結果

問題 No.460 裏表ちわーわ
ユーザー koyumeishi
提出日時 2016-12-11 06:04:57
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 12 ms / 2,000 ms
コード長 6,659 bytes
コンパイル時間 1,642 ms
コンパイル使用メモリ 127,096 KB
実行使用メモリ 5,248 KB
最終ジャッジ日時 2024-11-29 03:04:20
合計ジャッジ時間 2,476 ms
ジャッジサーバーID
(参考情報)
judge1 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 28
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <vector>
#include <cstdio>
#include <sstream>
#include <map>
#include <string>
#include <algorithm>
#include <queue>
#include <cmath>
#include <functional>
#include <set>
#include <ctime>
#include <random>
#include <chrono>
#include <cassert>
#include <tuple>
#include <utility>
using namespace std;
namespace {
using Integer = long long; //__int128;
template<class T, class S> istream& operator >> (istream& is, pair<T,S>& p){return is >> p.first >> p.second;}
template<class T> istream& operator >> (istream& is, vector<T>& vec){for(T& val: vec) is >> val; return is;}
template<class T> istream& operator , (istream& is, T& val){ return is >> val;}
template<class T, class S> ostream& operator << (ostream& os, const pair<T,S>& p){return os << p.first << " " << p.second;}
template<class T> ostream& operator << (ostream& os, const vector<T>& vec){for(size_t i=0; i<vec.size(); i++) os << vec[i] << (i==vec.size()-1?"":"
      "); return os;}
template<class T> ostream& operator , (ostream& os, const T& val){ return os << " " << val;}
template<class H> void print(const H& head){ cout << head; }
template<class H, class ... T> void print(const H& head, const T& ... tail){ cout << head << " "; print(tail...); }
template<class ... T> void println(const T& ... values){ print(values...); cout << endl; }
template<class H> void eprint(const H& head){ cerr << head; }
template<class H, class ... T> void eprint(const H& head, const T& ... tail){ cerr << head << " "; eprint(tail...); }
template<class ... T> void eprintln(const T& ... values){ eprint(values...); cerr << endl; }
class range{ Integer start_, end_, step_; public: struct range_iterator{ Integer val, step_; range_iterator(Integer v, Integer step) : val(v),
      step_(step) {} Integer operator * (){return val;} void operator ++ (){val += step_;} bool operator != (range_iterator& x){return step_ > 0 ?
      val < x.val : val > x.val;} }; range(Integer len) : start_(0), end_(len), step_(1) {} range(Integer start, Integer end) : start_(start), end_
      (end), step_(1) {} range(Integer start, Integer end, Integer step) : start_(start), end_(end), step_(step) {} range_iterator begin(){ return
      range_iterator(start_, step_); } range_iterator end(){ return range_iterator( end_, step_); } };
inline string operator "" _s (const char* str, size_t size){ return move(string(str)); }
constexpr Integer my_pow(Integer x, Integer k, Integer z=1){return k==0 ? z : k==1 ? z*x : (k&1) ? my_pow(x*x,k>>1,z*x) : my_pow(x*x,k>>1,z);}
constexpr Integer my_pow_mod(Integer x, Integer k, Integer M, Integer z=1){return k==0 ? z%M : k==1 ? z*x%M : (k&1) ? my_pow_mod(x*x%M,k>>1,M,z*x%M
      ) : my_pow_mod(x*x%M,k>>1,M,z);}
constexpr unsigned long long operator "" _ten (unsigned long long value){ return my_pow(10,value); }
inline int k_bit(Integer x, int k){return (x>>k)&1;} //0-indexed
