結果

問題 No.1050 Zero (Maximum)
コンテスト
ユーザー C
提出日時 2026-10-28 14:45:04
言語 C++23(gcc16)
(gcc 16.2.0 + boost 1.92.0 + ACL)
コンパイル:
g++-16 -O2 -fplugin=/usr/lib/yukicoder/noavx512-gcc16.so -lm -std=c++23 -Wuninitialized -DONLINE_JUDGE -o a.out _filename_
実行:
./a.out
結果
AC  
実行時間 1 ms / 2,000 ms
+ 866µs
コード長 11,291 bytes
記録
記録タグの例:
初AC ショートコード 純ショートコード 純主流ショートコード 最速実行時間
コンパイル時間 9,125 ms
コンパイル使用メモリ 399,816 KB
実行使用メモリ 6,400 KB
最終ジャッジ日時 2026-10-28 14:45:23
合計ジャッジ時間 9,882 ms
ジャッジサーバーID
(参考情報)
judge3_0 / judge7_0
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 15
権限があれば一括ダウンロードができます

ソースコード

diff #
raw source code

#include <bits/stdc++.h>
#include <atcoder/all>
#include <boost/polygon/point_data.hpp>
#include <boost/polygon/voronoi.hpp>
#define rep(i,a,b) for(int i=(a);i<(b);i++)
#define rrep(i,a,b) for(int i=(b)-1;i>=(a);i--)
#define all(x) begin(x),end(x)
#define sz(x) (int)(x).size()
using namespace std;
using namespace atcoder;
using ll=long long;
using ld=long double;
using vll=vector<ll>;
using vvll=vector<vll>;
using vi=vector<int>;
using vvi=vector<vi>;
using pll=pair<ll,ll>;
using pi=pair<int,int>;

// using mint=modint998244353;
using mint=modint1000000007;
// using mint2=static_modint<2>;

// using BoostPoint=boost::polygon::point_data<int>;
// using Voronoi=boost::polygon::voronoi_diagram<double>;

#line 2 "prime/osak.hpp"

#line 2 "prime/factor-enumerate.hpp"

vector<int> factor_enumerate(int N) {
  vector<int> lp(N + 1, 0);
  if (N < 2) return lp;
  vector<int> pr{2, 3};
  for (int i = 2; i <= N; i += 2) lp[i] = 2;
  for (int i = 3; i <= N; i += 6) lp[i] = 3;
  for (int i = 5, d = 4; i <= N; i += d = 6 - d) {
    if (lp[i] == 0) {
      lp[i] = i;
      pr.push_back(i);
    }
    for (int j = 2; j < (int)pr.size() && i * pr[j] <= N; ++j) {
      lp[i * pr[j]] = pr[j];
      if (pr[j] == lp[i]) break;
    }
  }
  return lp;
}
#line 4 "prime/osak.hpp"

template <int MAX>
vector<int> osak(int n) {
  static vector<int> f = factor_enumerate(MAX);
  vector<int> ret;
  while (f[n]) ret.push_back(f[n]), n /= f[n];
  return ret;
}

template <int MAX>
vector<pair<int, int>> osak_table(int n) {
  static vector<int> f = factor_enumerate(MAX);
  vector<pair<int, int>> v;
  for (; f[n]; n /= f[n]) {
    if (v.empty() || v.back().first != f[n]) {
      v.emplace_back(f[n], 1);
    } else {
      v.back().second++;
    }
  }
  return v;
}

template <int MAX>
vector<int> osak_divisors(int n) {
  if(n == 0) return {};
  if(n == 1) return vector<int>(1, 1);
  auto p = osak_table<MAX>(n);
  vector<int> ds;

  auto dfs = [&](auto r, int i, int c) {
    if (i == (int)p.size()) {
      ds.push_back(c);
      return;
    }
    for (int j = 0; j <= p[i].second; j++) {
      r(r, i + 1, c);
      c *= p[i].first;
    }
  };

  dfs(dfs, 0, 1);
  sort(begin(ds), end(ds));
  return ds;
}

#line 2 "math/elementary-function.hpp"

// totient function φ(N)=(1 ~ N , gcd(i,N) = 1)
// {0, 1, 1, 2, 4, 2, 6, 4, ... }
vector<int> EulersTotientFunction(int N) {
  vector<int> ret(N + 1, 0);
  for (int i = 0; i <= N; i++) ret[i] = i;
  for (int i = 2; i <= N; i++) {
    if (ret[i] == i)
      for (int j = i; j <= N; j += i) ret[j] = ret[j] / i * (i - 1);
  }
  return ret;
}

// Divisor ex) 12 -> {1, 2, 3, 4, 6, 12}
vector<long long> Divisor(long long N) {
  vector<long long> v;
  for (long long i = 1; i * i <= N; i++) {
    if (N % i == 0) {
      v.push_back(i);
      if (i * i != N) v.push_back(N / i);
    }
  }
  return v;
}

