結果

問題 No.3605 Grand Cross
コンテスト
ユーザー dadas
提出日時 2026-07-31 21:51:19
言語 C++17
(gcc 15.2.0 + boost 1.90.0)
コンパイル:
g++-15 -O2 -lm -std=c++17 -Wuninitialized -DONLINE_JUDGE -o a.out _filename_
実行:
./a.out
結果
WA  
実行時間 -
コード長 6,574 bytes
記録
記録タグの例:
初AC ショートコード 純ショートコード 純主流ショートコード 最速実行時間
コンパイル時間 1,339 ms
コンパイル使用メモリ 224,876 KB
実行使用メモリ 42,120 KB
最終ジャッジ日時 2026-07-31 21:51:27
合計ジャッジ時間 7,378 ms
ジャッジサーバーID
（参考情報） 		judge1_0 / judge3_0
このコードへのチャレンジ
（要ログイン）
ファイルパターン 結果
sample AC * 1
other AC * 44 WA * 5
権限があれば一括ダウンロードができます

ソースコード

diff #
raw source code 

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*/
#include <bits/stdc++.h>
#pragma GCC optimize("O3")
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
//	mt19937 engine((unsigned ll)time(NULL));
//	uniform_int_distribution<ll> distribution(0, (ll)1e18);
//	auto generator = bind(distribution, engine);
//	ll x = generator();
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/tree_policy.hpp>
// using namespace __gnu_pbds;
// #define ordered_set tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update>
// #define ordered_multiset tree<int, null_type, less_equal<int>, rb_tree_tag,tree_order_statistics_node_update>
using namespace std;
void _main();
int main()
{
	cin.tie(0);
	ios::sync_with_stdio(false);
	_main();
	return 0;
}
using ll = long long;
using ull = unsigned long long;
using ld = long double;
using vi = std::vector<int>;
using vvi = std::vector<vi>;
using vl = std::vector<ll>;
using vii = std::vector<pair<int, int>>;
using vvl = std::vector<vl>;
using vll = std::vector<pair<ll, ll>>;
using vd = std::vector<double>;
using vvd = std::vector<vd>;
using vs = std::vector<std::string>;
using vvs = std::vector<vs>;
using vb = std::vector<bool>;
using vvb = std::vector<vb>;
using vc = std::vector<char>;
using vvc = std::vector<vc>;
using pii = std::pair<int, int>;
using pll = std::pair<ll, ll>;
using piil = std::pair<pair<int, int>, ll>;
using mii = std::map<int, int>;
using mll = std::map<ll, ll>;
using pql = std::priority_queue<ll>;
using pqi = std::priority_queue<int>;
using pqiil = std::priority_queue<pair<pair<int, int>, ll>>;
using pqii = std::priority_queue<pair<int, int>>;

#define pb push_back
#define ps push
#define eb emplace_back
#define is insert
#define er erase
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define sf(i) sizeof(i)
#define endl "\n"
#define all(v) (v).begin(), (v).end()
#define rep(i, L, R) for (ll i = L; i <= R; i++)
#define pcis precision
#define sz(a) ((ll)a.size())

template <typename T>
struct infinity
{
	static constexpr T max = std::numeric_limits<T>::max();
	static constexpr T min = std::numeric_limits<T>::min();
	static constexpr T value = std::numeric_limits<T>::max() / 2;
	static constexpr T mvalue = std::numeric_limits<T>::min() / 2;
};
template <typename T>
constexpr T INF = infinity<T>::value;
constexpr ll lINF = INF<ll>;
constexpr int iINF = INF<int>;
constexpr ld PI = 3.1415926535897932384626;

void solve()
{
	ll N, M;
	cin >> N >> M;
	ll A[N + 1];
	rep(i, 1, N) cin >> A[i];
	ll B[M + 1];
	rep(i, 1, M) cin >> B[i];
	ll C[N + 1];
	rep(i, 1, N) cin >> C[i];
	ll D[M + 1];
	rep(i, 1, M) cin >> D[i];

	ll S1[N + 1];
	memset(S1, 0, sf(S1));
	rep(i, 1, N) S1[i] = S1[i - 1] + A[i];

	ll S2[M + 1];
	memset(S2, 0, sf(S2));
	rep(i, 1, M) S2[i] = S2[i - 1] + B[i];

	vl lstA[N + M + 1];
	vl lstB[N + M + 1];

	rep(i, 1, N) lstA[C[i]].pb(i);
	rep(j, 1, M) lstB[D[j]].pb(j);

	ll K = N + M;

	ll RES = -1;
	auto calcanswer = [&](ll x, ll y) -> void
	{
		if (C[x] != D[y])
			return;
		ll MN = min(min(N - x, x - 1), min(M - y, y - 1));
		ll tmp = S1[x + MN] - S1[x - MN - 1] + S2[y + MN] - S2[y - MN - 1];
		RES = max(RES, tmp);
		return;
	};

	rep(i, 1, K)
	{
		if (lstA[i].empty() || lstB[i].empty())
			continue;

		{
			ll at = -1;
			for (auto j : lstA[i])
				if (j - 1 <= N - j)
					at = j;

			if (at != -1)
			{
				for (auto k : lstB[i])
					calcanswer(at, k);
			}
		}

		{
			ll at = lINF / 2;
			for (auto j : lstA[i])
				if (j - 1 >= N - j)
					at = min(at, j);

			if (at != lINF / 2)
			{
				for (auto k : lstB[i])
					calcanswer(at, k);
			}
		}

		{
			ll at = -1;
			for (auto j : lstB[i])
				if (j - 1 <= M - j)
					at = j;

			if (at != -1)
			{
				for (auto k : lstA[i])
					calcanswer(k, at);
			}
		}

		{
			ll at = lINF / 2;
			for (auto j : lstB[i])
				if (j - 1 >= M - j)
					at = min(at, j);

			if (at != lINF / 2)
			{
				for (auto k : lstA[i])
					calcanswer(k, at);
			}
		}
	}

	cout << RES << endl;
}

void _main()
{

	ll t;
	cin >> t;
	while (t--)
		solve();
}
0