mt19937 mt(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count());
template<class T> string join(const vector<T>& v, const string& sep){ stringstream ss; for(size_t i=0; i<v.size(); i++){ if(i>0) ss << sep; ss <<
      v[i]; } return ss.str(); }
inline string operator * (string s, int k){ string ret; while(k){ if(k&1) ret += s; s += s; k >>= 1; } return ret; }
}
constexpr long long mod = 9_ten + 7;
int rank_;
vector<int> xx;
// A[n*p] * X[p*m] = B[n*m]
template<class T = long long>
vector<T> gaussian_elimination_binary(vector<T> A, vector<T> B, int n, int p, int m){
vector<T> M(n);
for(int i=0; i<n; i++){
M[i] = A[i] << m;
M[i] |= B[i];
}
int rank = 0;
vector<int> left_most(n,-1);
for(int row = 0, col = p+m-1; row<n && col>=m; col--){
if( ((M[row] >> col) & T(1)) == T(0)){
int pivot = row;
for(int row__ = row; row__<n; row__++){
if( ((M[row__] >> col) & T(1)) != T(0) ){
pivot = row__;
break;
}
}
if(pivot == row) continue;
swap(M[row], M[pivot]);
}
rank++;
left_most[row] = col;
for(int row__=row+1; row__<n; row__++){
if( ((M[row__] >> col) & T(1)) != T(0) ) M[row__] ^= M[row];
}
row++;
}
rank_ = rank;
xx = left_most;
// T = long long
//T mask_B = ((T)1<<m) - 1;
//T mask_A = (((T)1<<(m+p)) - 1) ^ mask_B;
// T = bitset
T mask_B( string(m, '1') );
T mask_A( string(m+p, '1') );
mask_A ^= mask_B;
bool has_solution = true;
for(int row=n-1; row>=0; row--){
if( (M[row] & mask_B) != T(0) && (M[row] & mask_A) == T(0) ) has_solution = false;
if(left_most[row] == -1) continue;
int col = left_most[row];
for(int row__ = row-1; row__>=0; row__--){
if( ((M[row__] >> col) & T(1)) != T(0) ) M[row__] ^= M[row];
}
}
return has_solution? M : vector<T>(0);
}
int dx[] = {0, 0, 1,-1, 1, 1,-1,-1};
int dy[] = {1,-1, 0, 0, 1,-1, 1,-1};
#include <bitset>
using bits = bitset<65>;
int main(){
int n,m;
cin >> n,m;
vector<vector<int>> v(n, vector<int>(m));
cin >> v;
vector<bits> B(n*m);
for(int i=0; i<n; i++){
for(int j=0; j<m; j++){
if( v[i][j] ) B[i*m+j].set(0);
}
}
//eprintln("B\n", join(B,"\n"));
vector<bits> A(n*m);
for(int i=0; i<n; i++){
for(int j=0; j<m; j++){
A[i*m + j].set(i*m+j);
for(int k=0; k<8; k++){
int y = i+dy[k];
int x = j+dx[k];
if(y<0 || y>=n || x<0 || x>=m) continue;
A[i*m+j].set(y*m+x);
}
}
}
//eprintln("A\n", join(A,"\n"));
auto res = gaussian_elimination_binary(A,B, n*m, n*m, 1);
for(auto& w:xx) w--;
//eprintln(xx);
if(res.size()==0){
println("Impossible");
return 0;
}
//eprintln( "res\n", join(res, "\n"));
set<int> x; //free
for(int i=0; i<n*m; i++){
x.insert(i);
}
for(int i : xx){
x.erase(i);
}
int ans = 0;
for(int i=0; i<m*n; i++){
ans += res[i][0];
}
vector<vector<int>> C;
for(int i : range(n*m)){
if(xx[i] < 0) break;
vector<int> tmp;
for(int j=n*m; j>0; j--){
if( res[i][j] ) tmp.push_back(j-1);
}
C.push_back(tmp);
}
for(int i=0; i<(1<<x.size()); i++){
vector<int> tmp_x(n*m, -1);
int k=0;
for(auto w : x){
if((i>>k) & 1) tmp_x[w] = 1;
else tmp_x[w] = 0;
k++;
}
int cnt = __builtin_popcount(i);
for(int j=0; j<n*m && cnt < ans; j++){
if(xx[j] < 0) break;
int val = res[j][0];
for(int l=1; l<C[j].size(); l++){
val ^= tmp_x[ C[j][l] ];
}
if(val){
tmp_x[ C[j][0] ] = 1;
cnt++;
}else{
tmp_x[C[j][0]] = 0;
}
}
ans = min(ans, cnt);
}
println(ans);
return 0;
}
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