#1179153 (PyPy3) No.3637 PANDORA

• 問題: No.3637 PANDORA
• ユーザー: 👑 loop0919
• 提出日時: 2026-08-25 18:34:24
• 言語: PyPy3 (7.3.17)
• 結果: WA
• 実行時間: -
• コード長: 5,741 bytes
• コンパイル時間: 286 ms
• コンパイル使用メモリ: 95,852 KB
• 実行使用メモリ: 110,792 KB
• 最終ジャッジ日時: 2026-08-25 18:34:44
• 合計ジャッジ時間: 17,643 ms
• ジャッジサーバーID （参考情報）: judge1_0 / judge2_0

サブタスク	配点	結果
サンプル	0 %	AC * 1 WA * 1
小課題1	5 %	RE * 4
小課題2	10 %	AC * 4
小課題3	5 %	AC * 6 RE * 2
小課題4	10 %	AC * 5
小課題5	20 %	AC * 7 RE * 3
小課題6	20 %	AC * 16
小課題7	30 %	AC * 24 WA * 1 RE * 13
合計	40 点

ソースコード

# https://github.com/tatyam-prime/SortedSet/blob/main/SortedSet.py
import math
from bisect import bisect_left, bisect_right
from collections.abc import Iterable, Iterator
from typing import Generic, TypeVar

T = TypeVar("T")


class SortedSet(Generic[T]):
    BUCKET_RATIO = 16
    SPLIT_RATIO = 24

    def __init__(self, a: Iterable[T] = []) -> None:
        "Make a new SortedSet from iterable. / O(N) if sorted and unique / O(N log N)"
        a = list(a)
        n = len(a)
        if any(a[i] > a[i + 1] for i in range(n - 1)):
            a.sort()
        if any(a[i] >= a[i + 1] for i in range(n - 1)):
            a, b = [], a
            for x in b:
                if not a or a[-1] != x:
                    a.append(x)
        n = self.size = len(a)
        num_bucket = int(math.ceil(math.sqrt(n / self.BUCKET_RATIO)))
        self.a = [a[n * i // num_bucket : n * (i + 1) // num_bucket] for i in range(num_bucket)]

    def __iter__(self) -> Iterator[T]:
        for i in self.a:
            for j in i:
                yield j

    def __reversed__(self) -> Iterator[T]:
        for i in reversed(self.a):
            for j in reversed(i):
                yield j

    def __eq__(self, other) -> bool:
        return list(self) == list(other)

    def __len__(self) -> int:
        return self.size

    def __repr__(self) -> str:
        return "SortedSet" + str(self.a)

    def __str__(self) -> str:
        s = str(list(self))
        return "{" + s[1 : len(s) - 1] + "}"

    def _position(self, x: T) -> tuple[list[T], int, int]:
        "return the bucket, index of the bucket and position in which x should be. self must not be empty."
        for i, a in enumerate(self.a):
            if x <= a[-1]:
                break
        return (a, i, bisect_left(a, x))

    def __contains__(self, x: T) -> bool:
        if self.size == 0:
            return False
        a, _, i = self._position(x)
        return i != len(a) and a[i] == x

    def add(self, x: T) -> bool:
        "Add an element and return True if added. / O(√N)"
        if self.size == 0:
            self.a = [[x]]
            self.size = 1
            return True
        a, b, i = self._position(x)
        if i != len(a) and a[i] == x:
            return False
        a.insert(i, x)
        self.size += 1
        if len(a) > len(self.a) * self.SPLIT_RATIO:
            mid = len(a) >> 1
            self.a[b : b + 1] = [a[:mid], a[mid:]]
        return True

    def _pop(self, a: list[T], b: int, i: int) -> T:
        ans = a.pop(i)
        self.size -= 1
        if not a:
            del self.a[b]
        return ans

    def discard(self, x: T) -> bool:
        "Remove an element and return True if removed. / O(√N)"
        if self.size == 0:
            return False
        a, b, i = self._position(x)
        if i == len(a) or a[i] != x:
            return False
        self._pop(a, b, i)
        return True

    def lt(self, x: T) -> T | None:
        "Find the largest element < x, or None if it doesn't exist."
        for a in reversed(self.a):
            if a[0] < x:
                return a[bisect_left(a, x) - 1]

    def le(self, x: T) -> T | None:
        "Find the largest element <= x, or None if it doesn't exist."
        for a in reversed(self.a):
            if a[0] <= x:
                return a[bisect_right(a, x) - 1]

    def gt(self, x: T) -> T | None:
        "Find the smallest element > x, or None if it doesn't exist."
        for a in self.a:
            if a[-1] > x:
                return a[bisect_right(a, x)]

    def ge(self, x: T) -> T | None:
        "Find the smallest element >= x, or None if it doesn't exist."
        for a in self.a:
            if a[-1] >= x:
                return a[bisect_left(a, x)]

    def __getitem__(self, i: int) -> T:
        "Return the i-th element."
        if i < 0:
            for a in reversed(self.a):
                i += len(a)
                if i >= 0:
                    return a[i]
        else:
            for a in self.a:
                if i < len(a):
                    return a[i]
                i -= len(a)
        raise IndexError

    def pop(self, i: int = -1) -> T:
        "Pop and return the i-th element."
        if i < 0:
            for b, a in enumerate(reversed(self.a)):
                i += len(a)
                if i >= 0:
                    return self._pop(a, ~b, i)
        else:
            for b, a in enumerate(self.a):
                if i < len(a):
                    return self._pop(a, b, i)
                i -= len(a)
        raise IndexError

    def index(self, x: T) -> int:
        "Count the number of elements < x."
        ans = 0
        for a in self.a:
            if a[-1] >= x:
                return ans + bisect_left(a, x)
            ans += len(a)
        return ans

    def index_right(self, x: T) -> int:
        "Count the number of elements <= x."
        ans = 0
        for a in self.a:
            if a[-1] > x:
                return ans + bisect_right(a, x)
            ans += len(a)
        return ans


sigma = 26

N, Q = [int(s) for s in input().split()]
S = [ord(s) - ord("a") for s in input()]

index = [SortedSet() for _ in range(sigma)]
for i, s in enumerate(S):
    index[s].add(i)

for _ in range(Q):
    cmd, *query = input().split()
    cmd = int(cmd)

    if cmd == 1:
        i, c = query
        i, c = int(i), ord(c) - ord("a")

        pre, to = S[i], c
        index[pre].discard(i)
        index[to].add(i)

    else:
        T = [ord(t) - ord("a") for t in query[0]]
        curr = -1
        for t in T:
            curr = index[t].gt(curr)
            if curr is None:
                print("No")
                break
        else:
            print("Yes")