// Factorization
// ex) 18 -> { (2,1) , (3,2) }
vector<pair<long long, int> > PrimeFactors(long long N) {
  vector<pair<long long, int> > ret;
  for (long long p = 2; p * p <= N; p++)
    if (N % p == 0) {
      ret.emplace_back(p, 0);
      while (N % p == 0) N /= p, ret.back().second++;
    }
  if (N >= 2) ret.emplace_back(N, 1);
  return ret;
}

// Factorization with Prime Sieve
// ex) 18 -> { (2,1) , (3,2) }
vector<pair<long long, int> > PrimeFactors(long long N,
                                           const vector<long long> &prime) {
  vector<pair<long long, int> > ret;
  for (auto &p : prime) {
    if (p * p > N) break;
    if (N % p == 0) {
      ret.emplace_back(p, 0);
      while (N % p == 0) N /= p, ret.back().second++;
    }
  }
  if (N >= 2) ret.emplace_back(N, 1);
  return ret;
}

// modpow for mod < 2 ^ 31
long long modpow(long long a, long long n, long long mod) {
  a %= mod;
  long long ret = 1;
  while (n > 0) {
    if (n & 1) ret = ret * a % mod;
    a = a * a % mod;
    n >>= 1;
  }
  return ret % mod;
};

// Check if r is Primitive Root
bool isPrimitiveRoot(long long r, long long mod) {
  r %= mod;
  if (r == 0) return false;
  auto pf = PrimeFactors(mod - 1);
  for (auto &x : pf) {
    if (modpow(r, (mod - 1) / x.first, mod) == 1) return false;
  }
  return true;
}

// Get Primitive Root
long long PrimitiveRoot(long long mod) {
  if(mod == 2) return 1;
  long long ret = 1;
  while (isPrimitiveRoot(ret, mod) == false) ret++;
  return ret;
}

// Euler's phi function
long long phi(long long n) {
  auto pf = PrimeFactors(n);
  long long ret = n;
  for (auto p : pf) {
    ret /= p.first;
    ret *= (p.first - 1);
  }
  return ret;
}

// Extended Euclidean algorithm
// solve : ax + by = gcd(a, b)
// return : pair(x, y)
// a>=0,b>=0 でない場合 gcd(a, b) は負にもなり得るので注意
pair<long long, long long> extgcd(long long a, long long b) {
  if (b == 0) return make_pair(1, 0);
  long long x, y;
  tie(y, x) = extgcd(b, a % b);
  y -= a / b * x;
  return make_pair(x, y);
}

// Check if n is Square Number
// true : return d s.t. d * d == n
// false : return -1
long long SqrtInt(long long n) {
  if (n == 0 || n == 1) return n;
  long long d = (long long)sqrt(n) - 1;
  while (d * d < n) ++d;
  return (d * d == n) ? d : -1;
}

// return a number of n's digit
// zero ... return value if n = 0 (default -> 1)
int isDigit(long long n, int zero = 1) {
  if (n == 0) return zero;
  int ret = 0;
  while (n) {
    n /= 10;
    ret++;
  }
  return ret;
}

#line 2 "matrix/matrix.hpp"

#line 2 "matrix/inverse-matrix.hpp"

#line 2 "matrix/gauss-elimination.hpp"

#include <utility>
#include <vector>
using namespace std;

// {rank, det(非正方行列の場合は未定義)} を返す
// 型が double や Rational でも動くはず?(未検証)
//
// pivot 候補 : [0, pivot_end)
template <typename T>
std::pair<int, T> GaussElimination(vector<vector<T>> &a, int pivot_end = -1,
                                   bool diagonalize = false) {
  if (a.empty()) return {0, 1};
  int H = a.size(), W = a[0].size(), rank = 0;
  if (pivot_end == -1) pivot_end = W;
  T det = 1;
  for (int j = 0; j < pivot_end; j++) {
    int idx = -1;
    for (int i = rank; i < H; i++) {
      if (a[i][j] != T(0)) {
        idx = i;
        break;
      }
    }
    if (idx == -1) {
      det = 0;
      continue;
    }
    if (rank != idx) det = -det, swap(a[rank], a[idx]);
    det *= a[rank][j];
    if (diagonalize && a[rank][j] != T(1)) {
      T coeff = T(1) / a[rank][j];
      for (int k = j; k < W; k++) a[rank][k] *= coeff;
    }
    int is = diagonalize ? 0 : rank + 1;
    for (int i = is; i < H; i++) {
      if (i == rank) continue;
      if (a[i][j] != T(0)) {
        T coeff = a[i][j] / a[rank][j];
        for (int k = j; k < W; k++) a[i][k] -= a[rank][k] * coeff;
      }
    }
    rank++;
  }
  return make_pair(rank, det);
}
#line 4 "matrix/inverse-matrix.hpp"

template <typename mint>
vector<vector<mint>> inverse_matrix(const vector<vector<mint>>& a) {
  int N = a.size();
  assert(N > 0);
  assert(N == (int)a[0].size());

  vector<vector<mint>> m(N, vector<mint>(2 * N));
  for (int i = 0; i < N; i++) {
    copy(begin(a[i]), end(a[i]), begin(m[i]));
    m[i][N + i] = 1;
  }

  auto [rank, det] = GaussElimination(m, N, true);
  if (rank != N) return {};

  vector<vector<mint>> b(N);
  for (int i = 0; i < N; i++) {
    copy(begin(m[i]) + N, end(m[i]), back_inserter(b[i]));
  }
  return b;
}
#line 4 "matrix/matrix.hpp"

template <class T>
struct Matrix {
  vector<vector<T> > A;

