結果

問題 No.456 Millions of Submits!
ユーザー shimomire
提出日時 2016-12-07 22:51:53
言語 C++11
(gcc 13.3.0)
結果
OLE  
(最新)
AC  
(最初)
実行時間 -
コード長 5,140 bytes
コンパイル時間 1,082 ms
コンパイル使用メモリ 115,716 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-06-23 03:10:24
合計ジャッジ時間 5,949 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 12 OLE * 1
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ソースコード

diff #
プレゼンテーションモードにする

#include <cassert>// c
#include <iostream>// io
#include <iomanip>
#include <fstream>
#include <sstream>
#include <vector>// container
#include <map>
#include <set>
#include <queue>
#include <bitset>
#include <stack>
#include <algorithm>// other
#include <complex>
#include <numeric>
#include <functional>
#include <random>
#include <regex>
using namespace std;
typedef long long ll;typedef unsigned long long ull;typedef long double ld;
#define ALL(c) c.begin(),c.end()
#define IN(l,v,r) (l<=v && v < r)
template<class T> void UNIQUE(T& v){v.erase(unique(ALL(v)),v.end());}
//debug
#define DUMP(x) cerr << #x <<" = " << (x)
#define LINE() cerr<< " (L" << __LINE__ << ")"
struct range{
    struct Iter{
        int v,step;
        Iter& operator++(){v+=step;return *this;}
        bool operator!=(Iter& itr){return v<itr.v;}
        int& operator*(){return v;}
    };
    Iter i, n;
    range(int i, int n,int step):i({i,step}), n({n,step}){}
    range(int i, int n):range(i,n,1){}
    range(int n):range(0,n){}
    Iter& begin(){return i;}
    Iter& end(){return n;}
};
struct rrange{
    struct Iter{
        int v,step;
        Iter& operator++(){v-=step;return *this;}
        bool operator!=(Iter& itr){return v>itr.v;}
        int& operator*(){return v;}
    };
    Iter i, n;
    rrange(int i, int n,int step):i({i-1,step}), n({n-1,step}){}
    rrange(int i, int n):rrange(i,n,1){}
    rrange(int n) :rrange(0,n){}
    Iter& begin(){return n;}
    Iter& end(){return i;}
};
//input
template<typename T1,typename T2> istream& operator >> (istream& is,pair<T1,T2>& p){return is>>p.first>>p.second;}
template<typename T1> istream& operator >> (istream& is,tuple<T1>& t){return is >> get<0>(t);}
template<typename T1,typename T2> istream& operator >> (istream& is,tuple<T1,T2>& t){return is >> get<0>(t) >> get<1>(t);}
template<typename T1,typename T2,typename T3> istream& operator >> (istream& is,tuple<T1,T2,T3>& t){return is >>get<0>(t)>>get<1>(t)>>get<2>(t);}
template<typename T1,typename T2,typename T3,typename T4> istream& operator >> (istream& is,tuple<T1,T2,T3,T4>& t){return is >> get<0>(t)>>get<1>(t
    )>>get<2>(t)>>get<3>(t);}
template<typename T> istream& operator >> (istream& is,vector<T>& as){for(int i:range(as.size()))is >>as[i];return is;}
//output
template<typename T> ostream& operator << (ostream& os, const set<T>& ss){for(auto a:ss){if(a!=ss.begin())os<<" "; os<<a;}return os;}
template<typename T1,typename T2> ostream& operator << (ostream& os, const pair<T1,T2>& p){return os<<p.first<<" "<<p.second;}
template<typename K,typename V> ostream& operator << (ostream& os, const map<K,V>& m){bool isF=true;for(auto& p:m){if(!isF)os<<endl;os<<p;isF=false
    ;}return os;}
template<typename T1> ostream& operator << (ostream& os, const tuple<T1>& t){return os << get<0>(t);}
template<typename T1,typename T2> ostream& operator << (ostream& os, const tuple<T1,T2>& t){return os << get<0>(t)<<" "<<get<1>(t);}
template<typename T1,typename T2,typename T3> ostream& operator << (ostream& os, const tuple<T1,T2,T3>& t){return os << get<0>(t)<<" "<<get<1>(t)<<" 
    "<<get<2>(t);}
template<typename T1,typename T2,typename T3,typename T4> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4>& t){return os << get<0>(t)<<" "
    <<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t);}
template<typename T> ostream& operator << (ostream& os, const vector<T>& as){for(int i:range(as.size())){if(i!=0)os<<" "; os<<as[i];}return os;}
template<typename T> ostream& operator << (ostream& os, const vector<vector<T>>& as){for(int i:range(as.size())){if(i!=0)os<<endl; os<<as[i];}return 
    os;}
// values
template<typename T> inline T INF(){assert(false);};
template<> inline int INF<int>(){return 1<<28;};
template<> inline ll INF<ll>(){return 1LL<<60;};
template<> inline double INF<double>(){return 1e16;};
template<> inline long double INF<long double>(){return 1e16;};
template<class T> inline T EPS(){assert(false);};
template<> inline int EPS<int>(){return 1;};
template<> inline ll EPS<ll>(){return 1LL;};
template<> inline double EPS<double>(){return 1e-8;};
template<> inline long double EPS<long double>(){return 1e-8;};
// min{2^r | n < 2^r}
template<typename T> inline T upper_pow2(T n){ T res=1;while(res<n)res<<=1;return res;}
// max{d | 2^d  <= n}
template<typename T> inline T msb(T n){ int d=62;while((1LL<<d)>n)d--;return d;}
template<typename T,typename U> T pmod(T v,U M){return (v%M+M)%M;}
class Main{
    public:
    inline double pw(double m,int a){
        double res = 1;
        while(a){
            if(a&1) res *= m;
            m *= m;
            a/=2;
        }
        return res;
    }
    void run(){
        int m;cin >> m;
        for(int i:range(m)){
            double a,b; double t;cin >> a >> b >> t;
            if(a == 0){
                if(i%1000 == 0) cout << exp(pow(t,1/b)) << endl;
                else cout << exp(pow(t,1/b)) << "\n";
            }else if(b == 0){
                if(i%1000 == 0) cout << pow(t,1/a) << endl;
                else cout << pow(t,1/a) << "\n";
            }else{
                double l=0, r = 10 + EPS<double>();
                for(int c:range(35)){
                    double m=(l+r)/2;
                    ((pw(m,a)*pw(log(m),b)<=t)?l:r)=m;
                }
                if(i%1000 == 0) cout << l << endl;
                else cout << l << "\n";
            }
        }
        cout << flush;
    }
};
int main(){
    cout <<fixed<<setprecision(20);
    cin.tie(0);
    ios::sync_with_stdio(false);
    Main().run();
    return 0;
}
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