結果
| 問題 | No.3780 Erase and Mex |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2026-10-30 22:29:45 |
| 言語 | PyPy3 (8.0.0 + ACL) |
| 結果 |
AC
不安定
|
| 実行時間 | 246 ms / 2,000 ms |
| + 753µs | |
| コード長 | 2,500 bytes |
| 記録 | |
| コンパイル時間 | 104 ms |
| コンパイル使用メモリ | 64,024 KB |
| 実行使用メモリ | 91,256 KB |
| 最終ジャッジ日時 | 2026-10-30 22:29:56 |
| 合計ジャッジ時間 | 10,844 ms |
|
ジャッジサーバーID (参考情報) |
judge1_0 / judge4_0 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 43 |
ソースコード
# haru: pypy
import sys
input = sys.stdin.readline
II = lambda : int(input())
MI = lambda : map(int, input().split())
LI = lambda : [int(a) for a in input().split()]
SI = lambda : input().rstrip()
LLI = lambda n : [[int(a) for a in input().split()] for _ in range(n)]
LSI = lambda n : [input().rstrip() for _ in range(n)]
MI_1 = lambda : map(lambda x:int(x)-1, input().split())
LI_1 = lambda : [int(a)-1 for a in input().split()]
mod = 998244353
inf = 1001001001001001001
ordalp = lambda s : ord(s)-65 if s.isupper() else ord(s)-97
ordallalp = lambda s : ord(s)-39 if s.isupper() else ord(s)-97
yes = lambda : print("Yes")
no = lambda : print("No")
yn = lambda flag : print("Yes" if flag else "No")
prinf = lambda ans : print(ans if ans < 1000001001001001001 else -1)
alplow = "abcdefghijklmnopqrstuvwxyz"
alpup = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
alpall = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
URDL = {'U':(-1,0), 'R':(0,1), 'D':(1,0), 'L':(0,-1)}
DIR_4 = [[-1,0],[0,1],[1,0],[0,-1]]
DIR_8 = [[-1,0],[-1,1],[0,1],[1,1],[1,0],[1,-1],[0,-1],[-1,-1]]
DIR_BISHOP = [[-1,1],[1,1],[1,-1],[-1,-1]]
prime60 = [2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59]
sys.set_int_max_str_digits(0)
# sys.setrecursionlimit(10**6)
# import pypyjit
# pypyjit.set_param('max_unroll_recursion=-1')
from collections import defaultdict,deque
from heapq import heappop,heappush
from bisect import bisect_left,bisect_right
DD = defaultdict
BSL = bisect_left
BSR = bisect_right
def solve():
n = II()
a = LI()
c = DD(int)
for x in a:
c[x] += 1
if n == 1:
if a[0] == 0:
print(1)
else:
print(a[0])
return
# 2 以上は必ず計算する
# つまり mex 操作で生み出される必要がある
def check(m):
z = 0
for v, cc in c.items():
if v >= m:
z += cc
nc = 1
for i in reversed(range(m)):
# print(m, i, nc, z)
if i == 0:
return nc <= c[0] + z
if nc <= c[i]:
z += c[i] - nc
else:
nc += nc - c[i]
if nc >= 10 ** 6:
return False
ok = 0
ng = n + 100
while ng - ok > 1:
m = ok + ng >> 1
if check(m):
ok = m
else:
ng = m
print(ok)
return
t = int(input())
for i in range(t):
solve()