);
        }
        cout << ans << endl;
    }
}