結果
| 問題 | No.2251 Marking Grid |
| コンテスト | |
| ユーザー |
detteiuu
|
| 提出日時 | 2026-08-29 17:56:18 |
| 言語 | PyPy3 (7.3.23 + ACL) |
| 結果 |
AC
不安定
|
| 実行時間 | 2,062 ms / 3,000 ms |
| + 987µs | |
| コード長 | 2,153 bytes |
| 記録 | |
| コンパイル時間 | 260 ms |
| コンパイル使用メモリ | 96,104 KB |
| 実行使用メモリ | 258,388 KB |
| 最終ジャッジ日時 | 2026-08-29 17:56:44 |
| 合計ジャッジ時間 | 20,925 ms |
|
ジャッジサーバーID (参考情報) |
judge1_0 / judge2_1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 40 |
ソースコード
def op(x, y):
return x|y
class UnionFind:
def __init__(self, n, A, op):
self.n = n
self.parent_size = [-1]*n
self.A = A[:]
self.op = op
def leader(self, a):
if self.parent_size[a] < 0:
return a
self.parent_size[a] = self.leader(self.parent_size[a])
return self.parent_size[a]
def merge(self, a, b):
x, y = self.leader(a), self.leader(b)
if x == y:
return
l, r = self.A[x], self.A[y]
if abs(self.parent_size[x]) < abs(self.parent_size[y]):
x, y = y, x
self.parent_size[x] += self.parent_size[y]
self.parent_size[y] = x
self.A[x] = self.op(l, r)
return
def __getitem__(self, n):
return self.A[self.leader(n)]
def update(self, n, a):
self.A[self.leader(n)] = a
def same(self, a, b):
return self.leader(a) == self.leader(b)
def size(self, a):
return abs(self.parent_size[self.leader(a)])
def groups(self):
result = [[] for _ in range(self.n)]
for i in range(self.n):
result[self.leader(i)].append(i)
return [r for r in result if r != []]
MOD = 998244353
H, W = map(int, input().split())
A = [list(map(int, input().split())) for _ in range(H)]
POW = [1]
for _ in range(H+W):
POW.append(POW[-1]*2%MOD)
B = sorted([(i, j, A[i][j]) for i in range(H) for j in range(W)], key=lambda x:x[2], reverse=True)
rank = [[-1]*W for _ in range(H)]
IDX = [-1]*H
for idx, (i, j, a) in enumerate(B):
rank[i][j] = idx
if IDX[i] == -1: IDX[i] = j
FH = [False]*H
cntH = H
UF = [UnionFind(W, [0]*W, op) for _ in range(H)]
cnt = [W]*H
ans = 0
for i, j, a in B:
if not FH[i]:
FH[i] = True
cntH -= 1
if UF[i][j] == 0:
cnt[i] -= 1
flag = UF[i][j] == 0
UF[i].update(j, 1)
if flag:
ans += a*POW[cntH+cnt[i]]%MOD
ans %= MOD
if IDX[i] != j and not UF[0].same(IDX[i], j):
for k in range(H):
if UF[k][IDX[i]] == 0 or UF[k][j] == 0:
cnt[k] -= 1
UF[k].merge(IDX[i], j)
print(ans)
detteiuu