  Matrix() = default;
  Matrix(int n, int m) : A(n, vector<T>(m, T())) {}
  Matrix(int n) : A(n, vector<T>(n, T())){};

  int H() const { return A.size(); }

  int W() const { return A[0].size(); }

  int size() const { return A.size(); }

  inline const vector<T> &operator[](int k) const { return A[k]; }

  inline vector<T> &operator[](int k) { return A[k]; }

  static Matrix I(int n) {
    Matrix mat(n);
    for (int i = 0; i < n; i++) mat[i][i] = 1;
    return (mat);
  }

  Matrix &operator+=(const Matrix &B) {
    int n = H(), m = W();
    assert(n == B.H() && m == B.W());
    for (int i = 0; i < n; i++)
      for (int j = 0; j < m; j++) (*this)[i][j] += B[i][j];
    return (*this);
  }

  Matrix &operator-=(const Matrix &B) {
    int n = H(), m = W();
    assert(n == B.H() && m == B.W());
    for (int i = 0; i < n; i++)
      for (int j = 0; j < m; j++) (*this)[i][j] -= B[i][j];
    return (*this);
  }

  Matrix &operator*=(const Matrix &B) {
    int n = H(), m = B.W(), p = W();
    assert(p == B.H());
    vector<vector<T> > C(n, vector<T>(m, T{}));
    for (int i = 0; i < n; i++)
      for (int k = 0; k < p; k++)
        for (int j = 0; j < m; j++) C[i][j] += (*this)[i][k] * B[k][j];
    A.swap(C);
    return (*this);
  }

  Matrix &operator^=(long long k) {
    Matrix B = Matrix::I(H());
    while (k > 0) {
      if (k & 1) B *= *this;
      *this *= *this;
      k >>= 1LL;
    }
    A.swap(B.A);
    return (*this);
  }

  Matrix operator+(const Matrix &B) const { return (Matrix(*this) += B); }

  Matrix operator-(const Matrix &B) const { return (Matrix(*this) -= B); }

  Matrix operator*(const Matrix &B) const { return (Matrix(*this) *= B); }

  Matrix operator^(const long long k) const { return (Matrix(*this) ^= k); }

  bool operator==(const Matrix &B) const {
    assert(H() == B.H() && W() == B.W());
    for (int i = 0; i < H(); i++)
      for (int j = 0; j < W(); j++)
        if (A[i][j] != B[i][j]) return false;
    return true;
  }

  bool operator!=(const Matrix &B) const {
    assert(H() == B.H() && W() == B.W());
    for (int i = 0; i < H(); i++)
      for (int j = 0; j < W(); j++)
        if (A[i][j] != B[i][j]) return true;
    return false;
  }

  Matrix inverse() const {
    assert(H() == W());
    Matrix B(H());
    B.A = inverse_matrix(A);
    return B;
  }

  friend ostream &operator<<(ostream &os, const Matrix &p) {
    int n = p.H(), m = p.W();
    for (int i = 0; i < n; i++) {
      os << (i ? "   " : "") << "[";
      for (int j = 0; j < m; j++) {
        os << p[i][j] << (j + 1 == m ? "]\n" : ",");
      }
    }
    return (os);
  }

  T determinant() const {
    Matrix B(*this);
    assert(H() == W());
    T ret = 1;
    for (int i = 0; i < H(); i++) {
      int idx = -1;
      for (int j = i; j < W(); j++) {
        if (B[j][i] != 0) {
          idx = j;
          break;
        }
      }
      if (idx == -1) return 0;
      if (i != idx) {
        ret *= T(-1);
        swap(B[i], B[idx]);
      }
      ret *= B[i][i];
      T inv = T(1) / B[i][i];
      for (int j = 0; j < W(); j++) {
        B[i][j] *= inv;
      }
      for (int j = i + 1; j < H(); j++) {
        T a = B[j][i];
        if (a == 0) continue;
        for (int k = i; k < W(); k++) {
          B[j][k] -= B[i][k] * a;
        }
      }
    }
    return ret;
  }
};

/**
 * @brief 行列ライブラリ
 */

int main()
{
	//gcd(x,M), x = 0,...,M-1を頂点にしたグラフを考えます
	//頂点数はMの約数の個数なので、より高速で解けます
  	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	int M,K;
	cin>>M>>K;
	vi divisors=osak_divisors<50>(M);
	int D=divisors.size();
	vi phi=EulersTotientFunction(M);
	Matrix<mint>A(D);
	rep(j,0,D){
		int gcdj=divisors[j];
		rep(i,0,D){
			int gcdi=divisors[i];
			int ways=1+(gcdi%gcdj==0?gcdj:0);
			A[i][j]=phi[M/gcdi]*ways;
		}
	}
	A^=K;
	cout<<A[D-1][D-1].val()<<'\n';
}
0