結果
問題 | No.455 冬の大三角 |
ユーザー |
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提出日時 | 2016-12-08 00:31:18 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 3 ms / 2,000 ms |
コード長 | 5,100 bytes |
コンパイル時間 | 1,218 ms |
コンパイル使用メモリ | 122,828 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-06-29 21:23:11 |
合計ジャッジ時間 | 3,035 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 54 |
コンパイルメッセージ
In member function 'void Main::run()', inlined from 'int main()' at main.cpp:133:12: main.cpp:119:58: warning: 'x2' may be used uninitialized [-Wmaybe-uninitialized] 119 | if((y2-y1)*(x3-x1) == (y3-y1)*(x2-x1)) continue; | ~~~^~~~ main.cpp: In function 'int main()': main.cpp:103:36: note: 'x2' was declared here 103 | int y1=-1,x1=-1,y2,x2; | ^~ In member function 'void Main::run()', inlined from 'int main()' at main.cpp:133:12: main.cpp:119:31: warning: 'y2' may be used uninitialized [-Wmaybe-uninitialized] 119 | if((y2-y1)*(x3-x1) == (y3-y1)*(x2-x1)) continue; | ~~~^~~~ main.cpp: In function 'int main()': main.cpp:103:33: note: 'y2' was declared here 103 | int y1=-1,x1=-1,y2,x2; | ^~
ソースコード
#include <cassert>// c#include <iostream>// io#include <iomanip>#include <fstream>#include <sstream>#include <vector>// container#include <map>#include <set>#include <queue>#include <bitset>#include <stack>#include <algorithm>// other#include <complex>#include <numeric>#include <functional>#include <random>#include <regex>using namespace std;typedef long long ll;typedef unsigned long long ull;typedef long double ld;#define ALL(c) c.begin(),c.end()#define IN(l,v,r) (l<=v && v < r)template<class T> void UNIQUE(T& v){v.erase(unique(ALL(v)),v.end());}//debug#define DUMP(x) cerr << #x <<" = " << (x)#define LINE() cerr<< " (L" << __LINE__ << ")"struct range{struct Iter{int v,step;Iter& operator++(){v+=step;return *this;}bool operator!=(Iter& itr){return v<itr.v;}int& operator*(){return v;}};Iter i, n;range(int i, int n,int step):i({i,step}), n({n,step}){}range(int i, int n):range(i,n,1){}range(int n):range(0,n){}Iter& begin(){return i;}Iter& end(){return n;}};struct rrange{struct Iter{int v,step;Iter& operator++(){v-=step;return *this;}bool operator!=(Iter& itr){return v>itr.v;}int& operator*(){return v;}};Iter i, n;rrange(int i, int n,int step):i({i-1,step}), n({n-1,step}){}rrange(int i, int n):rrange(i,n,1){}rrange(int n) :rrange(0,n){}Iter& begin(){return n;}Iter& end(){return i;}};//inputtemplate<typename T1,typename T2> istream& operator >> (istream& is,pair<T1,T2>& p){return is>>p.first>>p.second;}template<typename T1> istream& operator >> (istream& is,tuple<T1>& t){return is >> get<0>(t);}template<typename T1,typename T2> istream& operator >> (istream& is,tuple<T1,T2>& t){return is >> get<0>(t) >> get<1>(t);}template<typename T1,typename T2,typename T3> istream& operator >> (istream& is,tuple<T1,T2,T3>& t){return is >>get<0>(t)>>get<1>(t)>>get<2>(t);}template<typename T1,typename T2,typename T3,typename T4> istream& operator >> (istream& is,tuple<T1,T2,T3,T4>& t){return is >> get<0>(t)>>get<1>(t)>>get<2>(t)>>get<3>(t);}template<typename T> istream& operator >> (istream& is,vector<T>& as){for(int i:range(as.size()))is >>as[i];return is;}//outputtemplate<typename T> ostream& operator << (ostream& os, const set<T>& ss){for(auto a:ss){if(a!=ss.begin())os<<" "; os<<a;}return os;}template<typename T1,typename T2> ostream& operator << (ostream& os, const pair<T1,T2>& p){return os<<p.first<<" "<<p.second;}template<typename K,typename V> ostream& operator << (ostream& os, const map<K,V>& m){bool isF=true;for(auto& p:m){if(!isF)os<<endl;os<<p;isF=false;}return os;}template<typename T1> ostream& operator << (ostream& os, const tuple<T1>& t){return os << get<0>(t);}template<typename T1,typename T2> ostream& operator << (ostream& os, const tuple<T1,T2>& t){return os << get<0>(t)<<" "<<get<1>(t);}template<typename T1,typename T2,typename T3> ostream& operator << (ostream& os, const tuple<T1,T2,T3>& t){return os << get<0>(t)<<" "<<get<1>(t)<<""<<get<2>(t);}template<typename T1,typename T2,typename T3,typename T4> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4>& t){return os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t);}template<typename T> ostream& operator << (ostream& os, const vector<T>& as){for(int i:range(as.size())){if(i!=0)os<<" "; os<<as[i];}return os;}template<typename T> ostream& operator << (ostream& os, const vector<vector<T>>& as){for(int i:range(as.size())){if(i!=0)os<<endl; os<<as[i];}returnos;}// valuestemplate<typename T> inline T INF(){assert(false);};template<> inline int INF<int>(){return 1<<28;};template<> inline ll INF<ll>(){return 1LL<<60;};template<> inline double INF<double>(){return 1e16;};template<> inline long double INF<long double>(){return 1e16;};template<class T> inline T EPS(){assert(false);};template<> inline int EPS<int>(){return 1;};template<> inline ll EPS<ll>(){return 1LL;};template<> inline double EPS<double>(){return 1e-8;};template<> inline long double EPS<long double>(){return 1e-8;};// min{2^r | n < 2^r}template<typename T> inline T upper_pow2(T n){ T res=1;while(res<n)res<<=1;return res;}// max{d | 2^d <= n}template<typename T> inline T msb(T n){ int d=62;while((1LL<<d)>n)d--;return d;}template<typename T,typename U> T pmod(T v,U M){return (v%M+M)%M;}class Main{public:void run(){int H,W;cin >> H >> W;vector<string> board(H);cin >> board;int y1=-1,x1=-1,y2,x2;for(int y:range(H))for(int x:range(W)){if(board[y][x]=='*'){if(y1==-1) y1 = y,x1 = x;else y2 = y, x2 = x;}}// 適当に y1 の周りをまわって1直線上じゃなければ ok.int dy[] = {0,1,1,1,0,-1,-1,-1};int dx[] = {1,1,0,-1,-1,-1,0,1};for(int d:range(8)){int y3 = y1 + dy[d], x3 = x1 + dx[d];if(!IN(0,y3,H) || !IN(0,x3,W)) continue;if((y2-y1)*(x3-x1) == (y3-y1)*(x2-x1)) continue;board[y3][x3] = '*';break;}for(int y:range(H)){cout << board[y] << endl;}}};int main(){cout <<fixed<<setprecision(10);cin.tie(0);ios::sync_with_stdio(false);Main().run();return 0;}